Optimal. Leaf size=148 \[ -\frac {3}{128 x^4}-\frac {\sec ^{-1}(x)^4}{4 x^4}+\frac {3 \sec ^{-1}(x)^2}{16 x^4}-\frac {45}{128 x^2}+\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{8 x}+\frac {9 \sec ^{-1}(x)^2}{16 x^2}-\frac {45 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{64 x}+\frac {\sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{4 x^3}-\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{32 x^3}+\frac {3}{32} \sec ^{-1}(x)^4-\frac {45}{128} \sec ^{-1}(x)^2 \]
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Rubi [A] time = 0.15, antiderivative size = 148, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 5, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.625, Rules used = {5222, 3444, 3311, 30, 3310} \[ -\frac {45}{128 x^2}-\frac {3}{128 x^4}-\frac {\sec ^{-1}(x)^4}{4 x^4}+\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{8 x}+\frac {\sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{4 x^3}+\frac {9 \sec ^{-1}(x)^2}{16 x^2}+\frac {3 \sec ^{-1}(x)^2}{16 x^4}-\frac {45 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{64 x}-\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{32 x^3}+\frac {3}{32} \sec ^{-1}(x)^4-\frac {45}{128} \sec ^{-1}(x)^2 \]
Antiderivative was successfully verified.
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Rule 30
Rule 3310
Rule 3311
Rule 3444
Rule 5222
Rubi steps
\begin {align*} \int \frac {\sec ^{-1}(x)^4}{x^5} \, dx &=\operatorname {Subst}\left (\int x^4 \cos ^3(x) \sin (x) \, dx,x,\sec ^{-1}(x)\right )\\ &=-\frac {\sec ^{-1}(x)^4}{4 x^4}+\operatorname {Subst}\left (\int x^3 \cos ^4(x) \, dx,x,\sec ^{-1}(x)\right )\\ &=\frac {3 \sec ^{-1}(x)^2}{16 x^4}+\frac {\sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{4 x^3}-\frac {\sec ^{-1}(x)^4}{4 x^4}-\frac {3}{8} \operatorname {Subst}\left (\int x \cos ^4(x) \, dx,x,\sec ^{-1}(x)\right )+\frac {3}{4} \operatorname {Subst}\left (\int x^3 \cos ^2(x) \, dx,x,\sec ^{-1}(x)\right )\\ &=-\frac {3}{128 x^4}-\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{32 x^3}+\frac {3 \sec ^{-1}(x)^2}{16 x^4}+\frac {9 \sec ^{-1}(x)^2}{16 x^2}+\frac {\sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{4 x^3}+\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{8 x}-\frac {\sec ^{-1}(x)^4}{4 x^4}-\frac {9}{32} \operatorname {Subst}\left (\int x \cos ^2(x) \, dx,x,\sec ^{-1}(x)\right )+\frac {3}{8} \operatorname {Subst}\left (\int x^3 \, dx,x,\sec ^{-1}(x)\right )-\frac {9}{8} \operatorname {Subst}\left (\int x \cos ^2(x) \, dx,x,\sec ^{-1}(x)\right )\\ &=-\frac {3}{128 x^4}-\frac {45}{128 x^2}-\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{32 x^3}-\frac {45 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{64 x}+\frac {3 \sec ^{-1}(x)^2}{16 x^4}+\frac {9 \sec ^{-1}(x)^2}{16 x^2}+\frac {\sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{4 x^3}+\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{8 x}+\frac {3}{32} \sec ^{-1}(x)^4-\frac {\sec ^{-1}(x)^4}{4 x^4}-\frac {9}{64} \operatorname {Subst}\left (\int x \, dx,x,\sec ^{-1}(x)\right )-\frac {9}{16} \operatorname {Subst}\left (\int x \, dx,x,\sec ^{-1}(x)\right )\\ &=-\frac {3}{128 x^4}-\frac {45}{128 x^2}-\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{32 x^3}-\frac {45 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)}{64 x}-\frac {45}{128} \sec ^{-1}(x)^2+\frac {3 \sec ^{-1}(x)^2}{16 x^4}+\frac {9 \sec ^{-1}(x)^2}{16 x^2}+\frac {\sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{4 x^3}+\frac {3 \sqrt {1-\frac {1}{x^2}} \sec ^{-1}(x)^3}{8 x}+\frac {3}{32} \sec ^{-1}(x)^4-\frac {\sec ^{-1}(x)^4}{4 x^4}\\ \end {align*}
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Mathematica [A] time = 0.08, size = 92, normalized size = 0.62 \[ \frac {4 \left (3 x^4-8\right ) \sec ^{-1}(x)^4-45 x^2+16 \sqrt {1-\frac {1}{x^2}} x \left (3 x^2+2\right ) \sec ^{-1}(x)^3-6 \sqrt {1-\frac {1}{x^2}} x \left (15 x^2+2\right ) \sec ^{-1}(x)+\left (-45 x^4+72 x^2+24\right ) \sec ^{-1}(x)^2-3}{128 x^4} \]
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec ^{-1}(x)^4}{x^5} \, dx \]
Verification is Not applicable to the result.
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fricas [A] time = 1.17, size = 77, normalized size = 0.52 \[ \frac {4 \, {\left (3 \, x^{4} - 8\right )} \operatorname {arcsec}\relax (x)^{4} - 3 \, {\left (15 \, x^{4} - 24 \, x^{2} - 8\right )} \operatorname {arcsec}\relax (x)^{2} - 45 \, x^{2} + 2 \, {\left (8 \, {\left (3 \, x^{2} + 2\right )} \operatorname {arcsec}\relax (x)^{3} - 3 \, {\left (15 \, x^{2} + 2\right )} \operatorname {arcsec}\relax (x)\right )} \sqrt {x^{2} - 1} - 3}{128 \, x^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.98, size = 137, normalized size = 0.93 \[ \frac {3}{32} \, \arccos \left (\frac {1}{x}\right )^{4} + \frac {3 \, \sqrt {-\frac {1}{x^{2}} + 1} \arccos \left (\frac {1}{x}\right )^{3}}{8 \, x} - \frac {45}{128} \, \arccos \left (\frac {1}{x}\right )^{2} - \frac {45 \, \sqrt {-\frac {1}{x^{2}} + 1} \arccos \left (\frac {1}{x}\right )}{64 \, x} + \frac {\sqrt {-\frac {1}{x^{2}} + 1} \arccos \left (\frac {1}{x}\right )^{3}}{4 \, x^{3}} + \frac {9 \, \arccos \left (\frac {1}{x}\right )^{2}}{16 \, x^{2}} - \frac {\arccos \left (\frac {1}{x}\right )^{4}}{4 \, x^{4}} - \frac {3 \, \sqrt {-\frac {1}{x^{2}} + 1} \arccos \left (\frac {1}{x}\right )}{32 \, x^{3}} - \frac {45}{128 \, x^{2}} + \frac {3 \, \arccos \left (\frac {1}{x}\right )^{2}}{16 \, x^{4}} - \frac {3}{128 \, x^{4}} + \frac {189}{1024} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.38, size = 165, normalized size = 1.11
method | result | size |
default | \(-\frac {\mathrm {arcsec}\relax (x )^{4}}{4 x^{4}}+\frac {\mathrm {arcsec}\relax (x )^{3} \left (3 \,\mathrm {arcsec}\relax (x ) x^{3}+3 x^{2} \sqrt {\frac {x^{2}-1}{x^{2}}}+2 \sqrt {\frac {x^{2}-1}{x^{2}}}\right )}{8 x^{3}}+\frac {3 \mathrm {arcsec}\relax (x )^{2}}{16 x^{4}}-\frac {3 \,\mathrm {arcsec}\relax (x ) \left (3 \,\mathrm {arcsec}\relax (x ) x^{3}+3 x^{2} \sqrt {\frac {x^{2}-1}{x^{2}}}+2 \sqrt {\frac {x^{2}-1}{x^{2}}}\right )}{64 x^{3}}+\frac {45 \mathrm {arcsec}\relax (x )^{2}}{128}-\frac {3}{128 x^{4}}-\frac {45}{128 x^{2}}+\frac {9 \mathrm {arcsec}\relax (x )^{2}}{16 x^{2}}-\frac {9 \,\mathrm {arcsec}\relax (x ) \left (\mathrm {arcsec}\relax (x ) x +\sqrt {\frac {x^{2}-1}{x^{2}}}\right )}{16 x}+\frac {9}{32}-\frac {9 \mathrm {arcsec}\relax (x )^{4}}{32}\) | \(165\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {8 \, x^{4} \int \frac {12 \, {\left (x^{2} - 1\right )} \log \left (x^{2}\right )^{2} \log \relax (x)^{2} - 16 \, {\left (x^{2} - 1\right )} \log \left (x^{2}\right ) \log \relax (x)^{3} + 8 \, {\left (x^{2} - 1\right )} \log \relax (x)^{4} + {\left (x^{2} - 4 \, {\left (x^{2} - 1\right )} \log \relax (x) - 1\right )} \log \left (x^{2}\right )^{3} - 12 \, {\left (4 \, {\left (x^{2} - 1\right )} \log \relax (x)^{2} + {\left (x^{2} - 4 \, {\left (x^{2} - 1\right )} \log \relax (x) - 1\right )} \log \left (x^{2}\right )\right )} \arctan \left (\sqrt {x + 1} \sqrt {x - 1}\right )^{2} + 2 \, {\left (4 \, \arctan \left (\sqrt {x + 1} \sqrt {x - 1}\right )^{3} - 3 \, \arctan \left (\sqrt {x + 1} \sqrt {x - 1}\right ) \log \left (x^{2}\right )^{2}\right )} \sqrt {x + 1} \sqrt {x - 1}}{x^{7} - x^{5}}\,{d x} - 16 \, \arctan \left (\sqrt {x + 1} \sqrt {x - 1}\right )^{4} + 24 \, \arctan \left (\sqrt {x + 1} \sqrt {x - 1}\right )^{2} \log \left (x^{2}\right )^{2} - \log \left (x^{2}\right )^{4}}{64 \, x^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {acos}\left (\frac {1}{x}\right )}^4}{x^5} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {asec}^{4}{\relax (x )}}{x^{5}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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