3.23.68 \(\int \frac {b^8+x^4+a^8 x^8}{\sqrt {-b^4+a^4 x^4} (-b^8+a^8 x^8)} \, dx\)

Optimal. Leaf size=299 \[ \frac {x \left (2 a^4 b^4+1\right ) \sqrt {a^4 x^4-b^4}}{4 a^4 b^4 \left (b^4-a^4 x^4\right )}-\frac {\left (\frac {1}{8}-\frac {i}{8}\right ) \left (2 a^4 b^4-1\right ) \tan ^{-1}\left (\frac {(1+i) a b x}{\sqrt {a^4 x^4-b^4}+a^2 x^2+i b^2}\right )}{a^5 b^5}+\frac {\left (\frac {1}{16}-\frac {i}{16}\right ) \left (2 a^4 b^4-1\right ) \tanh ^{-1}\left (\frac {(1-i) \sqrt {a^4 x^4-b^4}+(1-i) a^2 x^2+(1+i) b^2}{2 \sqrt {3-2 \sqrt {2}} a b x}\right )}{a^5 b^5}-\frac {\left (\frac {1}{16}-\frac {i}{16}\right ) \left (2 a^4 b^4-1\right ) \tanh ^{-1}\left (\frac {(1-i) \sqrt {a^4 x^4-b^4}+(1-i) a^2 x^2+(1+i) b^2}{2 \sqrt {3+2 \sqrt {2}} a b x}\right )}{a^5 b^5} \]

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Rubi [C]  time = 0.77, antiderivative size = 338, normalized size of antiderivative = 1.13, number of steps used = 20, number of rules used = 11, integrand size = 47, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.234, Rules used = {6725, 224, 221, 1455, 527, 523, 409, 1211, 1699, 203, 206} \begin {gather*} -\frac {x \left (\frac {1}{a^4 b^4}+2\right )}{4 \sqrt {a^4 x^4-b^4}}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {a^4 x^4-b^4}}-\frac {\left (1-2 a^4 b^4\right ) \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{-a^4} b x}{\sqrt {a^4 x^4-b^4}}\right )}{8 \sqrt {2} \left (-a^4\right )^{5/4} b^5}-\frac {\left (1-2 a^4 b^4\right ) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{-a^4} b x}{\sqrt {a^4 x^4-b^4}}\right )}{8 \sqrt {2} \left (-a^4\right )^{5/4} b^5}+\frac {\left (1-2 a^4 b^4\right ) \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{4 a^5 b^3 \sqrt {a^4 x^4-b^4}}-\frac {\left (2 a^4 b^4+1\right ) \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{4 a^5 b^3 \sqrt {a^4 x^4-b^4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b^8 + x^4 + a^8*x^8)/(Sqrt[-b^4 + a^4*x^4]*(-b^8 + a^8*x^8)),x]

[Out]

-1/4*((2 + 1/(a^4*b^4))*x)/Sqrt[-b^4 + a^4*x^4] - ((1 - 2*a^4*b^4)*ArcTan[(Sqrt[2]*(-a^4)^(1/4)*b*x)/Sqrt[-b^4
+ a^4*x^4]])/(8*Sqrt[2]*(-a^4)^(5/4)*b^5) - ((1 - 2*a^4*b^4)*ArcTanh[(Sqrt[2]*(-a^4)^(1/4)*b*x)/Sqrt[-b^4 + a
^4*x^4]])/(8*Sqrt[2]*(-a^4)^(5/4)*b^5) + (b*Sqrt[1 - (a^4*x^4)/b^4]*EllipticF[ArcSin[(a*x)/b], -1])/(a*Sqrt[-b
^4 + a^4*x^4]) + ((1 - 2*a^4*b^4)*Sqrt[1 - (a^4*x^4)/b^4]*EllipticF[ArcSin[(a*x)/b], -1])/(4*a^5*b^3*Sqrt[-b^4
+ a^4*x^4]) - ((1 + 2*a^4*b^4)*Sqrt[1 - (a^4*x^4)/b^4]*EllipticF[ArcSin[(a*x)/b], -1])/(4*a^5*b^3*Sqrt[-b^4 +
a^4*x^4])

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 221

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[EllipticF[ArcSin[(Rt[-b, 4]*x)/Rt[a, 4]], -1]/(Rt[a, 4]*Rt[
-b, 4]), x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]

Rule 224

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Dist[Sqrt[1 + (b*x^4)/a]/Sqrt[a + b*x^4], Int[1/Sqrt[1 + (b*x^4)
/a], x], x] /; FreeQ[{a, b}, x] && NegQ[b/a] &&  !GtQ[a, 0]

Rule 409

Int[1/(Sqrt[(a_) + (b_.)*(x_)^4]*((c_) + (d_.)*(x_)^4)), x_Symbol] :> Dist[1/(2*c), Int[1/(Sqrt[a + b*x^4]*(1
- Rt[-(d/c), 2]*x^2)), x], x] + Dist[1/(2*c), Int[1/(Sqrt[a + b*x^4]*(1 + Rt[-(d/c), 2]*x^2)), x], x] /; FreeQ
[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 523

Int[((e_) + (f_.)*(x_)^(n_))/(((a_) + (b_.)*(x_)^(n_))*Sqrt[(c_) + (d_.)*(x_)^(n_)]), x_Symbol] :> Dist[f/b, I
nt[1/Sqrt[c + d*x^n], x], x] + Dist[(b*e - a*f)/b, Int[1/((a + b*x^n)*Sqrt[c + d*x^n]), x], x] /; FreeQ[{a, b,
c, d, e, f, n}, x]

Rule 527

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)), x_Symbol] :> -Simp[
((b*e - a*f)*x*(a + b*x^n)^(p + 1)*(c + d*x^n)^(q + 1))/(a*n*(b*c - a*d)*(p + 1)), x] + Dist[1/(a*n*(b*c - a*d
)*(p + 1)), Int[(a + b*x^n)^(p + 1)*(c + d*x^n)^q*Simp[c*(b*e - a*f) + e*n*(b*c - a*d)*(p + 1) + d*(b*e - a*f)
*(n*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, q}, x] && LtQ[p, -1]

Rule 1211

Int[1/(((d_) + (e_.)*(x_)^2)*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> Dist[1/(2*d), Int[1/Sqrt[a + c*x^4], x],
x] + Dist[1/(2*d), Int[(d - e*x^2)/((d + e*x^2)*Sqrt[a + c*x^4]), x], x] /; FreeQ[{a, c, d, e}, x] && NeQ[c*d
^2 + a*e^2, 0] && EqQ[c*d^2 - a*e^2, 0]

Rule 1455

Int[((d_) + (e_.)*(x_)^(n_))^(q_.)*((f_) + (g_.)*(x_)^(n_))^(r_.)*((a_) + (c_.)*(x_)^(n2_))^(p_.), x_Symbol] :
> Int[(d + e*x^n)^(p + q)*(f + g*x^n)^r*(a/d + (c*x^n)/e)^p, x] /; FreeQ[{a, c, d, e, f, g, n, q, r}, x] && Eq
Q[n2, 2*n] && EqQ[c*d^2 + a*e^2, 0] && IntegerQ[p]

Rule 1699

Int[((A_) + (B_.)*(x_)^2)/(((d_) + (e_.)*(x_)^2)*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> Dist[A, Subst[Int[1/
(d + 2*a*e*x^2), x], x, x/Sqrt[a + c*x^4]], x] /; FreeQ[{a, c, d, e, A, B}, x] && NeQ[c*d^2 + a*e^2, 0] && EqQ
[c*d^2 - a*e^2, 0] && EqQ[B*d + A*e, 0]

Rule 6725

Int[(u_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{v = RationalFunctionExpand[u/(a + b*x^n), x]}, Int[v, x]
/; SumQ[v]] /; FreeQ[{a, b}, x] && IGtQ[n, 0]

Rubi steps

\begin {align*} \int \frac {b^8+x^4+a^8 x^8}{\sqrt {-b^4+a^4 x^4} \left (-b^8+a^8 x^8\right )} \, dx &=\int \left (\frac {1}{\sqrt {-b^4+a^4 x^4}}+\frac {2 b^8+x^4}{\sqrt {-b^4+a^4 x^4} \left (-b^8+a^8 x^8\right )}\right ) \, dx\\ &=\int \frac {1}{\sqrt {-b^4+a^4 x^4}} \, dx+\int \frac {2 b^8+x^4}{\sqrt {-b^4+a^4 x^4} \left (-b^8+a^8 x^8\right )} \, dx\\ &=\frac {\sqrt {1-\frac {a^4 x^4}{b^4}} \int \frac {1}{\sqrt {1-\frac {a^4 x^4}{b^4}}} \, dx}{\sqrt {-b^4+a^4 x^4}}+\int \frac {2 b^8+x^4}{\left (-b^4+a^4 x^4\right )^{3/2} \left (b^4+a^4 x^4\right )} \, dx\\ &=-\frac {\left (2+\frac {1}{a^4 b^4}\right ) x}{4 \sqrt {-b^4+a^4 x^4}}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {-b^4+a^4 x^4}}+\frac {\int \frac {b^8 \left (1-6 a^4 b^4\right )-a^4 b^4 \left (1+2 a^4 b^4\right ) x^4}{\sqrt {-b^4+a^4 x^4} \left (b^4+a^4 x^4\right )} \, dx}{4 a^4 b^8}\\ &=-\frac {\left (2+\frac {1}{a^4 b^4}\right ) x}{4 \sqrt {-b^4+a^4 x^4}}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {-b^4+a^4 x^4}}-\frac {1}{4} \left (2+\frac {1}{a^4 b^4}\right ) \int \frac {1}{\sqrt {-b^4+a^4 x^4}} \, dx+\frac {1}{2} \left (\frac {1}{a^4}-2 b^4\right ) \int \frac {1}{\sqrt {-b^4+a^4 x^4} \left (b^4+a^4 x^4\right )} \, dx\\ &=-\frac {\left (2+\frac {1}{a^4 b^4}\right ) x}{4 \sqrt {-b^4+a^4 x^4}}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {-b^4+a^4 x^4}}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \int \frac {1}{\left (1-\frac {\sqrt {-a^4} x^2}{b^2}\right ) \sqrt {-b^4+a^4 x^4}} \, dx}{4 b^4}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \int \frac {1}{\left (1+\frac {\sqrt {-a^4} x^2}{b^2}\right ) \sqrt {-b^4+a^4 x^4}} \, dx}{4 b^4}-\frac {\left (\left (2+\frac {1}{a^4 b^4}\right ) \sqrt {1-\frac {a^4 x^4}{b^4}}\right ) \int \frac {1}{\sqrt {1-\frac {a^4 x^4}{b^4}}} \, dx}{4 \sqrt {-b^4+a^4 x^4}}\\ &=-\frac {\left (2+\frac {1}{a^4 b^4}\right ) x}{4 \sqrt {-b^4+a^4 x^4}}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {-b^4+a^4 x^4}}-\frac {\left (2+\frac {1}{a^4 b^4}\right ) b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{4 a \sqrt {-b^4+a^4 x^4}}+2 \frac {\left (\frac {1}{a^4}-2 b^4\right ) \int \frac {1}{\sqrt {-b^4+a^4 x^4}} \, dx}{8 b^4}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \int \frac {1-\frac {\sqrt {-a^4} x^2}{b^2}}{\left (1+\frac {\sqrt {-a^4} x^2}{b^2}\right ) \sqrt {-b^4+a^4 x^4}} \, dx}{8 b^4}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \int \frac {1+\frac {\sqrt {-a^4} x^2}{b^2}}{\left (1-\frac {\sqrt {-a^4} x^2}{b^2}\right ) \sqrt {-b^4+a^4 x^4}} \, dx}{8 b^4}\\ &=-\frac {\left (2+\frac {1}{a^4 b^4}\right ) x}{4 \sqrt {-b^4+a^4 x^4}}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {-b^4+a^4 x^4}}-\frac {\left (2+\frac {1}{a^4 b^4}\right ) b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{4 a \sqrt {-b^4+a^4 x^4}}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \operatorname {Subst}\left (\int \frac {1}{1-2 \sqrt {-a^4} b^2 x^2} \, dx,x,\frac {x}{\sqrt {-b^4+a^4 x^4}}\right )}{8 b^4}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \operatorname {Subst}\left (\int \frac {1}{1+2 \sqrt {-a^4} b^2 x^2} \, dx,x,\frac {x}{\sqrt {-b^4+a^4 x^4}}\right )}{8 b^4}+2 \frac {\left (\left (\frac {1}{a^4}-2 b^4\right ) \sqrt {1-\frac {a^4 x^4}{b^4}}\right ) \int \frac {1}{\sqrt {1-\frac {a^4 x^4}{b^4}}} \, dx}{8 b^4 \sqrt {-b^4+a^4 x^4}}\\ &=-\frac {\left (2+\frac {1}{a^4 b^4}\right ) x}{4 \sqrt {-b^4+a^4 x^4}}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{-a^4} b x}{\sqrt {-b^4+a^4 x^4}}\right )}{8 \sqrt {2} \sqrt [4]{-a^4} b^5}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{-a^4} b x}{\sqrt {-b^4+a^4 x^4}}\right )}{8 \sqrt {2} \sqrt [4]{-a^4} b^5}+\frac {b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{a \sqrt {-b^4+a^4 x^4}}-\frac {\left (2+\frac {1}{a^4 b^4}\right ) b \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{4 a \sqrt {-b^4+a^4 x^4}}+\frac {\left (\frac {1}{a^4}-2 b^4\right ) \sqrt {1-\frac {a^4 x^4}{b^4}} F\left (\left .\sin ^{-1}\left (\frac {a x}{b}\right )\right |-1\right )}{4 a b^3 \sqrt {-b^4+a^4 x^4}}\\ \end {align*}

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Mathematica [C]  time = 0.74, size = 221, normalized size = 0.74 \begin {gather*} \frac {x \left (\frac {5 \left (2 a^4 b^4-1\right ) \left (a^4 x^4-b^4\right ) F_1\left (\frac {1}{4};-\frac {1}{2},1;\frac {5}{4};\frac {a^4 x^4}{b^4},-\frac {a^4 x^4}{b^4}\right )}{\left (a^4 x^4+b^4\right ) \left (5 b^4 F_1\left (\frac {1}{4};-\frac {1}{2},1;\frac {5}{4};\frac {a^4 x^4}{b^4},-\frac {a^4 x^4}{b^4}\right )-2 a^4 x^4 \left (2 F_1\left (\frac {5}{4};-\frac {1}{2},2;\frac {9}{4};\frac {a^4 x^4}{b^4},-\frac {a^4 x^4}{b^4}\right )+F_1\left (\frac {5}{4};\frac {1}{2},1;\frac {9}{4};\frac {a^4 x^4}{b^4},-\frac {a^4 x^4}{b^4}\right )\right )\right )}-2 a^4-\frac {1}{b^4}\right )}{4 a^4 \sqrt {a^4 x^4-b^4}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[(b^8 + x^4 + a^8*x^8)/(Sqrt[-b^4 + a^4*x^4]*(-b^8 + a^8*x^8)),x]

[Out]

(x*(-2*a^4 - b^(-4) + (5*(-1 + 2*a^4*b^4)*(-b^4 + a^4*x^4)*AppellF1[1/4, -1/2, 1, 5/4, (a^4*x^4)/b^4, -((a^4*x
^4)/b^4)])/((b^4 + a^4*x^4)*(5*b^4*AppellF1[1/4, -1/2, 1, 5/4, (a^4*x^4)/b^4, -((a^4*x^4)/b^4)] - 2*a^4*x^4*(2
*AppellF1[5/4, -1/2, 2, 9/4, (a^4*x^4)/b^4, -((a^4*x^4)/b^4)] + AppellF1[5/4, 1/2, 1, 9/4, (a^4*x^4)/b^4, -((a
^4*x^4)/b^4)])))))/(4*a^4*Sqrt[-b^4 + a^4*x^4])

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IntegrateAlgebraic [A]  time = 1.38, size = 178, normalized size = 0.60 \begin {gather*} \frac {x \left (2 a^4 b^4+1\right ) \sqrt {a^4 x^4-b^4}}{4 a^4 b^4 \left (b^4-a^4 x^4\right )}+\frac {\left (\frac {1}{16}+\frac {i}{16}\right ) \left (2 a^4 b^4-1\right ) \tan ^{-1}\left (\frac {\left (\frac {1}{2}+\frac {i}{2}\right ) \sqrt {a^4 x^4-b^4}}{a b x}\right )}{a^5 b^5}-\frac {\left (\frac {1}{8}-\frac {i}{8}\right ) \left (2 a^4 b^4-1\right ) \tan ^{-1}\left (\frac {(1+i) a b x}{\sqrt {a^4 x^4-b^4}+a^2 x^2+i b^2}\right )}{a^5 b^5} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(b^8 + x^4 + a^8*x^8)/(Sqrt[-b^4 + a^4*x^4]*(-b^8 + a^8*x^8)),x]

[Out]

((1 + 2*a^4*b^4)*x*Sqrt[-b^4 + a^4*x^4])/(4*a^4*b^4*(b^4 - a^4*x^4)) + ((1/16 + I/16)*(-1 + 2*a^4*b^4)*ArcTan[
((1/2 + I/2)*Sqrt[-b^4 + a^4*x^4])/(a*b*x)])/(a^5*b^5) - ((1/8 - I/8)*(-1 + 2*a^4*b^4)*ArcTan[((1 + I)*a*b*x)/
(I*b^2 + a^2*x^2 + Sqrt[-b^4 + a^4*x^4])])/(a^5*b^5)

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fricas [A]  time = 2.51, size = 215, normalized size = 0.72 \begin {gather*} -\frac {4 \, {\left (2 \, a^{5} b^{5} + a b\right )} \sqrt {a^{4} x^{4} - b^{4}} x + 2 \, {\left (2 \, a^{4} b^{8} - {\left (2 \, a^{8} b^{4} - a^{4}\right )} x^{4} - b^{4}\right )} \arctan \left (\frac {\sqrt {a^{4} x^{4} - b^{4}} a x}{a^{2} b x^{2} + b^{3}}\right ) + {\left (2 \, a^{4} b^{8} - {\left (2 \, a^{8} b^{4} - a^{4}\right )} x^{4} - b^{4}\right )} \log \left (\frac {a^{4} x^{4} + 2 \, a^{2} b^{2} x^{2} - b^{4} - 2 \, \sqrt {a^{4} x^{4} - b^{4}} a b x}{a^{4} x^{4} + b^{4}}\right )}{16 \, {\left (a^{9} b^{5} x^{4} - a^{5} b^{9}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a^8*x^8+b^8+x^4)/(a^4*x^4-b^4)^(1/2)/(a^8*x^8-b^8),x, algorithm="fricas")

[Out]

-1/16*(4*(2*a^5*b^5 + a*b)*sqrt(a^4*x^4 - b^4)*x + 2*(2*a^4*b^8 - (2*a^8*b^4 - a^4)*x^4 - b^4)*arctan(sqrt(a^4
*x^4 - b^4)*a*x/(a^2*b*x^2 + b^3)) + (2*a^4*b^8 - (2*a^8*b^4 - a^4)*x^4 - b^4)*log((a^4*x^4 + 2*a^2*b^2*x^2 -
b^4 - 2*sqrt(a^4*x^4 - b^4)*a*b*x)/(a^4*x^4 + b^4)))/(a^9*b^5*x^4 - a^5*b^9)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a^{8} x^{8} + b^{8} + x^{4}}{{\left (a^{8} x^{8} - b^{8}\right )} \sqrt {a^{4} x^{4} - b^{4}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a^8*x^8+b^8+x^4)/(a^4*x^4-b^4)^(1/2)/(a^8*x^8-b^8),x, algorithm="giac")

[Out]

integrate((a^8*x^8 + b^8 + x^4)/((a^8*x^8 - b^8)*sqrt(a^4*x^4 - b^4)), x)

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maple [C]  time = 0.05, size = 1031, normalized size = 3.45

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a^8*x^8+b^8+x^4)/(a^4*x^4-b^4)^(1/2)/(a^8*x^8-b^8),x)

[Out]

1/(-a^2/b^2)^(1/2)*(a^2*x^2/b^2+1)^(1/2)*(1-a^2*x^2/b^2)^(1/2)/(a^4*x^4-b^4)^(1/2)*EllipticF(x*(-a^2/b^2)^(1/2
),I)+1/8/b^3*(2*a^4*b^4+1)/a^4*(-1/2*(a^4*x^3+a^3*b*x^2+a^2*b^2*x+a*b^3)/a^2/b^3/((x-b/a)*(a^4*x^3+a^3*b*x^2+a
^2*b^2*x+a*b^3))^(1/2)-1/2/b/(-a^2/b^2)^(1/2)*(a^2*x^2/b^2+1)^(1/2)*(1-a^2*x^2/b^2)^(1/2)/(a^4*x^4-b^4)^(1/2)*
EllipticF(x*(-a^2/b^2)^(1/2),I)+1/2/b/(-a^2/b^2)^(1/2)*(a^2*x^2/b^2+1)^(1/2)*(1-a^2*x^2/b^2)^(1/2)/(a^4*x^4-b^
4)^(1/2)*(EllipticF(x*(-a^2/b^2)^(1/2),I)-EllipticE(x*(-a^2/b^2)^(1/2),I)))+1/4/a^4/b^2*(-2*a^4*b^4-1)*(-1/2*(
a^4*x^2-a^2*b^2)/b^4*x/a^2/((x^2+b^2/a^2)*(a^4*x^2-a^2*b^2))^(1/2)+1/2/b^2/(-a^2/b^2)^(1/2)*(a^2*x^2/b^2+1)^(1
/2)*(1-a^2*x^2/b^2)^(1/2)/(a^4*x^4-b^4)^(1/2)*EllipticF(x*(-a^2/b^2)^(1/2),I)+1/2/b^2/(-a^2/b^2)^(1/2)*(a^2*x^
2/b^2+1)^(1/2)*(1-a^2*x^2/b^2)^(1/2)/(a^4*x^4-b^4)^(1/2)*(EllipticF(x*(-a^2/b^2)^(1/2),I)-EllipticE(x*(-a^2/b^
2)^(1/2),I)))+1/32/a^8*(-2*a^4*b^4+1)*sum(1/_alpha^3*(-2^(1/2)/(-b^4)^(1/2)*arctanh(_alpha^2*(_alpha^2+x^2)*a^
4/(-2*b^4)^(1/2)/(a^4*x^4-b^4)^(1/2))+4/(-a^2/b^2)^(1/2)*_alpha^3*a^4/b^4*(a^2*x^2/b^2+1)^(1/2)*(1-a^2*x^2/b^2
)^(1/2)/(a^4*x^4-b^4)^(1/2)*EllipticPi(x*(-a^2/b^2)^(1/2),_alpha^2*a^2/b^2,(a^2/b^2)^(1/2)/(-a^2/b^2)^(1/2))),
_alpha=RootOf(_Z^4*a^4+b^4))+1/8*(-2*a^4*b^4-1)/a^4/b^3*(1/2*(a^4*x^3-a^3*b*x^2+a^2*b^2*x-a*b^3)/a^2/b^3/((x+b
/a)*(a^4*x^3-a^3*b*x^2+a^2*b^2*x-a*b^3))^(1/2)+1/2/b/(-a^2/b^2)^(1/2)*(a^2*x^2/b^2+1)^(1/2)*(1-a^2*x^2/b^2)^(1
/2)/(a^4*x^4-b^4)^(1/2)*EllipticF(x*(-a^2/b^2)^(1/2),I)-1/2/b/(-a^2/b^2)^(1/2)*(a^2*x^2/b^2+1)^(1/2)*(1-a^2*x^
2/b^2)^(1/2)/(a^4*x^4-b^4)^(1/2)*(EllipticF(x*(-a^2/b^2)^(1/2),I)-EllipticE(x*(-a^2/b^2)^(1/2),I)))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a^{8} x^{8} + b^{8} + x^{4}}{{\left (a^{8} x^{8} - b^{8}\right )} \sqrt {a^{4} x^{4} - b^{4}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a^8*x^8+b^8+x^4)/(a^4*x^4-b^4)^(1/2)/(a^8*x^8-b^8),x, algorithm="maxima")

[Out]

integrate((a^8*x^8 + b^8 + x^4)/((a^8*x^8 - b^8)*sqrt(a^4*x^4 - b^4)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int -\frac {a^8\,x^8+b^8+x^4}{\sqrt {a^4\,x^4-b^4}\,\left (b^8-a^8\,x^8\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(b^8 + x^4 + a^8*x^8)/((a^4*x^4 - b^4)^(1/2)*(b^8 - a^8*x^8)),x)

[Out]

int(-(b^8 + x^4 + a^8*x^8)/((a^4*x^4 - b^4)^(1/2)*(b^8 - a^8*x^8)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a^{8} x^{8} + b^{8} + x^{4}}{\sqrt {\left (a x - b\right ) \left (a x + b\right ) \left (a^{2} x^{2} + b^{2}\right )} \left (a x - b\right ) \left (a x + b\right ) \left (a^{2} x^{2} + b^{2}\right ) \left (a^{4} x^{4} + b^{4}\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a**8*x**8+b**8+x**4)/(a**4*x**4-b**4)**(1/2)/(a**8*x**8-b**8),x)

[Out]

Integral((a**8*x**8 + b**8 + x**4)/(sqrt((a*x - b)*(a*x + b)*(a**2*x**2 + b**2))*(a*x - b)*(a*x + b)*(a**2*x**
2 + b**2)*(a**4*x**4 + b**4)), x)

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