3.34 \(\int y \sinh (y) \, dy\)

Optimal. Leaf size=9 \[ y \cosh (y)-\sinh (y) \]

[Out]

y*cosh(y)-sinh(y)

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Rubi [A]  time = 0.01, antiderivative size = 9, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3296, 2637} \[ y \cosh (y)-\sinh (y) \]

Antiderivative was successfully verified.

[In]

Int[y*Sinh[y],y]

[Out]

y*Cosh[y] - Sinh[y]

Rule 2637

Int[sin[Pi/2 + (c_.) + (d_.)*(x_)], x_Symbol] :> Simp[Sin[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rule 3296

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> -Simp[((c + d*x)^m*Cos[e + f*x])/f, x] +
Dist[(d*m)/f, Int[(c + d*x)^(m - 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rubi steps

\begin {align*} \int y \sinh (y) \, dy &=y \cosh (y)-\int \cosh (y) \, dy\\ &=y \cosh (y)-\sinh (y)\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 9, normalized size = 1.00 \[ y \cosh (y)-\sinh (y) \]

Antiderivative was successfully verified.

[In]

Integrate[y*Sinh[y],y]

[Out]

y*Cosh[y] - Sinh[y]

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fricas [A]  time = 0.40, size = 9, normalized size = 1.00 \[ y \cosh \relax (y) - \sinh \relax (y) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(y*sinh(y),y, algorithm="fricas")

[Out]

y*cosh(y) - sinh(y)

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giac [A]  time = 0.81, size = 17, normalized size = 1.89 \[ \frac {1}{2} \, {\left (y + 1\right )} e^{\left (-y\right )} + \frac {1}{2} \, {\left (y - 1\right )} e^{y} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(y*sinh(y),y, algorithm="giac")

[Out]

1/2*(y + 1)*e^(-y) + 1/2*(y - 1)*e^y

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maple [A]  time = 0.00, size = 10, normalized size = 1.11 \[ y \cosh \relax (y )-\sinh \relax (y ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(y*sinh(y),y)

[Out]

y*cosh(y)-sinh(y)

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maxima [B]  time = 0.43, size = 34, normalized size = 3.78 \[ \frac {1}{2} \, y^{2} \sinh \relax (y) + \frac {1}{4} \, {\left (y^{2} + 2 \, y + 2\right )} e^{\left (-y\right )} - \frac {1}{4} \, {\left (y^{2} - 2 \, y + 2\right )} e^{y} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(y*sinh(y),y, algorithm="maxima")

[Out]

1/2*y^2*sinh(y) + 1/4*(y^2 + 2*y + 2)*e^(-y) - 1/4*(y^2 - 2*y + 2)*e^y

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mupad [B]  time = 0.02, size = 9, normalized size = 1.00 \[ y\,\mathrm {cosh}\relax (y)-\mathrm {sinh}\relax (y) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(y*sinh(y),y)

[Out]

y*cosh(y) - sinh(y)

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sympy [A]  time = 0.19, size = 7, normalized size = 0.78 \[ y \cosh {\relax (y )} - \sinh {\relax (y )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(y*sinh(y),y)

[Out]

y*cosh(y) - sinh(y)

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