3.99 \(\int \frac{1-\sqrt{3}-\sqrt [3]{\frac{b}{a}} x}{\left (1+\sqrt{3}-\sqrt [3]{\frac{b}{a}} x\right ) \sqrt{a-b x^3}} \, dx\)

Optimal. Leaf size=75 \[ \frac{2 \tan ^{-1}\left (\frac{\sqrt{3+2 \sqrt{3}} \sqrt{a} \left (1-x \sqrt [3]{\frac{b}{a}}\right )}{\sqrt{a-b x^3}}\right )}{\sqrt{3+2 \sqrt{3}} \sqrt{a} \sqrt [3]{\frac{b}{a}}} \]

[Out]

(2*ArcTan[(Sqrt[3 + 2*Sqrt[3]]*Sqrt[a]*(1 - (b/a)^(1/3)*x))/Sqrt[a - b*x^3]])/(S
qrt[3 + 2*Sqrt[3]]*Sqrt[a]*(b/a)^(1/3))

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Rubi [A]  time = 0.331808, antiderivative size = 75, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 55, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.036 \[ \frac{2 \tan ^{-1}\left (\frac{\sqrt{3+2 \sqrt{3}} \sqrt{a} \left (1-x \sqrt [3]{\frac{b}{a}}\right )}{\sqrt{a-b x^3}}\right )}{\sqrt{3+2 \sqrt{3}} \sqrt{a} \sqrt [3]{\frac{b}{a}}} \]

Antiderivative was successfully verified.

[In]  Int[(1 - Sqrt[3] - (b/a)^(1/3)*x)/((1 + Sqrt[3] - (b/a)^(1/3)*x)*Sqrt[a - b*x^3]),x]

[Out]

(2*ArcTan[(Sqrt[3 + 2*Sqrt[3]]*Sqrt[a]*(1 - (b/a)^(1/3)*x))/Sqrt[a - b*x^3]])/(S
qrt[3 + 2*Sqrt[3]]*Sqrt[a]*(b/a)^(1/3))

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Rubi in Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((1-(b/a)**(1/3)*x-3**(1/2))/(1-(b/a)**(1/3)*x+3**(1/2))/(-b*x**3+a)**(1/2),x)

[Out]

Timed out

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Mathematica [C]  time = 8.08572, size = 1491, normalized size = 19.88 \[ \text{result too large to display} \]

Warning: Unable to verify antiderivative.

[In]  Integrate[(1 - Sqrt[3] - (b/a)^(1/3)*x)/((1 + Sqrt[3] - (b/a)^(1/3)*x)*Sqrt[a - b*x^3]),x]

[Out]

(-32*(26 + 15*Sqrt[3])*a^2*x*AppellF1[1/3, 1/2, 1, 4/3, (b*x^3)/a, (b*x^3)/(10*a
 + 6*Sqrt[3]*a)])/((5 + 3*Sqrt[3])*Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)
*(8*(5 + 3*Sqrt[3])*a*AppellF1[1/3, 1/2, 1, 4/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sq
rt[3]*a)] + 3*b*x^3*(AppellF1[4/3, 1/2, 2, 7/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqr
t[3]*a)] + (5 + 3*Sqrt[3])*AppellF1[4/3, 3/2, 1, 7/3, (b*x^3)/a, (b*x^3)/(10*a +
 6*Sqrt[3]*a)]))) - (32*Sqrt[3]*(26 + 15*Sqrt[3])*a^2*x*AppellF1[1/3, 1/2, 1, 4/
3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)])/((5 + 3*Sqrt[3])*Sqrt[a - b*x^3]*(2
*(5 + 3*Sqrt[3])*a - b*x^3)*(8*(5 + 3*Sqrt[3])*a*AppellF1[1/3, 1/2, 1, 4/3, (b*x
^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + 3*b*x^3*(AppellF1[4/3, 1/2, 2, 7/3, (b*x^
3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + (5 + 3*Sqrt[3])*AppellF1[4/3, 3/2, 1, 7/3,
 (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)]))) - (60*(26 + 15*Sqrt[3])*a^2*(b/a)^(
1/3)*x^2*AppellF1[2/3, 1/2, 1, 5/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)])/((
5 + 3*Sqrt[3])*Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)*(10*(5 + 3*Sqrt[3])
*a*AppellF1[2/3, 1/2, 1, 5/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + 3*b*x^3
*(AppellF1[5/3, 1/2, 2, 8/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + (5 + 3*S
qrt[3])*AppellF1[5/3, 3/2, 1, 8/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)]))) -
 (20*Sqrt[3]*(26 + 15*Sqrt[3])*a^2*(b/a)^(1/3)*x^2*AppellF1[2/3, 1/2, 1, 5/3, (b
*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)])/((5 + 3*Sqrt[3])*Sqrt[a - b*x^3]*(2*(5 +
 3*Sqrt[3])*a - b*x^3)*(10*(5 + 3*Sqrt[3])*a*AppellF1[2/3, 1/2, 1, 5/3, (b*x^3)/
a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + 3*b*x^3*(AppellF1[5/3, 1/2, 2, 8/3, (b*x^3)/a
, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + (5 + 3*Sqrt[3])*AppellF1[5/3, 3/2, 1, 8/3, (b*
x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)]))) - (16*(26 + 15*Sqrt[3])*a^2*(b/a)^(2/3)
*x^3*AppellF1[1, 1/2, 1, 2, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)])/(Sqrt[3]*(
5 + 3*Sqrt[3])*Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)*(4*(5 + 3*Sqrt[3])*
a*AppellF1[1, 1/2, 1, 2, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + b*x^3*(Appel
lF1[2, 1/2, 2, 3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + (5 + 3*Sqrt[3])*App
ellF1[2, 3/2, 1, 3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)]))) - (7*(26 + 15*Sq
rt[3])*a*b*x^4*AppellF1[4/3, 1/2, 1, 7/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a
)])/((5 + 3*Sqrt[3])*Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)*(14*(5 + 3*Sq
rt[3])*a*AppellF1[4/3, 1/2, 1, 7/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + 3
*b*x^3*(AppellF1[7/3, 1/2, 2, 10/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)] + (
5 + 3*Sqrt[3])*AppellF1[7/3, 3/2, 1, 10/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*
a)])))

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Maple [F]  time = 0.148, size = 0, normalized size = 0. \[ \int{1 \left ( 1-\sqrt [3]{{\frac{b}{a}}}x-\sqrt{3} \right ) \left ( 1-\sqrt [3]{{\frac{b}{a}}}x+\sqrt{3} \right ) ^{-1}{\frac{1}{\sqrt{-b{x}^{3}+a}}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((1-(b/a)^(1/3)*x-3^(1/2))/(1-(b/a)^(1/3)*x+3^(1/2))/(-b*x^3+a)^(1/2),x)

[Out]

int((1-(b/a)^(1/3)*x-3^(1/2))/(1-(b/a)^(1/3)*x+3^(1/2))/(-b*x^3+a)^(1/2),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{x \left (\frac{b}{a}\right )^{\frac{1}{3}} + \sqrt{3} - 1}{\sqrt{-b x^{3} + a}{\left (x \left (\frac{b}{a}\right )^{\frac{1}{3}} - \sqrt{3} - 1\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((x*(b/a)^(1/3) + sqrt(3) - 1)/(sqrt(-b*x^3 + a)*(x*(b/a)^(1/3) - sqrt(3) - 1)),x, algorithm="maxima")

[Out]

integrate((x*(b/a)^(1/3) + sqrt(3) - 1)/(sqrt(-b*x^3 + a)*(x*(b/a)^(1/3) - sqrt(
3) - 1)), x)

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((x*(b/a)^(1/3) + sqrt(3) - 1)/(sqrt(-b*x^3 + a)*(x*(b/a)^(1/3) - sqrt(3) - 1)),x, algorithm="fricas")

[Out]

Timed out

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Sympy [A]  time = 13.636, size = 0, normalized size = 0. \[ \mathrm{NaN} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((1-(b/a)**(1/3)*x-3**(1/2))/(1-(b/a)**(1/3)*x+3**(1/2))/(-b*x**3+a)**(1/2),x)

[Out]

nan

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GIAC/XCAS [A]  time = 0.605362, size = 4, normalized size = 0.05 \[ \mathit{sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((x*(b/a)^(1/3) + sqrt(3) - 1)/(sqrt(-b*x^3 + a)*(x*(b/a)^(1/3) - sqrt(3) - 1)),x, algorithm="giac")

[Out]

sage0*x