Optimal. Leaf size=23 \[ e^{\frac {e^{5+x}}{-x+\frac {134369280}{\log ^4(x)}}}+\log (x) \]
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Rubi [F] time = 16.58, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {18055103407718400-268738560 x \log ^4(x)+x^2 \log ^8(x)+e^{-\frac {e^{5+x} \log ^4(x)}{-134369280+x \log ^4(x)}} \left (537477120 e^{5+x} \log ^3(x)+134369280 e^{5+x} x \log ^4(x)+e^{5+x} \left (x-x^2\right ) \log ^8(x)\right )}{18055103407718400 x-268738560 x^2 \log ^4(x)+x^3 \log ^8(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {18055103407718400-268738560 x \log ^4(x)+x^2 \log ^8(x)+e^{-\frac {e^{5+x} \log ^4(x)}{-134369280+x \log ^4(x)}} \left (537477120 e^{5+x} \log ^3(x)+134369280 e^{5+x} x \log ^4(x)+e^{5+x} \left (x-x^2\right ) \log ^8(x)\right )}{x \left (134369280-x \log ^4(x)\right )^2} \, dx\\ &=\int \left (\frac {1}{x}-\frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} \log ^3(x) \left (-537477120-134369280 x \log (x)-x \log ^5(x)+x^2 \log ^5(x)\right )}{x \left (-134369280+x \log ^4(x)\right )^2}\right ) \, dx\\ &=\log (x)-\int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} \log ^3(x) \left (-537477120-134369280 x \log (x)-x \log ^5(x)+x^2 \log ^5(x)\right )}{x \left (-134369280+x \log ^4(x)\right )^2} \, dx\\ &=\log (x)-\int \left (\frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} (-1+x)}{x^2}-\frac {537477120 e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} \left (33592320+x \log ^3(x)\right )}{x^2 \left (-134369280+x \log ^4(x)\right )^2}+\frac {134369280 e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} (-2+x)}{x^2 \left (-134369280+x \log ^4(x)\right )}\right ) \, dx\\ &=\log (x)-134369280 \int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} (-2+x)}{x^2 \left (-134369280+x \log ^4(x)\right )} \, dx+537477120 \int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} \left (33592320+x \log ^3(x)\right )}{x^2 \left (-134369280+x \log ^4(x)\right )^2} \, dx-\int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} (-1+x)}{x^2} \, dx\\ &=\log (x)-134369280 \int \left (-\frac {2 e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x^2 \left (-134369280+x \log ^4(x)\right )}+\frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x \left (-134369280+x \log ^4(x)\right )}\right ) \, dx+537477120 \int \left (\frac {33592320 e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x^2 \left (-134369280+x \log ^4(x)\right )^2}+\frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} \log ^3(x)}{x \left (-134369280+x \log ^4(x)\right )^2}\right ) \, dx-\int \left (-\frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x^2}+\frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x}\right ) \, dx\\ &=\log (x)-134369280 \int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x \left (-134369280+x \log ^4(x)\right )} \, dx+268738560 \int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x^2 \left (-134369280+x \log ^4(x)\right )} \, dx+537477120 \int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}} \log ^3(x)}{x \left (-134369280+x \log ^4(x)\right )^2} \, dx+18055103407718400 \int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x^2 \left (-134369280+x \log ^4(x)\right )^2} \, dx+\int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x^2} \, dx-\int \frac {e^{5+x+\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}}{x} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 3.19, size = 26, normalized size = 1.13 \begin {gather*} e^{\frac {e^{5+x} \log ^4(x)}{134369280-x \log ^4(x)}}+\log (x) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.62, size = 24, normalized size = 1.04 \begin {gather*} e^{\left (-\frac {e^{\left (x + 5\right )} \log \relax (x)^{4}}{x \log \relax (x)^{4} - 134369280}\right )} + \log \relax (x) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2} \log \relax (x)^{8} - 268738560 \, x \log \relax (x)^{4} - {\left ({\left (x^{2} - x\right )} e^{\left (x + 5\right )} \log \relax (x)^{8} - 134369280 \, x e^{\left (x + 5\right )} \log \relax (x)^{4} - 537477120 \, e^{\left (x + 5\right )} \log \relax (x)^{3}\right )} e^{\left (-\frac {e^{\left (x + 5\right )} \log \relax (x)^{4}}{x \log \relax (x)^{4} - 134369280}\right )} + 18055103407718400}{x^{3} \log \relax (x)^{8} - 268738560 \, x^{2} \log \relax (x)^{4} + 18055103407718400 \, x}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 25, normalized size = 1.09
method | result | size |
risch | \(\ln \relax (x )+{\mathrm e}^{-\frac {{\mathrm e}^{5+x} \ln \relax (x )^{4}}{x \ln \relax (x )^{4}-134369280}}\) | \(25\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.53, size = 24, normalized size = 1.04 \begin {gather*} e^{\left (-\frac {e^{\left (x + 5\right )} \log \relax (x)^{4}}{x \log \relax (x)^{4} - 134369280}\right )} + \log \relax (x) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.71, size = 24, normalized size = 1.04 \begin {gather*} {\mathrm {e}}^{-\frac {{\mathrm {e}}^5\,{\mathrm {e}}^x\,{\ln \relax (x)}^4}{x\,{\ln \relax (x)}^4-134369280}}+\ln \relax (x) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.98, size = 24, normalized size = 1.04 \begin {gather*} \log {\relax (x )} + e^{- \frac {e^{x + 5} \log {\relax (x )}^{4}}{x \log {\relax (x )}^{4} - 134369280}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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