Optimal. Leaf size=50 \[ \frac{\log \left (1-(a+b x)^2\right )}{2 b}+\frac{(a+b x) \sin ^{-1}(a+b x)}{b \sqrt{1-(a+b x)^2}} \]
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Rubi [A] time = 0.0597169, antiderivative size = 50, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {4807, 4651, 260} \[ \frac{\log \left (1-(a+b x)^2\right )}{2 b}+\frac{(a+b x) \sin ^{-1}(a+b x)}{b \sqrt{1-(a+b x)^2}} \]
Antiderivative was successfully verified.
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Rule 4807
Rule 4651
Rule 260
Rubi steps
\begin{align*} \int \frac{\sin ^{-1}(a+b x)}{\left (1-a^2-2 a b x-b^2 x^2\right )^{3/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\sin ^{-1}(x)}{\left (1-x^2\right )^{3/2}} \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \sin ^{-1}(a+b x)}{b \sqrt{1-(a+b x)^2}}-\frac{\operatorname{Subst}\left (\int \frac{x}{1-x^2} \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \sin ^{-1}(a+b x)}{b \sqrt{1-(a+b x)^2}}+\frac{\log \left (1-(a+b x)^2\right )}{2 b}\\ \end{align*}
Mathematica [A] time = 0.0963208, size = 66, normalized size = 1.32 \[ \frac{\log \left (-a^2-2 a b x-b^2 x^2+1\right )+\frac{2 (a+b x) \sin ^{-1}(a+b x)}{\sqrt{-a^2-2 a b x-b^2 x^2+1}}}{2 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.056, size = 155, normalized size = 3.1 \begin{align*} -{\frac{1}{2\,b \left ({b}^{2}{x}^{2}+2\,xab+{a}^{2}-1 \right ) } \left ( -\ln \left ( 1- \left ( bx+a \right ) ^{2} \right ){x}^{2}{b}^{2}+2\,\arcsin \left ( bx+a \right ) \sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}xb-2\,\ln \left ( 1- \left ( bx+a \right ) ^{2} \right ) xab+2\,\arcsin \left ( bx+a \right ) \sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}a-\ln \left ( 1- \left ( bx+a \right ) ^{2} \right ){a}^{2}+\ln \left ( 1- \left ( bx+a \right ) ^{2} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.37571, size = 232, normalized size = 4.64 \begin{align*} -\frac{2 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (b x + a\right )} \arcsin \left (b x + a\right ) -{\left (b^{2} x^{2} + 2 \, a b x + a^{2} - 1\right )} \log \left (b^{2} x^{2} + 2 \, a b x + a^{2} - 1\right )}{2 \,{\left (b^{3} x^{2} + 2 \, a b^{2} x +{\left (a^{2} - 1\right )} b\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{asin}{\left (a + b x \right )}}{\left (- \left (a + b x - 1\right ) \left (a + b x + 1\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.28173, size = 112, normalized size = 2.24 \begin{align*} -\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (x + \frac{a}{b}\right )} \arcsin \left (b x + a\right )}{b^{2} x^{2} + 2 \, a b x + a^{2} - 1} + \frac{\log \left ({\left | b x + a + 1 \right |}\right )}{2 \, b} + \frac{\log \left ({\left | b x + a - 1 \right |}\right )}{2 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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