Optimal. Leaf size=190 \[ -\frac {\log \left (d^{2/3} \left (k^2 x^4+\left (-k^2-1\right ) x^2+1\right )^{2/3}+\left (\sqrt [3]{d} x+\sqrt [3]{d}\right ) \sqrt [3]{k^2 x^4+\left (-k^2-1\right ) x^2+1}+x^2+2 x+1\right )}{2 \sqrt [3]{d}}+\frac {\log \left (-\sqrt [3]{d} \sqrt [3]{k^2 x^4+\left (-k^2-1\right ) x^2+1}+x+1\right )}{\sqrt [3]{d}}+\frac {\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x+\sqrt {3}}{2 \sqrt [3]{d} \sqrt [3]{k^2 x^4+\left (-k^2-1\right ) x^2+1}+x+1}\right )}{\sqrt [3]{d}} \]
________________________________________________________________________________________
Rubi [F] time = 8.09, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {-3-2 \left (1+k^2\right ) x+\left (1+k^2\right ) x^2+4 k^2 x^3+k^2 x^4}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3} \left (-1+d-(2+d) x-\left (1+d k^2\right ) x^2+d k^2 x^3\right )} \, dx \end {gather*}
Verification is not applicable to the result.
[In]
[Out]
Rubi steps
\begin {align*} \int \frac {-3-2 \left (1+k^2\right ) x+\left (1+k^2\right ) x^2+4 k^2 x^3+k^2 x^4}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3} \left (-1+d-(2+d) x-\left (1+d k^2\right ) x^2+d k^2 x^3\right )} \, dx &=\frac {\left (\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {-3-2 \left (1+k^2\right ) x+\left (1+k^2\right ) x^2+4 k^2 x^3+k^2 x^4}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (-1+d-(2+d) x-\left (1+d k^2\right ) x^2+d k^2 x^3\right )} \, dx}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}\\ &=\frac {\left (\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \left (\frac {5 d+\frac {1}{k^2}}{d^2 \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}}+\frac {x}{d \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}}+\frac {1-8 d^2 k^2-d \left (1-5 k^2\right )+\left (2+d+11 d k^2+2 d^2 k^2 \left (1-k^2\right )\right ) x+\left (1+8 d k^2+2 d^2 \left (k^2+3 k^4\right )\right ) x^2}{d^2 k^2 \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (-1+d-(2+d) x-\left (1+d k^2\right ) x^2+d k^2 x^3\right )}\right ) \, dx}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}\\ &=\frac {\left (\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}} \, dx}{d \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (5 d+\frac {1}{k^2}\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {1}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}} \, dx}{d^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {1-8 d^2 k^2-d \left (1-5 k^2\right )+\left (2+d+11 d k^2+2 d^2 k^2 \left (1-k^2\right )\right ) x+\left (1+8 d k^2+2 d^2 \left (k^2+3 k^4\right )\right ) x^2}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (-1+d-(2+d) x-\left (1+d k^2\right ) x^2+d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}\\ &=\frac {\left (5 d+\frac {1}{k^2}\right ) x \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} F_1\left (\frac {1}{2};\frac {2}{3},\frac {2}{3};\frac {3}{2};x^2,k^2 x^2\right )}{d^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \operatorname {Subst}\left (\int \frac {1}{(1-x)^{2/3} \left (1-k^2 x\right )^{2/3}} \, dx,x,x^2\right )}{2 d \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \left (\frac {8 d^2 k^2 \left (1+\frac {-1+d-5 d k^2}{8 d^2 k^2}\right )}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )}+\frac {\left (-2-2 d^2 k^2 \left (1-k^2\right )-d \left (1+11 k^2\right )\right ) x}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )}+\frac {\left (-1-8 d k^2-2 d^2 \left (k^2+3 k^4\right )\right ) x^2}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )}\right ) \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}\\ &=\frac {\left (5 d+\frac {1}{k^2}\right ) x \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} F_1\left (\frac {1}{2};\frac {2}{3},\frac {2}{3};\frac {3}{2};x^2,k^2 x^2\right )}{d^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\operatorname {Subst}\left (\int \frac {1}{\left (1+\left (-1-k^2\right ) x+k^2 x^2\right )^{2/3}} \, dx,x,x^2\right )}{2 d}+\frac {\left (\left (-1+d-5 d k^2+8 d^2 k^2\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {1}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-2-2 d^2 k^2 \left (1-k^2\right )-d \left (1+11 k^2\right )\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-1-8 d k^2-2 d^2 \left (k^2+3 k^4\right )\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x^2}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}\\ &=\frac {\left (5 d+\frac {1}{k^2}\right ) x \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} F_1\left (\frac {1}{2};\frac {2}{3},\frac {2}{3};\frac {3}{2};x^2,k^2 x^2\right )}{d^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-1+d-5 d k^2+8 d^2 k^2\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {1}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-2-2 d^2 k^2 \left (1-k^2\right )-d \left (1+11 k^2\right )\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-1-8 d k^2-2 d^2 \left (k^2+3 k^4\right )\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x^2}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (3 \sqrt {\left (-1-k^2+2 k^2 x^2\right )^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-4 k^2+\left (-1-k^2\right )^2+4 k^2 x^3}} \, dx,x,\sqrt [3]{\left (-1+x^2\right ) \left (-1+k^2 x^2\right )}\right )}{2 d \left (-1-k^2+2 k^2 x^2\right )}\\ &=\frac {\left (5 d+\frac {1}{k^2}\right ) x \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} F_1\left (\frac {1}{2};\frac {2}{3},\frac {2}{3};\frac {3}{2};x^2,k^2 x^2\right )}{d^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}-\frac {3^{3/4} \sqrt {2+\sqrt {3}} \sqrt {\left (-1-k^2+2 k^2 x^2\right )^2} \left (\left (-1+k^2\right )^{2/3}+2^{2/3} k^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}\right ) \sqrt {\frac {\left (-1+k^2\right )^{4/3}-2^{2/3} k^{2/3} \left (-1+k^2\right )^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}+2 \sqrt [3]{2} k^{4/3} \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}{\left (\left (1+\sqrt {3}\right ) \left (-1+k^2\right )^{2/3}+2^{2/3} k^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \left (-1+k^2\right )^{2/3}+2^{2/3} k^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}}{\left (1+\sqrt {3}\right ) \left (-1+k^2\right )^{2/3}+2^{2/3} k^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}}\right )|-7-4 \sqrt {3}\right )}{2^{2/3} d k^{2/3} \left (1+k^2-2 k^2 x^2\right ) \sqrt {\left (-1-k^2 \left (1-2 x^2\right )\right )^2} \sqrt {\frac {\left (-1+k^2\right )^{2/3} \left (\left (-1+k^2\right )^{2/3}+2^{2/3} k^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}\right )}{\left (\left (1+\sqrt {3}\right ) \left (-1+k^2\right )^{2/3}+2^{2/3} k^{2/3} \sqrt [3]{\left (1-x^2\right ) \left (1-k^2 x^2\right )}\right )^2}}}+\frac {\left (\left (-1+d-5 d k^2+8 d^2 k^2\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {1}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-2-2 d^2 k^2 \left (1-k^2\right )-d \left (1+11 k^2\right )\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}+\frac {\left (\left (-1-8 d k^2-2 d^2 \left (k^2+3 k^4\right )\right ) \left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3}\right ) \int \frac {x^2}{\left (1-x^2\right )^{2/3} \left (1-k^2 x^2\right )^{2/3} \left (1-d+(2+d) x+\left (1+d k^2\right ) x^2-d k^2 x^3\right )} \, dx}{d^2 k^2 \left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3}}\\ \end {align*}
________________________________________________________________________________________
Mathematica [F] time = 3.59, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {-3-2 \left (1+k^2\right ) x+\left (1+k^2\right ) x^2+4 k^2 x^3+k^2 x^4}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{2/3} \left (-1+d-(2+d) x-\left (1+d k^2\right ) x^2+d k^2 x^3\right )} \, dx \end {gather*}
Verification is not applicable to the result.
[In]
[Out]
________________________________________________________________________________________
IntegrateAlgebraic [A] time = 8.12, size = 190, normalized size = 1.00 \begin {gather*} -\frac {\log \left (d^{2/3} \left (k^2 x^4+\left (-k^2-1\right ) x^2+1\right )^{2/3}+\left (\sqrt [3]{d} x+\sqrt [3]{d}\right ) \sqrt [3]{k^2 x^4+\left (-k^2-1\right ) x^2+1}+x^2+2 x+1\right )}{2 \sqrt [3]{d}}+\frac {\log \left (-\sqrt [3]{d} \sqrt [3]{k^2 x^4+\left (-k^2-1\right ) x^2+1}+x+1\right )}{\sqrt [3]{d}}+\frac {\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x+\sqrt {3}}{2 \sqrt [3]{d} \sqrt [3]{k^2 x^4+\left (-k^2-1\right ) x^2+1}+x+1}\right )}{\sqrt [3]{d}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {k^{2} x^{4} + 4 \, k^{2} x^{3} + {\left (k^{2} + 1\right )} x^{2} - 2 \, {\left (k^{2} + 1\right )} x - 3}{{\left (d k^{2} x^{3} - {\left (d k^{2} + 1\right )} x^{2} - {\left (d + 2\right )} x + d - 1\right )} \left ({\left (k^{2} x^{2} - 1\right )} {\left (x^{2} - 1\right )}\right )^{\frac {2}{3}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [F] time = 0.10, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {-3-2 \left (k^{2}+1\right ) x +\left (k^{2}+1\right ) x^{2}+4 k^{2} x^{3}+k^{2} x^{4}}{\left (\left (-x^{2}+1\right ) \left (-k^{2} x^{2}+1\right )\right )^{\frac {2}{3}} \left (-1+d -\left (2+d \right ) x -\left (d \,k^{2}+1\right ) x^{2}+d \,k^{2} x^{3}\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {k^{2} x^{4} + 4 \, k^{2} x^{3} + {\left (k^{2} + 1\right )} x^{2} - 2 \, {\left (k^{2} + 1\right )} x - 3}{{\left (d k^{2} x^{3} - {\left (d k^{2} + 1\right )} x^{2} - {\left (d + 2\right )} x + d - 1\right )} \left ({\left (k^{2} x^{2} - 1\right )} {\left (x^{2} - 1\right )}\right )^{\frac {2}{3}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int -\frac {4\,k^2\,x^3-2\,x\,\left (k^2+1\right )+k^2\,x^4+x^2\,\left (k^2+1\right )-3}{{\left (\left (x^2-1\right )\,\left (k^2\,x^2-1\right )\right )}^{2/3}\,\left (x^2\,\left (d\,k^2+1\right )-d+x\,\left (d+2\right )-d\,k^2\,x^3+1\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________