Optimal. Leaf size=29 \[ e^{\frac {(1+x) \left (\frac {1}{x^2}-3 \left (x+x^2\right )\right )}{5 \left (e^x-x\right )}} \]
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Rubi [F] time = 24.47, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\exp \left (\frac {1+x-3 x^3-6 x^4-3 x^5}{5 e^x x^2-5 x^3}\right ) \left (3 x+2 x^2+6 x^5+6 x^6+e^x \left (-2-2 x-x^2-3 x^3-9 x^4-3 x^5+3 x^6\right )\right )}{5 e^{2 x} x^3-10 e^x x^4+5 x^5} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \left (3 x+2 x^2+6 x^5+6 x^6+e^x \left (-2-2 x-x^2-3 x^3-9 x^4-3 x^5+3 x^6\right )\right )}{5 \left (e^x-x\right )^2 x^3} \, dx\\ &=\frac {1}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \left (3 x+2 x^2+6 x^5+6 x^6+e^x \left (-2-2 x-x^2-3 x^3-9 x^4-3 x^5+3 x^6\right )\right )}{\left (e^x-x\right )^2 x^3} \, dx\\ &=\frac {1}{5} \int \left (\frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \left (-2-2 x-x^2-3 x^3-9 x^4-3 x^5+3 x^6\right )}{\left (e^x-x\right ) x^3}+\frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \left (1-x^2-3 x^3-3 x^4+3 x^5+3 x^6\right )}{\left (e^x-x\right )^2 x^2}\right ) \, dx\\ &=\frac {1}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \left (-2-2 x-x^2-3 x^3-9 x^4-3 x^5+3 x^6\right )}{\left (e^x-x\right ) x^3} \, dx+\frac {1}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \left (1-x^2-3 x^3-3 x^4+3 x^5+3 x^6\right )}{\left (e^x-x\right )^2 x^2} \, dx\\ &=\frac {1}{5} \int \left (-\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{e^x-x}-\frac {2 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right ) x^3}-\frac {2 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right ) x^2}-\frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right ) x}-\frac {9 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x}{e^x-x}-\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^2}{e^x-x}+\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^3}{e^x-x}\right ) \, dx+\frac {1}{5} \int \left (-\frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right )^2}+\frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right )^2 x^2}-\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x}{\left (e^x-x\right )^2}-\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^2}{\left (e^x-x\right )^2}+\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^3}{\left (e^x-x\right )^2}+\frac {3 e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^4}{\left (e^x-x\right )^2}\right ) \, dx\\ &=-\left (\frac {1}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right )^2} \, dx\right )+\frac {1}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right )^2 x^2} \, dx-\frac {1}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right ) x} \, dx-\frac {2}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right ) x^3} \, dx-\frac {2}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{\left (e^x-x\right ) x^2} \, dx-\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}}}{e^x-x} \, dx-\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x}{\left (e^x-x\right )^2} \, dx-\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^2}{\left (e^x-x\right )^2} \, dx-\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^2}{e^x-x} \, dx+\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^3}{\left (e^x-x\right )^2} \, dx+\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^3}{e^x-x} \, dx+\frac {3}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x^4}{\left (e^x-x\right )^2} \, dx-\frac {9}{5} \int \frac {e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} x}{e^x-x} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.10, size = 36, normalized size = 1.24 \begin {gather*} e^{\frac {1+x-3 x^3-6 x^4-3 x^5}{5 \left (e^x-x\right ) x^2}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.81, size = 36, normalized size = 1.24 \begin {gather*} e^{\left (\frac {3 \, x^{5} + 6 \, x^{4} + 3 \, x^{3} - x - 1}{5 \, {\left (x^{3} - x^{2} e^{x}\right )}}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.12, size = 30, normalized size = 1.03
method | result | size |
risch | \({\mathrm e}^{-\frac {\left (x +1\right ) \left (3 x^{4}+3 x^{3}-1\right )}{5 x^{2} \left ({\mathrm e}^{x}-x \right )}}\) | \(30\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.07, size = 77, normalized size = 2.66 \begin {gather*} {\mathrm {e}}^{\frac {3\,x}{5\,x-5\,{\mathrm {e}}^x}}\,{\mathrm {e}}^{\frac {1}{5\,x\,{\mathrm {e}}^x-5\,x^2}}\,{\mathrm {e}}^{\frac {3\,x^3}{5\,x-5\,{\mathrm {e}}^x}}\,{\mathrm {e}}^{\frac {6\,x^2}{5\,x-5\,{\mathrm {e}}^x}}\,{\mathrm {e}}^{\frac {1}{5\,x^2\,{\mathrm {e}}^x-5\,x^3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.52, size = 32, normalized size = 1.10 \begin {gather*} e^{\frac {- 3 x^{5} - 6 x^{4} - 3 x^{3} + x + 1}{- 5 x^{3} + 5 x^{2} e^{x}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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