2.29 Sort each row (on its own) in a matrix

Given

     4     2     5 
     2     7     9 
    10     1     2
 

Sort each row on its own, so that the result is

     2     4     5 
     2     7     9 
     1     2     10
 

Mathematica mat={{4, 2,5}, {2, 7,9}, {10,1,2}}; Map[Sort[#]&,mat]

{{2, 4, 5}, {2, 7, 9}, {1, 2, 10}}

 

Matlab A=[4 2 5; 2 7 9; 10 1 2]; sort(A,2)

2 4 5 2 7 9 1 2 10

 

Maple restart; A:=Matrix([[4,2,5],[2,7,9],[10,1,2]]); map(x->convert(sort(x),list),[LinearAlgebra:-Row(A,[1..-1])]); Matrix(%); #or, may simpler is restart; A:=Matrix([[4,2,5],[2,7,9],[10,1,2]]); for n from 1 to LinearAlgebra:-RowDimension(A) do A[n,..]:=sort(A[n,..]); od: A

Matrix(3, 3, [[2, 4, 5], [2, 7, 9], [1, 2, 10]])

 

I had to convert each row to a list above for this to work. But for the case of columns (see last item earlier), this was not needed. Strange that one can’t not construct a Matrix from list of Row vectors as with a list of Column vectors.

Maple 2021.