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How to use Mason rule to obtain transfer function of simple RLC electric circuit

Nasser M. Abbasi

November 9, 2015

This is small example showing how to use Mason rule to find the transfer function Vout(s)
Vin(s)-   of an RLC circuit.

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Solving the circuit loops (V =  Ri  ) applied to each loop gives (all in done in Laplace domain)

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The variables are I ,I
 1 2   . In Mason, each variable goes to a node. Hence so we need to have each variable by on its own on the the LHS. To do this, do this trick: Add I1   to each side of the first equation, and add I2   to each side of the second equation, this gives

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Now set up the signal graph, assign a node to each variable. The input and output go a node also. This is the result.

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Now we Find VoVuint  for the above using Mason rule.

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