5.13 Complex Fourier series and Fourier transform

Given f(x) which is periodic on 0<x<L, so period is L, then Fourier series isf(x)1Ln=cnein2πLx Where cn=n|f=1L0Lf(x)ein2πLxdx

The basis are |n=1Lein2πLx and L is the period.

Fourier transform for non periodic f(x) is (sum above becomes integral)f(x)=12πckeikxdkck=f(x)eikxdx

This gives rise toδ(xx)=12πeik(xx)dk