Optimal. Leaf size=18 \[ \frac {\cosh ^4(x)}{4}-\cosh ^2(x)+\log (\cosh (x)) \]
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Rubi [A] time = 0.02, antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {2590, 266, 43} \[ \frac {\cosh ^4(x)}{4}-\cosh ^2(x)+\log (\cosh (x)) \]
Antiderivative was successfully verified.
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Rule 43
Rule 266
Rule 2590
Rubi steps
\begin {align*} \int \sinh ^4(x) \tanh (x) \, dx &=\operatorname {Subst}\left (\int \frac {\left (1-x^2\right )^2}{x} \, dx,x,\cosh (x)\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {(1-x)^2}{x} \, dx,x,\cosh ^2(x)\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (-2+\frac {1}{x}+x\right ) \, dx,x,\cosh ^2(x)\right )\\ &=-\cosh ^2(x)+\frac {\cosh ^4(x)}{4}+\log (\cosh (x))\\ \end {align*}
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Mathematica [A] time = 0.01, size = 18, normalized size = 1.00 \[ \frac {\cosh ^4(x)}{4}-\cosh ^2(x)+\log (\cosh (x)) \]
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sinh ^4(x) \tanh (x) \, dx \]
Verification is Not applicable to the result.
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fricas [B] time = 1.09, size = 257, normalized size = 14.28 \[ \frac {\cosh \relax (x)^{8} + 8 \, \cosh \relax (x) \sinh \relax (x)^{7} + \sinh \relax (x)^{8} + 4 \, {\left (7 \, \cosh \relax (x)^{2} - 3\right )} \sinh \relax (x)^{6} - 12 \, \cosh \relax (x)^{6} + 8 \, {\left (7 \, \cosh \relax (x)^{3} - 9 \, \cosh \relax (x)\right )} \sinh \relax (x)^{5} - 64 \, x \cosh \relax (x)^{4} + 2 \, {\left (35 \, \cosh \relax (x)^{4} - 90 \, \cosh \relax (x)^{2} - 32 \, x\right )} \sinh \relax (x)^{4} + 8 \, {\left (7 \, \cosh \relax (x)^{5} - 30 \, \cosh \relax (x)^{3} - 32 \, x \cosh \relax (x)\right )} \sinh \relax (x)^{3} + 4 \, {\left (7 \, \cosh \relax (x)^{6} - 45 \, \cosh \relax (x)^{4} - 96 \, x \cosh \relax (x)^{2} - 3\right )} \sinh \relax (x)^{2} - 12 \, \cosh \relax (x)^{2} + 64 \, {\left (\cosh \relax (x)^{4} + 4 \, \cosh \relax (x)^{3} \sinh \relax (x) + 6 \, \cosh \relax (x)^{2} \sinh \relax (x)^{2} + 4 \, \cosh \relax (x) \sinh \relax (x)^{3} + \sinh \relax (x)^{4}\right )} \log \left (\frac {2 \, \cosh \relax (x)}{\cosh \relax (x) - \sinh \relax (x)}\right ) + 8 \, {\left (\cosh \relax (x)^{7} - 9 \, \cosh \relax (x)^{5} - 32 \, x \cosh \relax (x)^{3} - 3 \, \cosh \relax (x)\right )} \sinh \relax (x) + 1}{64 \, {\left (\cosh \relax (x)^{4} + 4 \, \cosh \relax (x)^{3} \sinh \relax (x) + 6 \, \cosh \relax (x)^{2} \sinh \relax (x)^{2} + 4 \, \cosh \relax (x) \sinh \relax (x)^{3} + \sinh \relax (x)^{4}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.61, size = 43, normalized size = 2.39 \[ \frac {1}{64} \, {\left (48 \, e^{\left (4 \, x\right )} - 12 \, e^{\left (2 \, x\right )} + 1\right )} e^{\left (-4 \, x\right )} - x + \frac {1}{64} \, e^{\left (4 \, x\right )} - \frac {3}{16} \, e^{\left (2 \, x\right )} + \log \left (e^{\left (2 \, x\right )} + 1\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.04, size = 17, normalized size = 0.94
method | result | size |
default | \(\frac {\left (\sinh ^{4}\relax (x )\right )}{4}-\frac {\left (\sinh ^{2}\relax (x )\right )}{2}+\ln \left (\cosh \relax (x )\right )\) | \(17\) |
risch | \(-x +\frac {{\mathrm e}^{4 x}}{64}-\frac {3 \,{\mathrm e}^{2 x}}{16}-\frac {3 \,{\mathrm e}^{-2 x}}{16}+\frac {{\mathrm e}^{-4 x}}{64}+\ln \left (1+{\mathrm e}^{2 x}\right )\) | \(36\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.96, size = 35, normalized size = 1.94 \[ -\frac {1}{64} \, {\left (12 \, e^{\left (-2 \, x\right )} - 1\right )} e^{\left (4 \, x\right )} + x - \frac {3}{16} \, e^{\left (-2 \, x\right )} + \frac {1}{64} \, e^{\left (-4 \, x\right )} + \log \left (e^{\left (-2 \, x\right )} + 1\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.36, size = 35, normalized size = 1.94 \[ \ln \left ({\mathrm {e}}^{2\,x}+1\right )-x-\frac {3\,{\mathrm {e}}^{-2\,x}}{16}-\frac {3\,{\mathrm {e}}^{2\,x}}{16}+\frac {{\mathrm {e}}^{-4\,x}}{64}+\frac {{\mathrm {e}}^{4\,x}}{64} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\tanh ^{5}{\relax (x )}}{\operatorname {sech}^{4}{\relax (x )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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