Optimal. Leaf size=17 \[ 2+\frac {-81+16 x}{e^{e^x}+x} \]
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Rubi [F] time = 0.78, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {81+e^{e^x} \left (16+e^x (81-16 x)\right )}{e^{2 e^x}+2 e^{e^x} x+x^2} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {81+e^{e^x} \left (16+e^x (81-16 x)\right )}{\left (e^{e^x}+x\right )^2} \, dx\\ &=\int \left (\frac {81+16 e^{e^x}}{\left (e^{e^x}+x\right )^2}-\frac {e^{e^x+x} (-81+16 x)}{\left (e^{e^x}+x\right )^2}\right ) \, dx\\ &=\int \frac {81+16 e^{e^x}}{\left (e^{e^x}+x\right )^2} \, dx-\int \frac {e^{e^x+x} (-81+16 x)}{\left (e^{e^x}+x\right )^2} \, dx\\ &=-\int \left (-\frac {81 e^{e^x+x}}{\left (e^{e^x}+x\right )^2}+\frac {16 e^{e^x+x} x}{\left (e^{e^x}+x\right )^2}\right ) \, dx+\int \left (\frac {16}{e^{e^x}+x}-\frac {-81+16 x}{\left (e^{e^x}+x\right )^2}\right ) \, dx\\ &=-\left (16 \int \frac {e^{e^x+x} x}{\left (e^{e^x}+x\right )^2} \, dx\right )+16 \int \frac {1}{e^{e^x}+x} \, dx+81 \int \frac {e^{e^x+x}}{\left (e^{e^x}+x\right )^2} \, dx-\int \frac {-81+16 x}{\left (e^{e^x}+x\right )^2} \, dx\\ &=-\left (16 \int \frac {e^{e^x+x} x}{\left (e^{e^x}+x\right )^2} \, dx\right )+16 \int \frac {1}{e^{e^x}+x} \, dx+81 \int \frac {e^{e^x+x}}{\left (e^{e^x}+x\right )^2} \, dx-\int \left (-\frac {81}{\left (e^{e^x}+x\right )^2}+\frac {16 x}{\left (e^{e^x}+x\right )^2}\right ) \, dx\\ &=-\left (16 \int \frac {x}{\left (e^{e^x}+x\right )^2} \, dx\right )-16 \int \frac {e^{e^x+x} x}{\left (e^{e^x}+x\right )^2} \, dx+16 \int \frac {1}{e^{e^x}+x} \, dx+81 \int \frac {1}{\left (e^{e^x}+x\right )^2} \, dx+81 \int \frac {e^{e^x+x}}{\left (e^{e^x}+x\right )^2} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.25, size = 15, normalized size = 0.88 \begin {gather*} \frac {-81+16 x}{e^{e^x}+x} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.26, size = 13, normalized size = 0.76 \begin {gather*} \frac {16 \, x - 81}{x + e^{\left (e^{x}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.13, size = 13, normalized size = 0.76 \begin {gather*} \frac {16 \, x - 81}{x + e^{\left (e^{x}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 14, normalized size = 0.82
method | result | size |
risch | \(\frac {16 x -81}{x +{\mathrm e}^{{\mathrm e}^{x}}}\) | \(14\) |
norman | \(\frac {-81-16 \,{\mathrm e}^{{\mathrm e}^{x}}}{x +{\mathrm e}^{{\mathrm e}^{x}}}\) | \(16\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.37, size = 13, normalized size = 0.76 \begin {gather*} \frac {16 \, x - 81}{x + e^{\left (e^{x}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.41, size = 13, normalized size = 0.76 \begin {gather*} \frac {16\,x-81}{x+{\mathrm {e}}^{{\mathrm {e}}^x}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.11, size = 10, normalized size = 0.59 \begin {gather*} \frac {16 x - 81}{x + e^{e^{x}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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