Optimal. Leaf size=61 \[ \frac {1}{5} \left (x^2-10\right )^{5/2}-\frac {10}{3} \left (x^2-10\right )^{3/2}+100 \sqrt {x^2-10}-100 \sqrt {10} \tan ^{-1}\left (\frac {\sqrt {x^2-10}}{\sqrt {10}}\right ) \]
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Rubi [A] time = 0.03, antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {266, 50, 63, 203} \[ \frac {1}{5} \left (x^2-10\right )^{5/2}-\frac {10}{3} \left (x^2-10\right )^{3/2}+100 \sqrt {x^2-10}-100 \sqrt {10} \tan ^{-1}\left (\frac {\sqrt {x^2-10}}{\sqrt {10}}\right ) \]
Antiderivative was successfully verified.
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Rule 50
Rule 63
Rule 203
Rule 266
Rubi steps
\begin {align*} \int \frac {\left (-10+x^2\right )^{5/2}}{x} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {(-10+x)^{5/2}}{x} \, dx,x,x^2\right )\\ &=\frac {1}{5} \left (-10+x^2\right )^{5/2}-5 \operatorname {Subst}\left (\int \frac {(-10+x)^{3/2}}{x} \, dx,x,x^2\right )\\ &=-\frac {10}{3} \left (-10+x^2\right )^{3/2}+\frac {1}{5} \left (-10+x^2\right )^{5/2}+50 \operatorname {Subst}\left (\int \frac {\sqrt {-10+x}}{x} \, dx,x,x^2\right )\\ &=100 \sqrt {-10+x^2}-\frac {10}{3} \left (-10+x^2\right )^{3/2}+\frac {1}{5} \left (-10+x^2\right )^{5/2}-500 \operatorname {Subst}\left (\int \frac {1}{\sqrt {-10+x} x} \, dx,x,x^2\right )\\ &=100 \sqrt {-10+x^2}-\frac {10}{3} \left (-10+x^2\right )^{3/2}+\frac {1}{5} \left (-10+x^2\right )^{5/2}-1000 \operatorname {Subst}\left (\int \frac {1}{10+x^2} \, dx,x,\sqrt {-10+x^2}\right )\\ &=100 \sqrt {-10+x^2}-\frac {10}{3} \left (-10+x^2\right )^{3/2}+\frac {1}{5} \left (-10+x^2\right )^{5/2}-100 \sqrt {10} \tan ^{-1}\left (\frac {\sqrt {-10+x^2}}{\sqrt {10}}\right )\\ \end {align*}
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Mathematica [A] time = 0.02, size = 47, normalized size = 0.77 \[ \frac {1}{15} \sqrt {x^2-10} \left (3 x^4-110 x^2+2300\right )-100 \sqrt {10} \tan ^{-1}\left (\sqrt {\frac {x^2}{10}-1}\right ) \]
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.05, size = 49, normalized size = 0.80 \[ \frac {1}{15} \sqrt {x^2-10} \left (3 x^4-110 x^2+2300\right )-100 \sqrt {10} \tan ^{-1}\left (\frac {\sqrt {x^2-10}}{\sqrt {10}}\right ) \]
Antiderivative was successfully verified.
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fricas [A] time = 1.06, size = 47, normalized size = 0.77 \[ \frac {1}{15} \, {\left (3 \, x^{4} - 110 \, x^{2} + 2300\right )} \sqrt {x^{2} - 10} - 200 \, \sqrt {10} \arctan \left (-\frac {1}{10} \, \sqrt {10} x + \frac {1}{10} \, \sqrt {10} \sqrt {x^{2} - 10}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.63, size = 46, normalized size = 0.75 \[ \frac {1}{5} \, {\left (x^{2} - 10\right )}^{\frac {5}{2}} - \frac {10}{3} \, {\left (x^{2} - 10\right )}^{\frac {3}{2}} - 100 \, \sqrt {10} \arctan \left (\frac {1}{10} \, \sqrt {10} \sqrt {x^{2} - 10}\right ) + 100 \, \sqrt {x^{2} - 10} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.35, size = 46, normalized size = 0.75
method | result | size |
default | \(\frac {\left (x^{2}-10\right )^{\frac {5}{2}}}{5}-\frac {10 \left (x^{2}-10\right )^{\frac {3}{2}}}{3}+100 \sqrt {x^{2}-10}+100 \sqrt {10}\, \arctan \left (\frac {\sqrt {10}}{\sqrt {x^{2}-10}}\right )\) | \(46\) |
trager | \(\left (\frac {1}{5} x^{4}-\frac {22}{3} x^{2}+\frac {460}{3}\right ) \sqrt {x^{2}-10}-100 \RootOf \left (\textit {\_Z}^{2}+10\right ) \ln \left (\frac {\sqrt {x^{2}-10}+\RootOf \left (\textit {\_Z}^{2}+10\right )}{x}\right )\) | \(49\) |
meijerg | \(-\frac {375 \sqrt {2}\, \sqrt {5}\, \mathrm {signum}\left (-1+\frac {x^{2}}{10}\right )^{\frac {5}{2}} \left (\frac {368 \sqrt {\pi }}{225}-\frac {4 \sqrt {\pi }\, \left (\frac {3}{25} x^{4}-\frac {22}{5} x^{2}+92\right ) \sqrt {1-\frac {x^{2}}{10}}}{225}+\frac {16 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {1-\frac {x^{2}}{10}}}{2}\right )}{15}-\frac {8 \left (\frac {46}{15}-3 \ln \relax (2)+2 \ln \relax (x )-\ln \relax (5)+i \pi \right ) \sqrt {\pi }}{15}\right )}{4 \sqrt {\pi }\, \left (-\mathrm {signum}\left (-1+\frac {x^{2}}{10}\right )\right )^{\frac {5}{2}}}\) | \(108\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.95, size = 42, normalized size = 0.69 \[ \frac {1}{5} \, {\left (x^{2} - 10\right )}^{\frac {5}{2}} - \frac {10}{3} \, {\left (x^{2} - 10\right )}^{\frac {3}{2}} + 100 \, \sqrt {10} \arcsin \left (\frac {\sqrt {10}}{{\left | x \right |}}\right ) + 100 \, \sqrt {x^{2} - 10} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.47, size = 46, normalized size = 0.75 \[ 100\,\sqrt {x^2-10}-100\,\sqrt {10}\,\mathrm {atan}\left (\frac {\sqrt {10}\,\sqrt {x^2-10}}{10}\right )-\frac {10\,{\left (x^2-10\right )}^{3/2}}{3}+\frac {{\left (x^2-10\right )}^{5/2}}{5} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 5.55, size = 167, normalized size = 2.74 \[ \begin {cases} \frac {x^{4} \sqrt {x^{2} - 10}}{5} - \frac {22 x^{2} \sqrt {x^{2} - 10}}{3} + \frac {460 \sqrt {x^{2} - 10}}{3} - 100 \sqrt {10} i \log {\relax (x )} + 50 \sqrt {10} i \log {\left (x^{2} \right )} + 100 \sqrt {10} \operatorname {asin}{\left (\frac {\sqrt {10}}{x} \right )} & \text {for}\: \frac {\left |{x^{2}}\right |}{10} > 1 \\\frac {i x^{4} \sqrt {10 - x^{2}}}{5} - \frac {22 i x^{2} \sqrt {10 - x^{2}}}{3} + \frac {460 i \sqrt {10 - x^{2}}}{3} + 50 \sqrt {10} i \log {\left (x^{2} \right )} - 100 \sqrt {10} i \log {\left (\sqrt {1 - \frac {x^{2}}{10}} + 1 \right )} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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