Optimal. Leaf size=18 \[ \frac {x^2}{\log (8 (x-\log (x \log (x))))} \]
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Rubi [F] time = 1.36, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {-x+\left (-x+x^2\right ) \log (x)+\left (-2 x^2 \log (x)+2 x \log (x) \log (x \log (x))\right ) \log (8 x-8 \log (x \log (x)))}{(-x \log (x)+\log (x) \log (x \log (x))) \log ^2(8 x-8 \log (x \log (x)))} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {x-\left (-x+x^2\right ) \log (x)-\left (-2 x^2 \log (x)+2 x \log (x) \log (x \log (x))\right ) \log (8 x-8 \log (x \log (x)))}{\log (x) (x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))} \, dx\\ &=\int \left (\frac {x}{(x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))}-\frac {x^2}{(x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))}+\frac {x}{\log (x) (x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))}+\frac {2 x^2}{(x-\log (x \log (x))) \log (8 (x-\log (x \log (x))))}-\frac {2 x \log (x \log (x))}{(x-\log (x \log (x))) \log (8 (x-\log (x \log (x))))}\right ) \, dx\\ &=2 \int \frac {x^2}{(x-\log (x \log (x))) \log (8 (x-\log (x \log (x))))} \, dx-2 \int \frac {x \log (x \log (x))}{(x-\log (x \log (x))) \log (8 (x-\log (x \log (x))))} \, dx+\int \frac {x}{(x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))} \, dx-\int \frac {x^2}{(x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))} \, dx+\int \frac {x}{\log (x) (x-\log (x \log (x))) \log ^2(8 (x-\log (x \log (x))))} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.33, size = 18, normalized size = 1.00 \begin {gather*} \frac {x^2}{\log (8 (x-\log (x \log (x))))} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.60, size = 18, normalized size = 1.00 \begin {gather*} \frac {x^{2}}{\log \left (8 \, x - 8 \, \log \left (x \log \relax (x)\right )\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.10, size = 63, normalized size = 3.50
method | result | size |
risch | \(\frac {x^{2}}{\ln \left (-8 \ln \relax (x )-8 \ln \left (\ln \relax (x )\right )+4 i \pi \,\mathrm {csgn}\left (i x \ln \relax (x )\right ) \left (-\mathrm {csgn}\left (i x \ln \relax (x )\right )+\mathrm {csgn}\left (i x \right )\right ) \left (-\mathrm {csgn}\left (i x \ln \relax (x )\right )+\mathrm {csgn}\left (i \ln \relax (x )\right )\right )+8 x \right )}\) | \(63\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [C] time = 0.48, size = 24, normalized size = 1.33 \begin {gather*} \frac {x^{2}}{i \, \pi + 3 \, \log \relax (2) + \log \left (-x + \log \relax (x) + \log \left (\log \relax (x)\right )\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.06 \begin {gather*} \int -\frac {x+\ln \relax (x)\,\left (x-x^2\right )+\ln \left (8\,x-8\,\ln \left (x\,\ln \relax (x)\right )\right )\,\left (2\,x^2\,\ln \relax (x)-2\,x\,\ln \left (x\,\ln \relax (x)\right )\,\ln \relax (x)\right )}{{\ln \left (8\,x-8\,\ln \left (x\,\ln \relax (x)\right )\right )}^2\,\left (\ln \left (x\,\ln \relax (x)\right )\,\ln \relax (x)-x\,\ln \relax (x)\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.60, size = 15, normalized size = 0.83 \begin {gather*} \frac {x^{2}}{\log {\left (8 x - 8 \log {\left (x \log {\relax (x )} \right )} \right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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