Integrand size = 9, antiderivative size = 8 \[ \int \frac {x}{1+x^4} \, dx=\frac {\arctan \left (x^2\right )}{2} \]
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Time = 0.00 (sec) , antiderivative size = 8, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {281, 209} \[ \int \frac {x}{1+x^4} \, dx=\frac {\arctan \left (x^2\right )}{2} \]
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Rule 209
Rule 281
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,x^2\right ) \\ & = \frac {\arctan \left (x^2\right )}{2} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 8, normalized size of antiderivative = 1.00 \[ \int \frac {x}{1+x^4} \, dx=\frac {\arctan \left (x^2\right )}{2} \]
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Time = 0.08 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.88
method | result | size |
default | \(\frac {\arctan \left (x^{2}\right )}{2}\) | \(7\) |
meijerg | \(\frac {\arctan \left (x^{2}\right )}{2}\) | \(7\) |
risch | \(\frac {\arctan \left (x^{2}\right )}{2}\) | \(7\) |
parallelrisch | \(\frac {i \ln \left (x^{2}+i\right )}{4}-\frac {i \ln \left (x^{2}-i\right )}{4}\) | \(22\) |
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none
Time = 0.23 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.75 \[ \int \frac {x}{1+x^4} \, dx=\frac {1}{2} \, \arctan \left (x^{2}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.62 \[ \int \frac {x}{1+x^4} \, dx=\frac {\operatorname {atan}{\left (x^{2} \right )}}{2} \]
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none
Time = 0.28 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.75 \[ \int \frac {x}{1+x^4} \, dx=\frac {1}{2} \, \arctan \left (x^{2}\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.75 \[ \int \frac {x}{1+x^4} \, dx=\frac {1}{2} \, \arctan \left (x^{2}\right ) \]
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Time = 14.77 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.75 \[ \int \frac {x}{1+x^4} \, dx=\frac {\mathrm {atan}\left (x^2\right )}{2} \]
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