Optimal. Leaf size=94 \[ -\frac{a+b \sin ^{-1}(c+d x)}{4 d e^5 (c+d x)^4}-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^5 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2}}{12 d e^5 (c+d x)^3} \]
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Rubi [A] time = 0.0681326, antiderivative size = 94, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {4805, 12, 4627, 271, 264} \[ -\frac{a+b \sin ^{-1}(c+d x)}{4 d e^5 (c+d x)^4}-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^5 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2}}{12 d e^5 (c+d x)^3} \]
Antiderivative was successfully verified.
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Rule 4805
Rule 12
Rule 4627
Rule 271
Rule 264
Rubi steps
\begin{align*} \int \frac{a+b \sin ^{-1}(c+d x)}{(c e+d e x)^5} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{a+b \sin ^{-1}(x)}{e^5 x^5} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{a+b \sin ^{-1}(x)}{x^5} \, dx,x,c+d x\right )}{d e^5}\\ &=-\frac{a+b \sin ^{-1}(c+d x)}{4 d e^5 (c+d x)^4}+\frac{b \operatorname{Subst}\left (\int \frac{1}{x^4 \sqrt{1-x^2}} \, dx,x,c+d x\right )}{4 d e^5}\\ &=-\frac{b \sqrt{1-(c+d x)^2}}{12 d e^5 (c+d x)^3}-\frac{a+b \sin ^{-1}(c+d x)}{4 d e^5 (c+d x)^4}+\frac{b \operatorname{Subst}\left (\int \frac{1}{x^2 \sqrt{1-x^2}} \, dx,x,c+d x\right )}{6 d e^5}\\ &=-\frac{b \sqrt{1-(c+d x)^2}}{12 d e^5 (c+d x)^3}-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^5 (c+d x)}-\frac{a+b \sin ^{-1}(c+d x)}{4 d e^5 (c+d x)^4}\\ \end{align*}
Mathematica [A] time = 0.0610868, size = 63, normalized size = 0.67 \[ -\frac{3 \left (a+b \sin ^{-1}(c+d x)\right )+b (c+d x) \sqrt{1-(c+d x)^2} \left (2 (c+d x)^2+1\right )}{12 d e^5 (c+d x)^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.004, size = 84, normalized size = 0.9 \begin{align*}{\frac{1}{d} \left ( -{\frac{a}{4\,{e}^{5} \left ( dx+c \right ) ^{4}}}+{\frac{b}{{e}^{5}} \left ( -{\frac{\arcsin \left ( dx+c \right ) }{4\, \left ( dx+c \right ) ^{4}}}-{\frac{1}{12\, \left ( dx+c \right ) ^{3}}\sqrt{1- \left ( dx+c \right ) ^{2}}}-{\frac{1}{6\,dx+6\,c}\sqrt{1- \left ( dx+c \right ) ^{2}}} \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.61405, size = 355, normalized size = 3.78 \begin{align*} \frac{1}{12} \, b{\left (\frac{{\left (2 \, d^{4} x^{4} + 8 \, c d^{3} x^{3} + 2 \, c^{4} +{\left (12 \, c^{2} d^{2} - d^{2}\right )} x^{2} - c^{2} + 2 \,{\left (4 \, c^{3} d - c d\right )} x - 1\right )} d}{{\left (d^{5} e^{5} x^{3} + 3 \, c d^{4} e^{5} x^{2} + 3 \, c^{2} d^{3} e^{5} x + c^{3} d^{2} e^{5}\right )} \sqrt{d x + c + 1} \sqrt{-d x - c + 1}} - \frac{3 \, \arcsin \left (d x + c\right )}{d^{5} e^{5} x^{4} + 4 \, c d^{4} e^{5} x^{3} + 6 \, c^{2} d^{3} e^{5} x^{2} + 4 \, c^{3} d^{2} e^{5} x + c^{4} d e^{5}}\right )} - \frac{a}{4 \,{\left (d^{5} e^{5} x^{4} + 4 \, c d^{4} e^{5} x^{3} + 6 \, c^{2} d^{3} e^{5} x^{2} + 4 \, c^{3} d^{2} e^{5} x + c^{4} d e^{5}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.29779, size = 405, normalized size = 4.31 \begin{align*} \frac{3 \, a d^{4} x^{4} + 12 \, a c d^{3} x^{3} + 18 \, a c^{2} d^{2} x^{2} + 12 \, a c^{3} d x - 3 \, b c^{4} \arcsin \left (d x + c\right ) -{\left (2 \, b c^{4} d^{3} x^{3} + 6 \, b c^{5} d^{2} x^{2} + 2 \, b c^{7} + b c^{5} +{\left (6 \, b c^{6} + b c^{4}\right )} d x\right )} \sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1}}{12 \,{\left (c^{4} d^{5} e^{5} x^{4} + 4 \, c^{5} d^{4} e^{5} x^{3} + 6 \, c^{6} d^{3} e^{5} x^{2} + 4 \, c^{7} d^{2} e^{5} x + c^{8} d e^{5}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a}{c^{5} + 5 c^{4} d x + 10 c^{3} d^{2} x^{2} + 10 c^{2} d^{3} x^{3} + 5 c d^{4} x^{4} + d^{5} x^{5}}\, dx + \int \frac{b \operatorname{asin}{\left (c + d x \right )}}{c^{5} + 5 c^{4} d x + 10 c^{3} d^{2} x^{2} + 10 c^{2} d^{3} x^{3} + 5 c d^{4} x^{4} + d^{5} x^{5}}\, dx}{e^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.68219, size = 576, normalized size = 6.13 \begin{align*} -\frac{3 \, b \arcsin \left (d x + c\right ) e^{\left (-5\right )}}{32 \, d} - \frac{{\left (d x + c\right )}^{4} b \arcsin \left (d x + c\right ) e^{\left (-5\right )}}{64 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{4}} - \frac{{\left (d x + c\right )}^{2} b \arcsin \left (d x + c\right ) e^{\left (-5\right )}}{16 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{2}} - \frac{b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{2} \arcsin \left (d x + c\right ) e^{\left (-5\right )}}{16 \,{\left (d x + c\right )}^{2} d} - \frac{b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{4} \arcsin \left (d x + c\right ) e^{\left (-5\right )}}{64 \,{\left (d x + c\right )}^{4} d} - \frac{3 \, a e^{\left (-5\right )}}{32 \, d} - \frac{{\left (d x + c\right )}^{4} a e^{\left (-5\right )}}{64 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{4}} + \frac{{\left (d x + c\right )}^{3} b e^{\left (-5\right )}}{96 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{3}} - \frac{{\left (d x + c\right )}^{2} a e^{\left (-5\right )}}{16 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{2}} + \frac{3 \,{\left (d x + c\right )} b e^{\left (-5\right )}}{32 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}} - \frac{3 \, b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )} e^{\left (-5\right )}}{32 \,{\left (d x + c\right )} d} - \frac{a{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{2} e^{\left (-5\right )}}{16 \,{\left (d x + c\right )}^{2} d} - \frac{b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{3} e^{\left (-5\right )}}{96 \,{\left (d x + c\right )}^{3} d} - \frac{a{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{4} e^{\left (-5\right )}}{64 \,{\left (d x + c\right )}^{4} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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