Optimal. Leaf size=167 \[ \frac{c x^{m+1} \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b c^2 x^n}{a c^2-d^2}\right )}{(m+1) \left (a c^2-d^2\right )}-\frac{d x^{m+1} \sqrt{\frac{b x^n}{a}+1} F_1\left (\frac{m+1}{n};\frac{1}{2},1;\frac{m+n+1}{n};-\frac{b x^n}{a},-\frac{b c^2 x^n}{a c^2-d^2}\right )}{(m+1) \left (a c^2-d^2\right ) \sqrt{a+b x^n}} \]
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Rubi [A] time = 0.455837, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.138 \[ \frac{c x^{m+1} \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b c^2 x^n}{a c^2-d^2}\right )}{(m+1) \left (a c^2-d^2\right )}-\frac{d x^{m+1} \sqrt{\frac{b x^n}{a}+1} F_1\left (\frac{m+1}{n};\frac{1}{2},1;\frac{m+n+1}{n};-\frac{b x^n}{a},-\frac{b c^2 x^n}{a c^2-d^2}\right )}{(m+1) \left (a c^2-d^2\right ) \sqrt{a+b x^n}} \]
Antiderivative was successfully verified.
[In] Int[x^m/(a*c + b*c*x^n + d*Sqrt[a + b*x^n]),x]
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Rubi in Sympy [A] time = 43.1399, size = 126, normalized size = 0.75 \[ - \frac{c x^{m + 1}{{}_{2}F_{1}\left (\begin{matrix} 1, \frac{m + 1}{n} \\ \frac{m + n + 1}{n} \end{matrix}\middle |{- \frac{b c^{2} x^{n}}{a c^{2} - d^{2}}} \right )}}{\left (m + 1\right ) \left (- a c^{2} + d^{2}\right )} + \frac{d x^{m + 1} \sqrt{a + b x^{n}} \operatorname{appellf_{1}}{\left (\frac{m + 1}{n},\frac{1}{2},1,\frac{m + n + 1}{n},- \frac{b x^{n}}{a},- \frac{b c^{2} x^{n}}{a c^{2} - d^{2}} \right )}}{a \sqrt{1 + \frac{b x^{n}}{a}} \left (m + 1\right ) \left (- a c^{2} + d^{2}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**m/(a*c+b*c*x**n+d*(a+b*x**n)**(1/2)),x)
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Mathematica [B] time = 1.27272, size = 373, normalized size = 2.23 \[ \frac{x^{m+1} \left (c \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b c^2 x^n}{a c^2-d^2}\right )-\frac{2 a d (m+n+1) \left (d^2-a c^2\right )^2 F_1\left (\frac{m+1}{n};\frac{1}{2},1;\frac{m+n+1}{n};-\frac{b x^n}{a},-\frac{b c^2 x^n}{a c^2-d^2}\right )}{\sqrt{a+b x^n} \left (a c^2+b c^2 x^n-d^2\right ) \left (2 a (m+n+1) \left (a c^2-d^2\right ) F_1\left (\frac{m+1}{n};\frac{1}{2},1;\frac{m+n+1}{n};-\frac{b x^n}{a},-\frac{b c^2 x^n}{a c^2-d^2}\right )-b n x^n \left (2 a c^2 F_1\left (\frac{m+n+1}{n};\frac{1}{2},2;\frac{m+1}{n}+2;-\frac{b x^n}{a},-\frac{b c^2 x^n}{a c^2-d^2}\right )+\left (a c^2-d^2\right ) F_1\left (\frac{m+n+1}{n};\frac{3}{2},1;\frac{m+1}{n}+2;-\frac{b x^n}{a},-\frac{b c^2 x^n}{a c^2-d^2}\right )\right )\right )}\right )}{(m+1) \left (a c^2-d^2\right )} \]
Warning: Unable to verify antiderivative.
[In] Integrate[x^m/(a*c + b*c*x^n + d*Sqrt[a + b*x^n]),x]
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Maple [F] time = 0.019, size = 0, normalized size = 0. \[ \int{{x}^{m} \left ( ac+bc{x}^{n}+d\sqrt{a+b{x}^{n}} \right ) ^{-1}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^m/(a*c+b*c*x^n+d*(a+b*x^n)^(1/2)),x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{m}}{b c x^{n} + a c + \sqrt{b x^{n} + a} d}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^m/(b*c*x^n + a*c + sqrt(b*x^n + a)*d),x, algorithm="maxima")
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{x^{m}}{b c x^{n} + a c + \sqrt{b x^{n} + a} d}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^m/(b*c*x^n + a*c + sqrt(b*x^n + a)*d),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{m}}{a c + b c x^{n} + d \sqrt{a + b x^{n}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**m/(a*c+b*c*x**n+d*(a+b*x**n)**(1/2)),x)
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{m}}{b c x^{n} + a c + \sqrt{b x^{n} + a} d}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^m/(b*c*x^n + a*c + sqrt(b*x^n + a)*d),x, algorithm="giac")
[Out]