Optimal. Leaf size=28 \[ -\frac {4 \left (x^3+x\right )^{3/4} \left (14 x^3-3 x^2-3\right )}{21 x^6} \]
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Rubi [A] time = 0.36, antiderivative size = 49, normalized size of antiderivative = 1.75, number of steps used = 21, number of rules used = 5, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2052, 2025, 2011, 364, 2032} \begin {gather*} -\frac {8 \left (x^3+x\right )^{3/4}}{3 x^3}+\frac {4 \left (x^3+x\right )^{3/4}}{7 x^6}+\frac {4 \left (x^3+x\right )^{3/4}}{7 x^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 364
Rule 2011
Rule 2025
Rule 2032
Rule 2052
Rubi steps
\begin {align*} \int \frac {\left (3+x^2\right ) \left (-1-x^2+2 x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx &=\int \left (-\frac {3}{x^6 \sqrt [4]{x+x^3}}-\frac {4}{x^4 \sqrt [4]{x+x^3}}+\frac {6}{x^3 \sqrt [4]{x+x^3}}-\frac {1}{x^2 \sqrt [4]{x+x^3}}+\frac {2}{x \sqrt [4]{x+x^3}}\right ) \, dx\\ &=2 \int \frac {1}{x \sqrt [4]{x+x^3}} \, dx-3 \int \frac {1}{x^6 \sqrt [4]{x+x^3}} \, dx-4 \int \frac {1}{x^4 \sqrt [4]{x+x^3}} \, dx+6 \int \frac {1}{x^3 \sqrt [4]{x+x^3}} \, dx-\int \frac {1}{x^2 \sqrt [4]{x+x^3}} \, dx\\ &=\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}+\frac {16 \left (x+x^3\right )^{3/4}}{13 x^4}-\frac {8 \left (x+x^3\right )^{3/4}}{3 x^3}+\frac {4 \left (x+x^3\right )^{3/4}}{5 x^2}-\frac {8 \left (x+x^3\right )^{3/4}}{x}-\frac {1}{5} \int \frac {1}{\sqrt [4]{x+x^3}} \, dx-2 \int \frac {1}{x \sqrt [4]{x+x^3}} \, dx+\frac {15}{7} \int \frac {1}{x^4 \sqrt [4]{x+x^3}} \, dx+\frac {28}{13} \int \frac {1}{x^2 \sqrt [4]{x+x^3}} \, dx+10 \int \frac {x}{\sqrt [4]{x+x^3}} \, dx\\ &=\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}+\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {8 \left (x+x^3\right )^{3/4}}{3 x^3}-\frac {12 \left (x+x^3\right )^{3/4}}{13 x^2}+\frac {28}{65} \int \frac {1}{\sqrt [4]{x+x^3}} \, dx-\frac {15}{13} \int \frac {1}{x^2 \sqrt [4]{x+x^3}} \, dx-10 \int \frac {x}{\sqrt [4]{x+x^3}} \, dx-\frac {\left (\sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{1+x^2}} \, dx}{5 \sqrt [4]{x+x^3}}+\frac {\left (10 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {x^{3/4}}{\sqrt [4]{1+x^2}} \, dx}{\sqrt [4]{x+x^3}}\\ &=\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}+\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {8 \left (x+x^3\right )^{3/4}}{3 x^3}-\frac {4 x \sqrt [4]{1+x^2} \, _2F_1\left (\frac {1}{4},\frac {3}{8};\frac {11}{8};-x^2\right )}{15 \sqrt [4]{x+x^3}}+\frac {40 x^2 \sqrt [4]{1+x^2} \, _2F_1\left (\frac {1}{4},\frac {7}{8};\frac {15}{8};-x^2\right )}{7 \sqrt [4]{x+x^3}}-\frac {3}{13} \int \frac {1}{\sqrt [4]{x+x^3}} \, dx+\frac {\left (28 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{1+x^2}} \, dx}{65 \sqrt [4]{x+x^3}}-\frac {\left (10 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {x^{3/4}}{\sqrt [4]{1+x^2}} \, dx}{\sqrt [4]{x+x^3}}\\ &=\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}+\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {8 \left (x+x^3\right )^{3/4}}{3 x^3}+\frac {4 x \sqrt [4]{1+x^2} \, _2F_1\left (\frac {1}{4},\frac {3}{8};\frac {11}{8};-x^2\right )}{13 \sqrt [4]{x+x^3}}-\frac {\left (3 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{1+x^2}} \, dx}{13 \sqrt [4]{x+x^3}}\\ &=\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}+\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {8 \left (x+x^3\right )^{3/4}}{3 x^3}\\ \end {align*}
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Mathematica [C] time = 0.08, size = 125, normalized size = 4.46 \begin {gather*} -\frac {4 \sqrt [4]{x^2+1} \left (7 x^2 \left (13 x \left (30 x^2 \, _2F_1\left (-\frac {1}{8},\frac {1}{4};\frac {7}{8};-x^2\right )-3 x \, _2F_1\left (-\frac {5}{8},\frac {1}{4};\frac {3}{8};-x^2\right )+10 \, _2F_1\left (-\frac {9}{8},\frac {1}{4};-\frac {1}{8};-x^2\right )\right )-60 \, _2F_1\left (-\frac {13}{8},\frac {1}{4};-\frac {5}{8};-x^2\right )\right )-195 \, _2F_1\left (-\frac {21}{8},\frac {1}{4};-\frac {13}{8};-x^2\right )\right )}{1365 x^5 \sqrt [4]{x^3+x}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.73, size = 28, normalized size = 1.00 \begin {gather*} -\frac {4 \left (x^3+x\right )^{3/4} \left (14 x^3-3 x^2-3\right )}{21 x^6} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.40, size = 24, normalized size = 0.86 \begin {gather*} -\frac {4 \, {\left (14 \, x^{3} - 3 \, x^{2} - 3\right )} {\left (x^{3} + x\right )}^{\frac {3}{4}}}{21 \, x^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.57, size = 23, normalized size = 0.82 \begin {gather*} \frac {4}{7} \, {\left (\frac {1}{x} + \frac {1}{x^{3}}\right )}^{\frac {7}{4}} - \frac {8}{3} \, {\left (\frac {1}{x} + \frac {1}{x^{3}}\right )}^{\frac {3}{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 30, normalized size = 1.07 \begin {gather*} -\frac {4 \left (14 x^{3}-3 x^{2}-3\right ) \left (x^{2}+1\right )}{21 x^{5} \left (x^{3}+x \right )^{\frac {1}{4}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (2 \, x^{3} - x^{2} - 1\right )} {\left (x^{2} + 3\right )}}{{\left (x^{3} + x\right )}^{\frac {1}{4}} x^{6}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.24, size = 39, normalized size = 1.39 \begin {gather*} \frac {12\,{\left (x^3+x\right )}^{3/4}+12\,x^2\,{\left (x^3+x\right )}^{3/4}-56\,x^3\,{\left (x^3+x\right )}^{3/4}}{21\,x^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (x - 1\right ) \left (x^{2} + 3\right ) \left (2 x^{2} + x + 1\right )}{x^{6} \sqrt [4]{x \left (x^{2} + 1\right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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