3.12.7 \(\int \frac {(-1+x^5)^{2/3} (3+2 x^5)}{x^3 (-1-x^3+x^5)} \, dx\)

Optimal. Leaf size=90 \[ \log \left (\sqrt [3]{x^5-1}-x\right )-\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x}{2 \sqrt [3]{x^5-1}+x}\right )+\frac {3 \left (x^5-1\right )^{2/3}}{2 x^2}-\frac {1}{2} \log \left (\sqrt [3]{x^5-1} x+\left (x^5-1\right )^{2/3}+x^2\right ) \]

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Rubi [F]  time = 0.79, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\left (-1+x^5\right )^{2/3} \left (3+2 x^5\right )}{x^3 \left (-1-x^3+x^5\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[((-1 + x^5)^(2/3)*(3 + 2*x^5))/(x^3*(-1 - x^3 + x^5)),x]

[Out]

(3*(-1 + x^5)^(2/3)*Hypergeometric2F1[-2/3, -2/5, 3/5, x^5])/(2*x^2*(1 - x^5)^(2/3)) - 3*Defer[Int][(-1 + x^5)
^(2/3)/(-1 - x^3 + x^5), x] + 5*Defer[Int][(x^2*(-1 + x^5)^(2/3))/(-1 - x^3 + x^5), x]

Rubi steps

\begin {align*} \int \frac {\left (-1+x^5\right )^{2/3} \left (3+2 x^5\right )}{x^3 \left (-1-x^3+x^5\right )} \, dx &=\int \left (-\frac {3 \left (-1+x^5\right )^{2/3}}{x^3}+\frac {\left (-3+5 x^2\right ) \left (-1+x^5\right )^{2/3}}{-1-x^3+x^5}\right ) \, dx\\ &=-\left (3 \int \frac {\left (-1+x^5\right )^{2/3}}{x^3} \, dx\right )+\int \frac {\left (-3+5 x^2\right ) \left (-1+x^5\right )^{2/3}}{-1-x^3+x^5} \, dx\\ &=-\frac {\left (3 \left (-1+x^5\right )^{2/3}\right ) \int \frac {\left (1-x^5\right )^{2/3}}{x^3} \, dx}{\left (1-x^5\right )^{2/3}}+\int \left (-\frac {3 \left (-1+x^5\right )^{2/3}}{-1-x^3+x^5}+\frac {5 x^2 \left (-1+x^5\right )^{2/3}}{-1-x^3+x^5}\right ) \, dx\\ &=\frac {3 \left (-1+x^5\right )^{2/3} \, _2F_1\left (-\frac {2}{3},-\frac {2}{5};\frac {3}{5};x^5\right )}{2 x^2 \left (1-x^5\right )^{2/3}}-3 \int \frac {\left (-1+x^5\right )^{2/3}}{-1-x^3+x^5} \, dx+5 \int \frac {x^2 \left (-1+x^5\right )^{2/3}}{-1-x^3+x^5} \, dx\\ \end {align*}

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Mathematica [F]  time = 0.27, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (-1+x^5\right )^{2/3} \left (3+2 x^5\right )}{x^3 \left (-1-x^3+x^5\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[((-1 + x^5)^(2/3)*(3 + 2*x^5))/(x^3*(-1 - x^3 + x^5)),x]

[Out]

Integrate[((-1 + x^5)^(2/3)*(3 + 2*x^5))/(x^3*(-1 - x^3 + x^5)), x]

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IntegrateAlgebraic [A]  time = 1.38, size = 90, normalized size = 1.00 \begin {gather*} \log \left (\sqrt [3]{x^5-1}-x\right )-\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x}{2 \sqrt [3]{x^5-1}+x}\right )+\frac {3 \left (x^5-1\right )^{2/3}}{2 x^2}-\frac {1}{2} \log \left (\sqrt [3]{x^5-1} x+\left (x^5-1\right )^{2/3}+x^2\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((-1 + x^5)^(2/3)*(3 + 2*x^5))/(x^3*(-1 - x^3 + x^5)),x]

[Out]

(3*(-1 + x^5)^(2/3))/(2*x^2) - Sqrt[3]*ArcTan[(Sqrt[3]*x)/(x + 2*(-1 + x^5)^(1/3))] + Log[-x + (-1 + x^5)^(1/3
)] - Log[x^2 + x*(-1 + x^5)^(1/3) + (-1 + x^5)^(2/3)]/2

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fricas [A]  time = 5.37, size = 135, normalized size = 1.50 \begin {gather*} -\frac {2 \, \sqrt {3} x^{2} \arctan \left (\frac {67616276 \, \sqrt {3} {\left (x^{5} - 1\right )}^{\frac {1}{3}} x^{2} + 10249526 \, \sqrt {3} {\left (x^{5} - 1\right )}^{\frac {2}{3}} x + \sqrt {3} {\left (1423013 \, x^{5} + 37509888 \, x^{3} - 1423013\right )}}{300763 \, x^{5} - 86350888 \, x^{3} - 300763}\right ) - x^{2} \log \left (\frac {x^{5} - x^{3} + 3 \, {\left (x^{5} - 1\right )}^{\frac {1}{3}} x^{2} - 3 \, {\left (x^{5} - 1\right )}^{\frac {2}{3}} x - 1}{x^{5} - x^{3} - 1}\right ) - 3 \, {\left (x^{5} - 1\right )}^{\frac {2}{3}}}{2 \, x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^5-1)^(2/3)*(2*x^5+3)/x^3/(x^5-x^3-1),x, algorithm="fricas")

[Out]

-1/2*(2*sqrt(3)*x^2*arctan((67616276*sqrt(3)*(x^5 - 1)^(1/3)*x^2 + 10249526*sqrt(3)*(x^5 - 1)^(2/3)*x + sqrt(3
)*(1423013*x^5 + 37509888*x^3 - 1423013))/(300763*x^5 - 86350888*x^3 - 300763)) - x^2*log((x^5 - x^3 + 3*(x^5
- 1)^(1/3)*x^2 - 3*(x^5 - 1)^(2/3)*x - 1)/(x^5 - x^3 - 1)) - 3*(x^5 - 1)^(2/3))/x^2

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (2 \, x^{5} + 3\right )} {\left (x^{5} - 1\right )}^{\frac {2}{3}}}{{\left (x^{5} - x^{3} - 1\right )} x^{3}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^5-1)^(2/3)*(2*x^5+3)/x^3/(x^5-x^3-1),x, algorithm="giac")

[Out]

integrate((2*x^5 + 3)*(x^5 - 1)^(2/3)/((x^5 - x^3 - 1)*x^3), x)

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maple [C]  time = 3.96, size = 288, normalized size = 3.20 \begin {gather*} \frac {3 \left (x^{5}-1\right )^{\frac {2}{3}}}{2 x^{2}}+\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right ) \ln \left (\frac {\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right ) x^{5}+\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )^{2} x^{3}-x^{5}-3 \left (x^{5}-1\right )^{\frac {2}{3}} x -3 \left (x^{5}-1\right )^{\frac {1}{3}} x^{2}-x^{3}-\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )+1}{x^{5}-x^{3}-1}\right )-\ln \left (\frac {-\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right ) x^{5}+\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )^{2} x^{3}-2 x^{5}+2 \RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right ) x^{3}-3 \left (x^{5}-1\right )^{\frac {2}{3}} x -3 \left (x^{5}-1\right )^{\frac {1}{3}} x^{2}+\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )+2}{x^{5}-x^{3}-1}\right ) \RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )-\ln \left (\frac {-\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right ) x^{5}+\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )^{2} x^{3}-2 x^{5}+2 \RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right ) x^{3}-3 \left (x^{5}-1\right )^{\frac {2}{3}} x -3 \left (x^{5}-1\right )^{\frac {1}{3}} x^{2}+\RootOf \left (\textit {\_Z}^{2}+\textit {\_Z} +1\right )+2}{x^{5}-x^{3}-1}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^5-1)^(2/3)*(2*x^5+3)/x^3/(x^5-x^3-1),x)

[Out]

3/2*(x^5-1)^(2/3)/x^2+RootOf(_Z^2+_Z+1)*ln((RootOf(_Z^2+_Z+1)*x^5+RootOf(_Z^2+_Z+1)^2*x^3-x^5-3*(x^5-1)^(2/3)*
x-3*(x^5-1)^(1/3)*x^2-x^3-RootOf(_Z^2+_Z+1)+1)/(x^5-x^3-1))-ln((-RootOf(_Z^2+_Z+1)*x^5+RootOf(_Z^2+_Z+1)^2*x^3
-2*x^5+2*RootOf(_Z^2+_Z+1)*x^3-3*(x^5-1)^(2/3)*x-3*(x^5-1)^(1/3)*x^2+RootOf(_Z^2+_Z+1)+2)/(x^5-x^3-1))*RootOf(
_Z^2+_Z+1)-ln((-RootOf(_Z^2+_Z+1)*x^5+RootOf(_Z^2+_Z+1)^2*x^3-2*x^5+2*RootOf(_Z^2+_Z+1)*x^3-3*(x^5-1)^(2/3)*x-
3*(x^5-1)^(1/3)*x^2+RootOf(_Z^2+_Z+1)+2)/(x^5-x^3-1))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (2 \, x^{5} + 3\right )} {\left (x^{5} - 1\right )}^{\frac {2}{3}}}{{\left (x^{5} - x^{3} - 1\right )} x^{3}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^5-1)^(2/3)*(2*x^5+3)/x^3/(x^5-x^3-1),x, algorithm="maxima")

[Out]

integrate((2*x^5 + 3)*(x^5 - 1)^(2/3)/((x^5 - x^3 - 1)*x^3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int -\frac {{\left (x^5-1\right )}^{2/3}\,\left (2\,x^5+3\right )}{x^3\,\left (-x^5+x^3+1\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-((x^5 - 1)^(2/3)*(2*x^5 + 3))/(x^3*(x^3 - x^5 + 1)),x)

[Out]

int(-((x^5 - 1)^(2/3)*(2*x^5 + 3))/(x^3*(x^3 - x^5 + 1)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (\left (x - 1\right ) \left (x^{4} + x^{3} + x^{2} + x + 1\right )\right )^{\frac {2}{3}} \left (2 x^{5} + 3\right )}{x^{3} \left (x^{5} - x^{3} - 1\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x**5-1)**(2/3)*(2*x**5+3)/x**3/(x**5-x**3-1),x)

[Out]

Integral(((x - 1)*(x**4 + x**3 + x**2 + x + 1))**(2/3)*(2*x**5 + 3)/(x**3*(x**5 - x**3 - 1)), x)

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