Optimal. Leaf size=151 \[ -\frac{3 x^{m+1} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{m+1}{2},\frac{m+3}{2},a^2 x^2\right )}{m+1}+\frac{4 x^{m+1} \text{Hypergeometric2F1}\left (\frac{3}{2},\frac{m+1}{2},\frac{m+3}{2},a^2 x^2\right )}{m+1}-\frac{a x^{m+2} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{m+2}{2},\frac{m+4}{2},a^2 x^2\right )}{m+2}+\frac{4 a x^{m+2} \text{Hypergeometric2F1}\left (\frac{3}{2},\frac{m+2}{2},\frac{m+4}{2},a^2 x^2\right )}{m+2} \]
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Rubi [A] time = 0.881088, antiderivative size = 151, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.417, Rules used = {6124, 6742, 364, 850, 808} \[ -\frac{3 x^{m+1} \, _2F_1\left (\frac{1}{2},\frac{m+1}{2};\frac{m+3}{2};a^2 x^2\right )}{m+1}+\frac{4 x^{m+1} \, _2F_1\left (\frac{3}{2},\frac{m+1}{2};\frac{m+3}{2};a^2 x^2\right )}{m+1}-\frac{a x^{m+2} \, _2F_1\left (\frac{1}{2},\frac{m+2}{2};\frac{m+4}{2};a^2 x^2\right )}{m+2}+\frac{4 a x^{m+2} \, _2F_1\left (\frac{3}{2},\frac{m+2}{2};\frac{m+4}{2};a^2 x^2\right )}{m+2} \]
Antiderivative was successfully verified.
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Rule 6124
Rule 6742
Rule 364
Rule 850
Rule 808
Rubi steps
\begin{align*} \int e^{3 \tanh ^{-1}(a x)} x^m \, dx &=\int \frac{x^m (1+a x)^2}{(1-a x) \sqrt{1-a^2 x^2}} \, dx\\ &=\int \left (-\frac{3 x^m}{\sqrt{1-a^2 x^2}}-\frac{a x^{1+m}}{\sqrt{1-a^2 x^2}}+\frac{4 x^m}{(1-a x) \sqrt{1-a^2 x^2}}\right ) \, dx\\ &=-\left (3 \int \frac{x^m}{\sqrt{1-a^2 x^2}} \, dx\right )+4 \int \frac{x^m}{(1-a x) \sqrt{1-a^2 x^2}} \, dx-a \int \frac{x^{1+m}}{\sqrt{1-a^2 x^2}} \, dx\\ &=-\frac{3 x^{1+m} \, _2F_1\left (\frac{1}{2},\frac{1+m}{2};\frac{3+m}{2};a^2 x^2\right )}{1+m}-\frac{a x^{2+m} \, _2F_1\left (\frac{1}{2},\frac{2+m}{2};\frac{4+m}{2};a^2 x^2\right )}{2+m}+4 \int \frac{x^m (1+a x)}{\left (1-a^2 x^2\right )^{3/2}} \, dx\\ &=-\frac{3 x^{1+m} \, _2F_1\left (\frac{1}{2},\frac{1+m}{2};\frac{3+m}{2};a^2 x^2\right )}{1+m}-\frac{a x^{2+m} \, _2F_1\left (\frac{1}{2},\frac{2+m}{2};\frac{4+m}{2};a^2 x^2\right )}{2+m}+4 \int \frac{x^m}{\left (1-a^2 x^2\right )^{3/2}} \, dx+(4 a) \int \frac{x^{1+m}}{\left (1-a^2 x^2\right )^{3/2}} \, dx\\ &=-\frac{3 x^{1+m} \, _2F_1\left (\frac{1}{2},\frac{1+m}{2};\frac{3+m}{2};a^2 x^2\right )}{1+m}-\frac{a x^{2+m} \, _2F_1\left (\frac{1}{2},\frac{2+m}{2};\frac{4+m}{2};a^2 x^2\right )}{2+m}+\frac{4 x^{1+m} \, _2F_1\left (\frac{3}{2},\frac{1+m}{2};\frac{3+m}{2};a^2 x^2\right )}{1+m}+\frac{4 a x^{2+m} \, _2F_1\left (\frac{3}{2},\frac{2+m}{2};\frac{4+m}{2};a^2 x^2\right )}{2+m}\\ \end{align*}
Mathematica [C] time = 0.0787062, size = 92, normalized size = 0.61 \[ \frac{\sqrt{-a x-1} \sqrt{1-a x} x^{m+1} \left (F_1\left (m+1;-\frac{1}{2},\frac{1}{2};m+2;-a x,a x\right )-2 F_1\left (m+1;-\frac{1}{2},\frac{3}{2};m+2;-a x,a x\right )\right )}{(m+1) \sqrt{a x-1} \sqrt{a x+1}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.343, size = 139, normalized size = 0.9 \begin{align*}{\frac{{x}^{1+m}}{1+m}{\mbox{$_2$F$_1$}({\frac{3}{2}},{\frac{1}{2}}+{\frac{m}{2}};\,{\frac{3}{2}}+{\frac{m}{2}};\,{a}^{2}{x}^{2})}}+{\frac{{a}^{3}{x}^{4+m}}{4+m}{\mbox{$_2$F$_1$}({\frac{3}{2}},2+{\frac{m}{2}};\,3+{\frac{m}{2}};\,{a}^{2}{x}^{2})}}+3\,{\frac{{a}^{2}{x}^{3+m}{\mbox{$_2$F$_1$}(3/2,3/2+m/2;\,5/2+m/2;\,{a}^{2}{x}^{2})}}{3+m}}+3\,{\frac{a{x}^{2+m}{\mbox{$_2$F$_1$}(3/2,1+m/2;\,2+m/2;\,{a}^{2}{x}^{2})}}{2+m}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}^{3} x^{m}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{-a^{2} x^{2} + 1}{\left (a x + 1\right )} x^{m}}{a^{2} x^{2} - 2 \, a x + 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{m} \left (a x + 1\right )^{3}}{\left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}^{3} x^{m}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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