3.12.49 \(\int \frac {1+2 x^3}{(-1+x+x^3) \sqrt [3]{-x^2+x^5}} \, dx\)

Optimal. Leaf size=93 \[ -\log \left (\sqrt [3]{x^5-x^2}+x\right )+\frac {1}{2} \log \left (x^2-\sqrt [3]{x^5-x^2} x+\left (x^5-x^2\right )^{2/3}\right )-\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x}{2 \sqrt [3]{x^5-x^2}-x}\right ) \]

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Rubi [F]  time = 1.01, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {1+2 x^3}{\left (-1+x+x^3\right ) \sqrt [3]{-x^2+x^5}} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(1 + 2*x^3)/((-1 + x + x^3)*(-x^2 + x^5)^(1/3)),x]

[Out]

(6*x*(1 - x^3)^(1/3)*Hypergeometric2F1[1/9, 1/3, 10/9, x^3])/(-x^2 + x^5)^(1/3) + (9*x^(2/3)*(-1 + x^3)^(1/3)*
Defer[Subst][Defer[Int][1/((-1 + x^9)^(1/3)*(-1 + x^3 + x^9)), x], x, x^(1/3)])/(-x^2 + x^5)^(1/3) - (6*x^(2/3
)*(-1 + x^3)^(1/3)*Defer[Subst][Defer[Int][x^3/((-1 + x^9)^(1/3)*(-1 + x^3 + x^9)), x], x, x^(1/3)])/(-x^2 + x
^5)^(1/3)

Rubi steps

\begin {align*} \int \frac {1+2 x^3}{\left (-1+x+x^3\right ) \sqrt [3]{-x^2+x^5}} \, dx &=\frac {\left (x^{2/3} \sqrt [3]{-1+x^3}\right ) \int \frac {1+2 x^3}{x^{2/3} \sqrt [3]{-1+x^3} \left (-1+x+x^3\right )} \, dx}{\sqrt [3]{-x^2+x^5}}\\ &=\frac {\left (3 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \frac {1+2 x^9}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}\\ &=\frac {\left (3 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \left (\frac {2}{\sqrt [3]{-1+x^9}}+\frac {3-2 x^3}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )}\right ) \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}\\ &=\frac {\left (3 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \frac {3-2 x^3}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}+\frac {\left (6 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{-1+x^9}} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}\\ &=\frac {\left (6 x^{2/3} \sqrt [3]{1-x^3}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{1-x^9}} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}+\frac {\left (3 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \left (\frac {3}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )}-\frac {2 x^3}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )}\right ) \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}\\ &=\frac {6 x \sqrt [3]{1-x^3} \, _2F_1\left (\frac {1}{9},\frac {1}{3};\frac {10}{9};x^3\right )}{\sqrt [3]{-x^2+x^5}}-\frac {\left (6 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \frac {x^3}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}+\frac {\left (9 x^{2/3} \sqrt [3]{-1+x^3}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{-1+x^9} \left (-1+x^3+x^9\right )} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{-x^2+x^5}}\\ \end {align*}

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Mathematica [F]  time = 0.20, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1+2 x^3}{\left (-1+x+x^3\right ) \sqrt [3]{-x^2+x^5}} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(1 + 2*x^3)/((-1 + x + x^3)*(-x^2 + x^5)^(1/3)),x]

[Out]

Integrate[(1 + 2*x^3)/((-1 + x + x^3)*(-x^2 + x^5)^(1/3)), x]

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IntegrateAlgebraic [A]  time = 1.05, size = 93, normalized size = 1.00 \begin {gather*} -\log \left (\sqrt [3]{x^5-x^2}+x\right )+\frac {1}{2} \log \left (x^2-\sqrt [3]{x^5-x^2} x+\left (x^5-x^2\right )^{2/3}\right )-\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x}{2 \sqrt [3]{x^5-x^2}-x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 + 2*x^3)/((-1 + x + x^3)*(-x^2 + x^5)^(1/3)),x]

[Out]

-(Sqrt[3]*ArcTan[(Sqrt[3]*x)/(-x + 2*(-x^2 + x^5)^(1/3))]) - Log[x + (-x^2 + x^5)^(1/3)] + Log[x^2 - x*(-x^2 +
x^5)^(1/3) + (-x^2 + x^5)^(2/3)]/2

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fricas [A]  time = 1.37, size = 124, normalized size = 1.33 \begin {gather*} -\sqrt {3} \arctan \left (\frac {2 \, \sqrt {3} {\left (x^{5} - x^{2}\right )}^{\frac {1}{3}} x + \sqrt {3} {\left (x^{4} + x^{2} - x\right )} + 2 \, \sqrt {3} {\left (x^{5} - x^{2}\right )}^{\frac {2}{3}}}{3 \, {\left (x^{4} - x^{2} - x\right )}}\right ) - \frac {1}{2} \, \log \left (\frac {x^{4} + x^{2} + 3 \, {\left (x^{5} - x^{2}\right )}^{\frac {1}{3}} x - x + 3 \, {\left (x^{5} - x^{2}\right )}^{\frac {2}{3}}}{x^{4} + x^{2} - x}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x^3+1)/(x^3+x-1)/(x^5-x^2)^(1/3),x, algorithm="fricas")

[Out]

-sqrt(3)*arctan(1/3*(2*sqrt(3)*(x^5 - x^2)^(1/3)*x + sqrt(3)*(x^4 + x^2 - x) + 2*sqrt(3)*(x^5 - x^2)^(2/3))/(x
^4 - x^2 - x)) - 1/2*log((x^4 + x^2 + 3*(x^5 - x^2)^(1/3)*x - x + 3*(x^5 - x^2)^(2/3))/(x^4 + x^2 - x))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {2 \, x^{3} + 1}{{\left (x^{5} - x^{2}\right )}^{\frac {1}{3}} {\left (x^{3} + x - 1\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x^3+1)/(x^3+x-1)/(x^5-x^2)^(1/3),x, algorithm="giac")

[Out]

integrate((2*x^3 + 1)/((x^5 - x^2)^(1/3)*(x^3 + x - 1)), x)

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maple [C]  time = 4.37, size = 385, normalized size = 4.14 \begin {gather*} -\ln \left (\frac {1462231700 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right )^{2} x^{4}-9984360926 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) x^{4}-5117810950 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right )^{2} x^{2}-1758826818 x^{4}-1462231700 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right )^{2} x -17923671861 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) \left (x^{5}-x^{2}\right )^{\frac {2}{3}}-14667651144 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) \left (x^{5}-x^{2}\right )^{\frac {1}{3}} x [phone] \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) x^{2}[phone] \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) x [phone] \left (x^{5}-x^{2}\right )^{\frac {2}{3}}[phone] x \left (x^{5}-x^{2}\right )^{\frac {1}{3}}[phone] x^{2}[phone] x}{x \left (x^{3}+x -1\right )}\right )+\frac {\RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) \ln \left (\frac {251260974 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right )^{2} x^{4}[phone] \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) x^{4}-879413409 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right )^{2} x^{2}[phone] x^{4}-251260974 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right )^{2} x [phone] \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) \left (x^{5}-x^{2}\right )^{\frac {2}{3}}[phone] \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) \left (x^{5}-x^{2}\right )^{\frac {1}{3}} x -19968721852 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) x^{2}-7105231670 \RootOf \left (\textit {\_Z}^{2}-2 \textit {\_Z} +4\right ) x -58670604576 \left (x^{5}-x^{2}\right )^{\frac {2}{3}}-71694687444 x \left (x^{5}-x^{2}\right )^{\frac {1}{3}}[phone] x^{2}-29244634000 x}{x \left (x^{3}+x -1\right )}\right )}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x^3+1)/(x^3+x-1)/(x^5-x^2)^(1/3),x)

[Out]

-ln((1462231700*RootOf(_Z^2-2*_Z+4)^2*x^4-9984360926*RootOf(_Z^2-2*_Z+4)*x^4-5117810950*RootOf(_Z^2-2*_Z+4)^2*
x^2-1758826818*x^4-1462231700*RootOf(_Z^2-2*_Z+4)^2*x-17923671861*RootOf(_Z^2-2*_Z+4)*(x^5-x^2)^(2/3)-14667651
144*RootOf(_Z^2-2*_Z+4)*(x^5-x^2)^(1/3)*x+6431745091*RootOf(_Z^2-2*_Z+4)*x^2+9984360926*RootOf(_Z^2-2*_Z+4)*x+
6512041434*(x^5-x^2)^(2/3)[phone]*x*(x^5-x^2)^(1/3)[phone]*x^2+1758826818*x)/x/(x^3+x-1))+1/2*RootOf(
_Z^2-2*_Z+4)*ln((251260974*RootOf(_Z^2-2*_Z+4)^2*x^4+7105231670*RootOf(_Z^2-2*_Z+4)*x^4-879413409*RootOf(_Z^2-
2*_Z+4)^2*x^2+29244634000*x^4-251260974*RootOf(_Z^2-2*_Z+4)^2*x+35847343722*RootOf(_Z^2-2*_Z+4)*(x^5-x^2)^(2/3
)[phone]*RootOf(_Z^2-2*_Z+4)*(x^5-x^2)^(1/3)*x-19968721852*RootOf(_Z^2-2*_Z+4)*x^2-7105231670*RootOf(_Z^2-
2*_Z+4)*x-58670604576*(x^5-x^2)^(2/3)-71694687444*x*(x^5-x^2)^(1/3)[phone]*x^2-29244634000*x)/x/(x^3+x-1)
)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {2 \, x^{3} + 1}{{\left (x^{5} - x^{2}\right )}^{\frac {1}{3}} {\left (x^{3} + x - 1\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x^3+1)/(x^3+x-1)/(x^5-x^2)^(1/3),x, algorithm="maxima")

[Out]

integrate((2*x^3 + 1)/((x^5 - x^2)^(1/3)*(x^3 + x - 1)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {2\,x^3+1}{{\left (x^5-x^2\right )}^{1/3}\,\left (x^3+x-1\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x^3 + 1)/((x^5 - x^2)^(1/3)*(x + x^3 - 1)),x)

[Out]

int((2*x^3 + 1)/((x^5 - x^2)^(1/3)*(x + x^3 - 1)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x**3+1)/(x**3+x-1)/(x**5-x**2)**(1/3),x)

[Out]

Timed out

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