Integrand size = 9, antiderivative size = 115 \[ \int \sin ^2(\coth (a+b x)) \, dx=\frac {\cos (2) \operatorname {CosIntegral}(2-2 \coth (a+b x))}{4 b}-\frac {\cos (2) \operatorname {CosIntegral}(2+2 \coth (a+b x))}{4 b}-\frac {\log (1-\coth (a+b x))}{4 b}+\frac {\log (1+\coth (a+b x))}{4 b}+\frac {\sin (2) \text {Si}(2-2 \coth (a+b x))}{4 b}-\frac {\sin (2) \text {Si}(2+2 \coth (a+b x))}{4 b} \]
1/4*Ci(2-2*coth(b*x+a))*cos(2)/b-1/4*Ci(2+2*coth(b*x+a))*cos(2)/b-1/4*ln(1 -coth(b*x+a))/b+1/4*ln(1+coth(b*x+a))/b-1/4*Si(-2+2*coth(b*x+a))*sin(2)/b- 1/4*Si(2+2*coth(b*x+a))*sin(2)/b
Time = 0.50 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.77 \[ \int \sin ^2(\coth (a+b x)) \, dx=\frac {\cos (2) \operatorname {CosIntegral}(2-2 \coth (a+b x))-\cos (2) \operatorname {CosIntegral}(2 (1+\coth (a+b x)))-\log (1-\coth (a+b x))+\log (1+\coth (a+b x))+\sin (2) \text {Si}(2-2 \coth (a+b x))-\sin (2) \text {Si}(2 (1+\coth (a+b x)))}{4 b} \]
(Cos[2]*CosIntegral[2 - 2*Coth[a + b*x]] - Cos[2]*CosIntegral[2*(1 + Coth[ a + b*x])] - Log[1 - Coth[a + b*x]] + Log[1 + Coth[a + b*x]] + Sin[2]*SinI ntegral[2 - 2*Coth[a + b*x]] - Sin[2]*SinIntegral[2*(1 + Coth[a + b*x])])/ (4*b)
Time = 0.46 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.88, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {4852, 7276, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin ^2(\coth (a+b x)) \, dx\) |
\(\Big \downarrow \) 4852 |
\(\displaystyle \frac {\int \frac {\sin ^2(\coth (a+b x))}{1-\coth ^2(a+b x)}d\coth (a+b x)}{b}\) |
\(\Big \downarrow \) 7276 |
\(\displaystyle \frac {\int \left (\frac {\sin ^2(\coth (a+b x))}{2 (\coth (a+b x)+1)}-\frac {\sin ^2(\coth (a+b x))}{2 (\coth (a+b x)-1)}\right )d\coth (a+b x)}{b}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {\frac {1}{4} \cos (2) \operatorname {CosIntegral}(2-2 \coth (a+b x))-\frac {1}{4} \cos (2) \operatorname {CosIntegral}(2 \coth (a+b x)+2)+\frac {1}{4} \sin (2) \text {Si}(2-2 \coth (a+b x))-\frac {1}{4} \sin (2) \text {Si}(2 \coth (a+b x)+2)-\frac {1}{4} \log (1-\coth (a+b x))+\frac {1}{4} \log (\coth (a+b x)+1)}{b}\) |
((Cos[2]*CosIntegral[2 - 2*Coth[a + b*x]])/4 - (Cos[2]*CosIntegral[2 + 2*C oth[a + b*x]])/4 - Log[1 - Coth[a + b*x]]/4 + Log[1 + Coth[a + b*x]]/4 + ( Sin[2]*SinIntegral[2 - 2*Coth[a + b*x]])/4 - (Sin[2]*SinIntegral[2 + 2*Cot h[a + b*x]])/4)/b
3.3.18.3.1 Defintions of rubi rules used
Int[u_, x_Symbol] :> With[{v = FunctionOfTrig[u, x]}, Simp[With[{d = FreeFa ctors[Cot[v], x]}, -d/Coefficient[v, x, 1] Subst[Int[SubstFor[1/(1 + d^2* x^2), Cot[v]/d, u, x], x], x, Cot[v]/d]], x] /; !FalseQ[v] && FunctionOfQ[ NonfreeFactors[Cot[v], x], u, x, True] && TryPureTanSubst[ActivateTrig[u], x]]
Int[(u_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{v = RationalFunctionE xpand[u/(a + b*x^n), x]}, Int[v, x] /; SumQ[v]] /; FreeQ[{a, b}, x] && IGtQ [n, 0]
Time = 1.26 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.77
method | result | size |
derivativedivides | \(\frac {-\frac {\ln \left (\coth \left (b x +a \right )-1\right )}{4}+\frac {\ln \left (\coth \left (b x +a \right )+1\right )}{4}-\frac {\operatorname {Si}\left (-2+2 \coth \left (b x +a \right )\right ) \sin \left (2\right )}{4}+\frac {\operatorname {Ci}\left (-2+2 \coth \left (b x +a \right )\right ) \cos \left (2\right )}{4}-\frac {\operatorname {Si}\left (2+2 \coth \left (b x +a \right )\right ) \sin \left (2\right )}{4}-\frac {\operatorname {Ci}\left (2+2 \coth \left (b x +a \right )\right ) \cos \left (2\right )}{4}}{b}\) | \(88\) |
default | \(\frac {-\frac {\ln \left (\coth \left (b x +a \right )-1\right )}{4}+\frac {\ln \left (\coth \left (b x +a \right )+1\right )}{4}-\frac {\operatorname {Si}\left (-2+2 \coth \left (b x +a \right )\right ) \sin \left (2\right )}{4}+\frac {\operatorname {Ci}\left (-2+2 \coth \left (b x +a \right )\right ) \cos \left (2\right )}{4}-\frac {\operatorname {Si}\left (2+2 \coth \left (b x +a \right )\right ) \sin \left (2\right )}{4}-\frac {\operatorname {Ci}\left (2+2 \coth \left (b x +a \right )\right ) \cos \left (2\right )}{4}}{b}\) | \(88\) |
risch | \(\frac {{\mathrm e}^{2 i} \operatorname {Ei}_{1}\left (\frac {4 i {\mathrm e}^{-a}}{{\mathrm e}^{2 b x +a}-{\mathrm e}^{-a}}+4 i\right )}{8 b}-\frac {i \operatorname {csgn}\left (\frac {{\mathrm e}^{-a}}{-{\mathrm e}^{2 b x +a}+{\mathrm e}^{-a}}\right ) \pi \,{\mathrm e}^{-2 i}}{8 b}-\frac {i \operatorname {Si}\left (\frac {4 \,{\mathrm e}^{-a}}{{\mathrm e}^{2 b x +a}-{\mathrm e}^{-a}}\right ) {\mathrm e}^{-2 i}}{4 b}-\frac {{\mathrm e}^{-2 i} \operatorname {Ei}_{1}\left (-\frac {4 i {\mathrm e}^{-a}}{{\mathrm e}^{2 b x +a}-{\mathrm e}^{-a}}\right )}{8 b}+\frac {{\mathrm e}^{-2 i} \operatorname {Ei}_{1}\left (-\frac {4 i {\mathrm e}^{-a}}{{\mathrm e}^{2 b x +a}-{\mathrm e}^{-a}}-4 i\right )}{8 b}-\frac {{\mathrm e}^{2 i} \operatorname {Ei}_{1}\left (-\frac {4 i {\mathrm e}^{-a}}{{\mathrm e}^{2 b x +a}-{\mathrm e}^{-a}}\right )}{8 b}+\frac {\ln \left ({\mathrm e}^{b x}\right )}{2 b}\) | \(214\) |
1/b*(-1/4*ln(coth(b*x+a)-1)+1/4*ln(coth(b*x+a)+1)-1/4*Si(-2+2*coth(b*x+a)) *sin(2)+1/4*Ci(-2+2*coth(b*x+a))*cos(2)-1/4*Si(2+2*coth(b*x+a))*sin(2)-1/4 *Ci(2+2*coth(b*x+a))*cos(2))
Result contains complex when optimal does not.
Time = 0.27 (sec) , antiderivative size = 230, normalized size of antiderivative = 2.00 \[ \int \sin ^2(\coth (a+b x)) \, dx=\frac {4 \, b x \cos \left (2\right ) + 4 i \, b x \sin \left (2\right ) - {\left (\cos \left (2\right )^{2} + 2 i \, \cos \left (2\right ) \sin \left (2\right ) - \sin \left (2\right )^{2} + 1\right )} \operatorname {Ci}\left (\frac {2 \, {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}}{\sinh \left (b x + a\right )}\right ) + {\left (\cos \left (2\right )^{2} + 2 i \, \cos \left (2\right ) \sin \left (2\right ) - \sin \left (2\right )^{2} + 1\right )} \operatorname {Ci}\left (\frac {4}{\cosh \left (b x + a\right )^{2} + 2 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + \sinh \left (b x + a\right )^{2} - 1}\right ) + {\left (i \, \cos \left (2\right )^{2} - 2 \, \cos \left (2\right ) \sin \left (2\right ) - i \, \sin \left (2\right )^{2} - i\right )} \operatorname {Si}\left (\frac {2 \, {\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )}}{\sinh \left (b x + a\right )}\right ) + {\left (i \, \cos \left (2\right )^{2} - 2 \, \cos \left (2\right ) \sin \left (2\right ) - i \, \sin \left (2\right )^{2} - i\right )} \operatorname {Si}\left (\frac {4}{\cosh \left (b x + a\right )^{2} + 2 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + \sinh \left (b x + a\right )^{2} - 1}\right )}{8 \, {\left (b \cos \left (2\right ) + i \, b \sin \left (2\right )\right )}} \]
1/8*(4*b*x*cos(2) + 4*I*b*x*sin(2) - (cos(2)^2 + 2*I*cos(2)*sin(2) - sin(2 )^2 + 1)*cos_integral(2*(cosh(b*x + a) + sinh(b*x + a))/sinh(b*x + a)) + ( cos(2)^2 + 2*I*cos(2)*sin(2) - sin(2)^2 + 1)*cos_integral(4/(cosh(b*x + a) ^2 + 2*cosh(b*x + a)*sinh(b*x + a) + sinh(b*x + a)^2 - 1)) + (I*cos(2)^2 - 2*cos(2)*sin(2) - I*sin(2)^2 - I)*sin_integral(2*(cosh(b*x + a) + sinh(b* x + a))/sinh(b*x + a)) + (I*cos(2)^2 - 2*cos(2)*sin(2) - I*sin(2)^2 - I)*s in_integral(4/(cosh(b*x + a)^2 + 2*cosh(b*x + a)*sinh(b*x + a) + sinh(b*x + a)^2 - 1)))/(b*cos(2) + I*b*sin(2))
\[ \int \sin ^2(\coth (a+b x)) \, dx=\int \sin ^{2}{\left (\coth {\left (a + b x \right )} \right )}\, dx \]
\[ \int \sin ^2(\coth (a+b x)) \, dx=\int { \sin \left (\coth \left (b x + a\right )\right )^{2} \,d x } \]
\[ \int \sin ^2(\coth (a+b x)) \, dx=\int { \sin \left (\coth \left (b x + a\right )\right )^{2} \,d x } \]
Timed out. \[ \int \sin ^2(\coth (a+b x)) \, dx=\int {\sin \left (\mathrm {coth}\left (a+b\,x\right )\right )}^2 \,d x \]