Optimal. Leaf size=21 \[ \frac {\log (2)}{-1+e^{(x+\log (\log (4)))^2}-2 x+\log (x)} \]
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Rubi [F] time = 3.70, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {(-1+2 x) \log (2)+e^{x^2+2 x \log (\log (4))+\log ^2(\log (4))} \left (-2 x^2 \log (2)-2 x \log (2) \log (\log (4))\right )}{x+e^{2 x^2+4 x \log (\log (4))+2 \log ^2(\log (4))} x+4 x^2+4 x^3+\left (-2 x-4 x^2\right ) \log (x)+x \log ^2(x)+e^{x^2+2 x \log (\log (4))+\log ^2(\log (4))} \left (-2 x-4 x^2+2 x \log (x)\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {\log (2) \left (-1-2 e^{x^2+\log ^2(\log (4))} x^2 \log ^{2 x}(4)-2 x \left (-1+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4) \log (\log (4))\right )\right )}{x \left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx\\ &=\log (2) \int \frac {-1-2 e^{x^2+\log ^2(\log (4))} x^2 \log ^{2 x}(4)-2 x \left (-1+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4) \log (\log (4))\right )}{x \left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx\\ &=\log (2) \int \left (\frac {2 (x+\log (\log (4)))}{1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)}+\frac {-1-4 x^3+2 x^2 \log (x)+2 x (1-\log (\log (4)))+2 x \log (x) \log (\log (4))-2 x^2 (1+2 \log (\log (4)))}{x \left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2}\right ) \, dx\\ &=\log (2) \int \frac {-1-4 x^3+2 x^2 \log (x)+2 x (1-\log (\log (4)))+2 x \log (x) \log (\log (4))-2 x^2 (1+2 \log (\log (4)))}{x \left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx+(2 \log (2)) \int \frac {x+\log (\log (4))}{1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)} \, dx\\ &=\log (2) \int \left (-\frac {1}{x \left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2}-\frac {4 x^2}{\left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2}+\frac {2 x \log (x)}{\left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2}-\frac {2 (-1+\log (\log (4)))}{\left (-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)\right )^2}+\frac {2 \log (x) \log (\log (4))}{\left (-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)\right )^2}-\frac {2 x (1+2 \log (\log (4)))}{\left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2}\right ) \, dx+(2 \log (2)) \int \left (\frac {x}{1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)}-\frac {\log (\log (4))}{-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)}\right ) \, dx\\ &=-\left (\log (2) \int \frac {1}{x \left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx\right )+(2 \log (2)) \int \frac {x}{1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)} \, dx+(2 \log (2)) \int \frac {x \log (x)}{\left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx-(4 \log (2)) \int \frac {x^2}{\left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx+(2 \log (2) (1-\log (\log (4)))) \int \frac {1}{\left (-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)\right )^2} \, dx+(2 \log (2) \log (\log (4))) \int \frac {\log (x)}{\left (-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)\right )^2} \, dx-(2 \log (2) \log (\log (4))) \int \frac {1}{-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)} \, dx-(2 \log (2) (1+2 \log (\log (4)))) \int \frac {x}{\left (1+2 x-e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)-\log (x)\right )^2} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.13, size = 30, normalized size = 1.43 \begin {gather*} \frac {\log (2)}{-1-2 x+e^{x^2+\log ^2(\log (4))} \log ^{2 x}(4)+\log (x)} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.00, size = 37, normalized size = 1.76 \begin {gather*} -\frac {\log \relax (2)}{2 \, x - e^{\left (x^{2} + 2 \, x \log \left (2 \, \log \relax (2)\right ) + \log \left (2 \, \log \relax (2)\right )^{2}\right )} - \log \relax (x) + 1} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \mathit {undef} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.12, size = 28, normalized size = 1.33
method | result | size |
risch | \(-\frac {\ln \relax (2)}{2 x -{\mathrm e}^{\left (\ln \relax (2)+\ln \left (\ln \relax (2)\right )+x \right )^{2}}-\ln \relax (x )+1}\) | \(28\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.56, size = 45, normalized size = 2.14 \begin {gather*} \frac {\log \relax (2)}{2^{2 \, \log \left (\log \relax (2)\right )} e^{\left (x^{2} + 2 \, x \log \relax (2) + \log \relax (2)^{2} + 2 \, x \log \left (\log \relax (2)\right ) + \log \left (\log \relax (2)\right )^{2}\right )} - 2 \, x + \log \relax (x) - 1} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.06, size = 65, normalized size = 3.10 \begin {gather*} -\frac {2\,\ln \relax (2)\,\left (x+\ln \left (\ln \relax (4)\right )\right )}{\left (2\,x+\ln \left ({\ln \relax (4)}^2\right )\right )\,\left (2\,x-\ln \relax (x)-2^{2\,x}\,2^{2\,\ln \left (\ln \relax (2)\right )}\,{\mathrm {e}}^{x^2+{\ln \left (\ln \relax (2)\right )}^2+{\ln \relax (2)}^2}\,{\ln \relax (2)}^{2\,x}+1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.38, size = 34, normalized size = 1.62 \begin {gather*} \frac {\log {\relax (2 )}}{- 2 x + e^{x^{2} + 2 x \log {\left (2 \log {\relax (2 )} \right )} + \log {\left (2 \log {\relax (2 )} \right )}^{2}} + \log {\relax (x )} - 1} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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