Integrand size = 22, antiderivative size = 145 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {x}{c^4}-\frac {1}{32 a c^4 (1-a x)^4}+\frac {13}{48 a c^4 (1-a x)^3}-\frac {35}{32 a c^4 (1-a x)^2}+\frac {99}{32 a c^4 (1-a x)}+\frac {1}{64 a c^4 (1+a x)^2}-\frac {11}{64 a c^4 (1+a x)}+\frac {303 \log (1-a x)}{128 a c^4}-\frac {47 \log (1+a x)}{128 a c^4} \]
x/c^4-1/32/a/c^4/(-a*x+1)^4+13/48/a/c^4/(-a*x+1)^3-35/32/a/c^4/(-a*x+1)^2+ 99/32/a/c^4/(-a*x+1)+1/64/a/c^4/(a*x+1)^2-11/64/a/c^4/(a*x+1)+303/128*ln(- a*x+1)/a/c^4-47/128*ln(a*x+1)/a/c^4
Time = 0.12 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.68 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {\frac {2 \left (400-275 a x-1258 a^2 x^2+866 a^3 x^3+1254 a^4 x^4-819 a^5 x^5-384 a^6 x^6+192 a^7 x^7\right )}{(-1+a x)^4 (1+a x)^2}+909 \log (1-a x)-141 \log (1+a x)}{384 a c^4} \]
((2*(400 - 275*a*x - 1258*a^2*x^2 + 866*a^3*x^3 + 1254*a^4*x^4 - 819*a^5*x ^5 - 384*a^6*x^6 + 192*a^7*x^7))/((-1 + a*x)^4*(1 + a*x)^2) + 909*Log[1 - a*x] - 141*Log[1 + a*x])/(384*a*c^4)
Time = 0.53 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.90, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {6717, 27, 6707, 6700, 99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx\) |
\(\Big \downarrow \) 6717 |
\(\displaystyle -\int \frac {a^8 e^{2 \text {arctanh}(a x)}}{c^4 \left (a^2-\frac {1}{x^2}\right )^4}dx\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {a^8 \int \frac {e^{2 \text {arctanh}(a x)}}{\left (a^2-\frac {1}{x^2}\right )^4}dx}{c^4}\) |
\(\Big \downarrow \) 6707 |
\(\displaystyle -\frac {a^8 \int \frac {e^{2 \text {arctanh}(a x)} x^8}{\left (1-a^2 x^2\right )^4}dx}{c^4}\) |
\(\Big \downarrow \) 6700 |
\(\displaystyle -\frac {a^8 \int \frac {x^8}{(1-a x)^5 (a x+1)^3}dx}{c^4}\) |
\(\Big \downarrow \) 99 |
\(\displaystyle -\frac {a^8 \int \left (\frac {47}{128 a^8 (a x+1)}-\frac {11}{64 a^8 (a x+1)^2}+\frac {1}{32 a^8 (a x+1)^3}-\frac {1}{a^8}-\frac {303}{128 a^8 (a x-1)}-\frac {99}{32 a^8 (a x-1)^2}-\frac {35}{16 a^8 (a x-1)^3}-\frac {13}{16 a^8 (a x-1)^4}-\frac {1}{8 a^8 (a x-1)^5}\right )dx}{c^4}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {a^8 \left (-\frac {99}{32 a^9 (1-a x)}+\frac {11}{64 a^9 (a x+1)}+\frac {35}{32 a^9 (1-a x)^2}-\frac {1}{64 a^9 (a x+1)^2}-\frac {13}{48 a^9 (1-a x)^3}+\frac {1}{32 a^9 (1-a x)^4}-\frac {303 \log (1-a x)}{128 a^9}+\frac {47 \log (a x+1)}{128 a^9}-\frac {x}{a^8}\right )}{c^4}\) |
-((a^8*(-(x/a^8) + 1/(32*a^9*(1 - a*x)^4) - 13/(48*a^9*(1 - a*x)^3) + 35/( 32*a^9*(1 - a*x)^2) - 99/(32*a^9*(1 - a*x)) - 1/(64*a^9*(1 + a*x)^2) + 11/ (64*a^9*(1 + a*x)) - (303*Log[1 - a*x])/(128*a^9) + (47*Log[1 + a*x])/(128 *a^9)))/c^4)
3.8.88.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x _Symbol] :> Simp[c^p Int[x^m*(1 - a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0])
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_.), x_Symb ol] :> Simp[d^p Int[(u/x^(2*p))*(1 - a^2*x^2)^p*E^(n*ArcTanh[a*x]), x], x ] /; FreeQ[{a, c, d, n}, x] && EqQ[c + a^2*d, 0] && IntegerQ[p]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_))*(u_.), x_Symbol] :> Simp[(-1)^(n/2) Int[ u*E^(n*ArcTanh[a*x]), x], x] /; FreeQ[a, x] && IntegerQ[n/2]
Time = 0.54 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.74
method | result | size |
default | \(\frac {a^{8} \left (\frac {1}{64 a^{9} \left (a x +1\right )^{2}}-\frac {11}{64 a^{9} \left (a x +1\right )}-\frac {47 \ln \left (a x +1\right )}{128 a^{9}}+\frac {x}{a^{8}}-\frac {1}{32 a^{9} \left (a x -1\right )^{4}}-\frac {13}{48 a^{9} \left (a x -1\right )^{3}}-\frac {35}{32 a^{9} \left (a x -1\right )^{2}}-\frac {99}{32 a^{9} \left (a x -1\right )}+\frac {303 \ln \left (a x -1\right )}{128 a^{9}}\right )}{c^{4}}\) | \(108\) |
risch | \(\frac {x}{c^{4}}+\frac {-\frac {209 a^{4} c^{4} x^{5}}{64}+\frac {81 a^{3} c^{4} x^{4}}{32}+\frac {529 a^{2} c^{4} x^{3}}{96}-\frac {437 a \,c^{4} x^{2}}{96}-\frac {467 c^{4} x}{192}+\frac {25 c^{4}}{12 a}}{c^{8} \left (a x -1\right )^{2} \left (a^{2} x^{2}-1\right )^{2}}+\frac {303 \ln \left (-a x +1\right )}{128 a \,c^{4}}-\frac {47 \ln \left (a x +1\right )}{128 a \,c^{4}}\) | \(115\) |
norman | \(\frac {\frac {a^{7} x^{8}}{c}+\frac {175 x}{64 c}-\frac {111 a \,x^{2}}{64 c}-\frac {199 a^{2} x^{3}}{24 c}+\frac {115 a^{3} x^{4}}{24 c}+\frac {545 a^{4} x^{5}}{64 c}-\frac {803 a^{5} x^{6}}{192 c}-\frac {37 a^{6} x^{7}}{12 c}}{c^{3} \left (a x -1\right )^{4} \left (a x +1\right )^{3}}+\frac {303 \ln \left (a x -1\right )}{128 a \,c^{4}}-\frac {47 \ln \left (a x +1\right )}{128 a \,c^{4}}\) | \(129\) |
parallelrisch | \(\frac {282 a \ln \left (a x +1\right ) x +141 a^{2} \ln \left (a x +1\right ) x^{2}-38 a^{5} x^{5}-1468 a^{3} x^{3}+282 \ln \left (a x +1\right ) x^{5} a^{5}-141 \ln \left (a x +1\right ) x^{6} a^{6}+141 \ln \left (a x +1\right ) x^{4} a^{4}+909 \ln \left (a x -1\right ) x^{6} a^{6}-1818 \ln \left (a x -1\right ) x^{5} a^{5}-909 \ln \left (a x -1\right ) x^{4} a^{4}-564 a^{3} \ln \left (a x +1\right ) x^{3}-1568 a^{6} x^{6}+1050 a x +3636 a^{3} \ln \left (a x -1\right ) x^{3}-909 a^{2} \ln \left (a x -1\right ) x^{2}-1818 a \ln \left (a x -1\right ) x +3308 a^{4} x^{4}+909 \ln \left (a x -1\right )-141 \ln \left (a x +1\right )+384 a^{7} x^{7}-1716 a^{2} x^{2}}{384 c^{4} \left (a x -1\right )^{2} \left (a^{2} x^{2}-1\right )^{2} a}\) | \(256\) |
a^8/c^4*(1/64/a^9/(a*x+1)^2-11/64/a^9/(a*x+1)-47/128/a^9*ln(a*x+1)+1/a^8*x -1/32/a^9/(a*x-1)^4-13/48/a^9/(a*x-1)^3-35/32/a^9/(a*x-1)^2-99/32/a^9/(a*x -1)+303/128/a^9*ln(a*x-1))
Time = 0.26 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.61 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {384 \, a^{7} x^{7} - 768 \, a^{6} x^{6} - 1638 \, a^{5} x^{5} + 2508 \, a^{4} x^{4} + 1732 \, a^{3} x^{3} - 2516 \, a^{2} x^{2} - 550 \, a x - 141 \, {\left (a^{6} x^{6} - 2 \, a^{5} x^{5} - a^{4} x^{4} + 4 \, a^{3} x^{3} - a^{2} x^{2} - 2 \, a x + 1\right )} \log \left (a x + 1\right ) + 909 \, {\left (a^{6} x^{6} - 2 \, a^{5} x^{5} - a^{4} x^{4} + 4 \, a^{3} x^{3} - a^{2} x^{2} - 2 \, a x + 1\right )} \log \left (a x - 1\right ) + 800}{384 \, {\left (a^{7} c^{4} x^{6} - 2 \, a^{6} c^{4} x^{5} - a^{5} c^{4} x^{4} + 4 \, a^{4} c^{4} x^{3} - a^{3} c^{4} x^{2} - 2 \, a^{2} c^{4} x + a c^{4}\right )}} \]
1/384*(384*a^7*x^7 - 768*a^6*x^6 - 1638*a^5*x^5 + 2508*a^4*x^4 + 1732*a^3* x^3 - 2516*a^2*x^2 - 550*a*x - 141*(a^6*x^6 - 2*a^5*x^5 - a^4*x^4 + 4*a^3* x^3 - a^2*x^2 - 2*a*x + 1)*log(a*x + 1) + 909*(a^6*x^6 - 2*a^5*x^5 - a^4*x ^4 + 4*a^3*x^3 - a^2*x^2 - 2*a*x + 1)*log(a*x - 1) + 800)/(a^7*c^4*x^6 - 2 *a^6*c^4*x^5 - a^5*c^4*x^4 + 4*a^4*c^4*x^3 - a^3*c^4*x^2 - 2*a^2*c^4*x + a *c^4)
Time = 0.47 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.08 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=a^{8} \left (\frac {- 627 a^{5} x^{5} + 486 a^{4} x^{4} + 1058 a^{3} x^{3} - 874 a^{2} x^{2} - 467 a x + 400}{192 a^{15} c^{4} x^{6} - 384 a^{14} c^{4} x^{5} - 192 a^{13} c^{4} x^{4} + 768 a^{12} c^{4} x^{3} - 192 a^{11} c^{4} x^{2} - 384 a^{10} c^{4} x + 192 a^{9} c^{4}} + \frac {x}{a^{8} c^{4}} + \frac {\frac {303 \log {\left (x - \frac {1}{a} \right )}}{128} - \frac {47 \log {\left (x + \frac {1}{a} \right )}}{128}}{a^{9} c^{4}}\right ) \]
a**8*((-627*a**5*x**5 + 486*a**4*x**4 + 1058*a**3*x**3 - 874*a**2*x**2 - 4 67*a*x + 400)/(192*a**15*c**4*x**6 - 384*a**14*c**4*x**5 - 192*a**13*c**4* x**4 + 768*a**12*c**4*x**3 - 192*a**11*c**4*x**2 - 384*a**10*c**4*x + 192* a**9*c**4) + x/(a**8*c**4) + (303*log(x - 1/a)/128 - 47*log(x + 1/a)/128)/ (a**9*c**4))
Time = 0.20 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.00 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=-\frac {627 \, a^{5} x^{5} - 486 \, a^{4} x^{4} - 1058 \, a^{3} x^{3} + 874 \, a^{2} x^{2} + 467 \, a x - 400}{192 \, {\left (a^{7} c^{4} x^{6} - 2 \, a^{6} c^{4} x^{5} - a^{5} c^{4} x^{4} + 4 \, a^{4} c^{4} x^{3} - a^{3} c^{4} x^{2} - 2 \, a^{2} c^{4} x + a c^{4}\right )}} + \frac {x}{c^{4}} - \frac {47 \, \log \left (a x + 1\right )}{128 \, a c^{4}} + \frac {303 \, \log \left (a x - 1\right )}{128 \, a c^{4}} \]
-1/192*(627*a^5*x^5 - 486*a^4*x^4 - 1058*a^3*x^3 + 874*a^2*x^2 + 467*a*x - 400)/(a^7*c^4*x^6 - 2*a^6*c^4*x^5 - a^5*c^4*x^4 + 4*a^4*c^4*x^3 - a^3*c^4 *x^2 - 2*a^2*c^4*x + a*c^4) + x/c^4 - 47/128*log(a*x + 1)/(a*c^4) + 303/12 8*log(a*x - 1)/(a*c^4)
Time = 0.28 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.66 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {x}{c^{4}} - \frac {47 \, \log \left ({\left | a x + 1 \right |}\right )}{128 \, a c^{4}} + \frac {303 \, \log \left ({\left | a x - 1 \right |}\right )}{128 \, a c^{4}} - \frac {627 \, a^{5} x^{5} - 486 \, a^{4} x^{4} - 1058 \, a^{3} x^{3} + 874 \, a^{2} x^{2} + 467 \, a x - 400}{192 \, {\left (a x + 1\right )}^{2} {\left (a x - 1\right )}^{4} a c^{4}} \]
x/c^4 - 47/128*log(abs(a*x + 1))/(a*c^4) + 303/128*log(abs(a*x - 1))/(a*c^ 4) - 1/192*(627*a^5*x^5 - 486*a^4*x^4 - 1058*a^3*x^3 + 874*a^2*x^2 + 467*a *x - 400)/((a*x + 1)^2*(a*x - 1)^4*a*c^4)
Time = 4.21 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.98 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {x}{c^4}+\frac {\frac {467\,x}{192}+\frac {437\,a\,x^2}{96}-\frac {25}{12\,a}-\frac {529\,a^2\,x^3}{96}-\frac {81\,a^3\,x^4}{32}+\frac {209\,a^4\,x^5}{64}}{-a^6\,c^4\,x^6+2\,a^5\,c^4\,x^5+a^4\,c^4\,x^4-4\,a^3\,c^4\,x^3+a^2\,c^4\,x^2+2\,a\,c^4\,x-c^4}+\frac {303\,\ln \left (a\,x-1\right )}{128\,a\,c^4}-\frac {47\,\ln \left (a\,x+1\right )}{128\,a\,c^4} \]