y''(x)=-\frac{y(x) \left(4 a (a+1) x^4-2 a \left(x^2-1\right) x^2+\left(x^2-1\right)^2 \left(x^2-v^2\right)\right)}{x^2 \left(x^2-1\right)^2}-\frac{\left((1-4 a) x^2-1\right) y'(x)}{x \left(x^2-1\right)}