Optimal. Leaf size=41 \[ \frac{e^{\sin ^{-1}(a x)} \sin \left (2 \sin ^{-1}(a x)\right )}{10 a^2}-\frac{e^{\sin ^{-1}(a x)} \cos \left (2 \sin ^{-1}(a x)\right )}{5 a^2} \]
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Rubi [A] time = 0.0338236, antiderivative size = 41, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4836, 12, 4469, 4432} \[ \frac{e^{\sin ^{-1}(a x)} \sin \left (2 \sin ^{-1}(a x)\right )}{10 a^2}-\frac{e^{\sin ^{-1}(a x)} \cos \left (2 \sin ^{-1}(a x)\right )}{5 a^2} \]
Antiderivative was successfully verified.
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Rule 4836
Rule 12
Rule 4469
Rule 4432
Rubi steps
\begin{align*} \int e^{\sin ^{-1}(a x)} x \, dx &=\frac{\operatorname{Subst}\left (\int \frac{e^x \cos (x) \sin (x)}{a} \, dx,x,\sin ^{-1}(a x)\right )}{a}\\ &=\frac{\operatorname{Subst}\left (\int e^x \cos (x) \sin (x) \, dx,x,\sin ^{-1}(a x)\right )}{a^2}\\ &=\frac{\operatorname{Subst}\left (\int \frac{1}{2} e^x \sin (2 x) \, dx,x,\sin ^{-1}(a x)\right )}{a^2}\\ &=\frac{\operatorname{Subst}\left (\int e^x \sin (2 x) \, dx,x,\sin ^{-1}(a x)\right )}{2 a^2}\\ &=-\frac{e^{\sin ^{-1}(a x)} \cos \left (2 \sin ^{-1}(a x)\right )}{5 a^2}+\frac{e^{\sin ^{-1}(a x)} \sin \left (2 \sin ^{-1}(a x)\right )}{10 a^2}\\ \end{align*}
Mathematica [A] time = 0.0382223, size = 30, normalized size = 0.73 \[ \frac{e^{\sin ^{-1}(a x)} \left (\sin \left (2 \sin ^{-1}(a x)\right )-2 \cos \left (2 \sin ^{-1}(a x)\right )\right )}{10 a^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.008, size = 0, normalized size = 0. \begin{align*} \int{{\rm e}^{\arcsin \left ( ax \right ) }}x\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x e^{\left (\arcsin \left (a x\right )\right )}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.11044, size = 89, normalized size = 2.17 \begin{align*} \frac{{\left (2 \, a^{2} x^{2} + \sqrt{-a^{2} x^{2} + 1} a x - 1\right )} e^{\left (\arcsin \left (a x\right )\right )}}{5 \, a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.606224, size = 53, normalized size = 1.29 \begin{align*} \begin{cases} \frac{2 x^{2} e^{\operatorname{asin}{\left (a x \right )}}}{5} + \frac{x \sqrt{- a^{2} x^{2} + 1} e^{\operatorname{asin}{\left (a x \right )}}}{5 a} - \frac{e^{\operatorname{asin}{\left (a x \right )}}}{5 a^{2}} & \text{for}\: a \neq 0 \\\frac{x^{2}}{2} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19821, size = 72, normalized size = 1.76 \begin{align*} \frac{\sqrt{-a^{2} x^{2} + 1} x e^{\left (\arcsin \left (a x\right )\right )}}{5 \, a} + \frac{2 \,{\left (a^{2} x^{2} - 1\right )} e^{\left (\arcsin \left (a x\right )\right )}}{5 \, a^{2}} + \frac{e^{\left (\arcsin \left (a x\right )\right )}}{5 \, a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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