3.70.2 \(\int \frac {(-40-2 x^2+4 x^3+x^5+8 x^6) \log (\frac {2-x^3}{x})+(16 x^2+16 x^5) \log (\log (\frac {2-x^3}{x}))+(-8 x^2+4 x^5) \log (\frac {2-x^3}{x}) \log ^2(\log (\frac {2-x^3}{x}))}{(-8 x^2+4 x^5) \log (\frac {2-x^3}{x})} \, dx\)

Optimal. Leaf size=36 \[ 1-\frac {5-x}{x}+x^2+x \left (\frac {1}{4}+\log ^2\left (\log \left (\frac {2}{x}-x^2\right )\right )\right ) \]

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Rubi [F]  time = 1.84, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\left (-40-2 x^2+4 x^3+x^5+8 x^6\right ) \log \left (\frac {2-x^3}{x}\right )+\left (16 x^2+16 x^5\right ) \log \left (\log \left (\frac {2-x^3}{x}\right )\right )+\left (-8 x^2+4 x^5\right ) \log \left (\frac {2-x^3}{x}\right ) \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (-8 x^2+4 x^5\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[((-40 - 2*x^2 + 4*x^3 + x^5 + 8*x^6)*Log[(2 - x^3)/x] + (16*x^2 + 16*x^5)*Log[Log[(2 - x^3)/x]] + (-8*x^2
+ 4*x^5)*Log[(2 - x^3)/x]*Log[Log[(2 - x^3)/x]]^2)/((-8*x^2 + 4*x^5)*Log[(2 - x^3)/x]),x]

[Out]

-5/x + x/4 + x^2 + 4*Defer[Int][Log[Log[(2 - x^3)/x]]/Log[(2 - x^3)/x], x] - 2*2^(1/3)*Defer[Int][Log[Log[(2 -
x^3)/x]]/((2^(1/3) - x)*Log[(2 - x^3)/x]), x] - 2*2^(1/3)*Defer[Int][Log[Log[(2 - x^3)/x]]/((2^(1/3) + (-1)^(
1/3)*x)*Log[(2 - x^3)/x]), x] - 2*2^(1/3)*Defer[Int][Log[Log[(2 - x^3)/x]]/((2^(1/3) - (-1)^(2/3)*x)*Log[(2 -
x^3)/x]), x] + Defer[Int][Log[Log[(2 - x^3)/x]]^2, x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {\left (-40-2 x^2+4 x^3+x^5+8 x^6\right ) \log \left (\frac {2-x^3}{x}\right )+\left (16 x^2+16 x^5\right ) \log \left (\log \left (\frac {2-x^3}{x}\right )\right )+\left (-8 x^2+4 x^5\right ) \log \left (\frac {2-x^3}{x}\right ) \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right )}{x^2 \left (-8+4 x^3\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx\\ &=\int \left (\frac {1}{4}+\frac {5}{x^2}+2 x+\frac {4 \left (1+x^3\right ) \log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (-2+x^3\right ) \log \left (\frac {2-x^3}{x}\right )}+\log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right )\right ) \, dx\\ &=-\frac {5}{x}+\frac {x}{4}+x^2+4 \int \frac {\left (1+x^3\right ) \log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (-2+x^3\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx+\int \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right ) \, dx\\ &=-\frac {5}{x}+\frac {x}{4}+x^2+4 \int \left (\frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\log \left (\frac {2-x^3}{x}\right )}+\frac {3 \log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (-2+x^3\right ) \log \left (\frac {2-x^3}{x}\right )}\right ) \, dx+\int \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right ) \, dx\\ &=-\frac {5}{x}+\frac {x}{4}+x^2+4 \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\log \left (\frac {2-x^3}{x}\right )} \, dx+12 \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (-2+x^3\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx+\int \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right ) \, dx\\ &=-\frac {5}{x}+\frac {x}{4}+x^2+4 \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\log \left (\frac {2-x^3}{x}\right )} \, dx+12 \int \left (-\frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{3\ 2^{2/3} \left (\sqrt [3]{2}-x\right ) \log \left (\frac {2-x^3}{x}\right )}-\frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{3\ 2^{2/3} \left (\sqrt [3]{2}+\sqrt [3]{-1} x\right ) \log \left (\frac {2-x^3}{x}\right )}-\frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{3\ 2^{2/3} \left (\sqrt [3]{2}-(-1)^{2/3} x\right ) \log \left (\frac {2-x^3}{x}\right )}\right ) \, dx+\int \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right ) \, dx\\ &=-\frac {5}{x}+\frac {x}{4}+x^2+4 \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\log \left (\frac {2-x^3}{x}\right )} \, dx-\left (2 \sqrt [3]{2}\right ) \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (\sqrt [3]{2}-x\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx-\left (2 \sqrt [3]{2}\right ) \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (\sqrt [3]{2}+\sqrt [3]{-1} x\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx-\left (2 \sqrt [3]{2}\right ) \int \frac {\log \left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (\sqrt [3]{2}-(-1)^{2/3} x\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx+\int \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right ) \, dx\\ \end {aligned} \end {gather*}

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Mathematica [F]  time = 0.42, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (-40-2 x^2+4 x^3+x^5+8 x^6\right ) \log \left (\frac {2-x^3}{x}\right )+\left (16 x^2+16 x^5\right ) \log \left (\log \left (\frac {2-x^3}{x}\right )\right )+\left (-8 x^2+4 x^5\right ) \log \left (\frac {2-x^3}{x}\right ) \log ^2\left (\log \left (\frac {2-x^3}{x}\right )\right )}{\left (-8 x^2+4 x^5\right ) \log \left (\frac {2-x^3}{x}\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[((-40 - 2*x^2 + 4*x^3 + x^5 + 8*x^6)*Log[(2 - x^3)/x] + (16*x^2 + 16*x^5)*Log[Log[(2 - x^3)/x]] + (-
8*x^2 + 4*x^5)*Log[(2 - x^3)/x]*Log[Log[(2 - x^3)/x]]^2)/((-8*x^2 + 4*x^5)*Log[(2 - x^3)/x]),x]

[Out]

Integrate[((-40 - 2*x^2 + 4*x^3 + x^5 + 8*x^6)*Log[(2 - x^3)/x] + (16*x^2 + 16*x^5)*Log[Log[(2 - x^3)/x]] + (-
8*x^2 + 4*x^5)*Log[(2 - x^3)/x]*Log[Log[(2 - x^3)/x]]^2)/((-8*x^2 + 4*x^5)*Log[(2 - x^3)/x]), x]

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fricas [A]  time = 0.65, size = 34, normalized size = 0.94 \begin {gather*} \frac {4 \, x^{2} \log \left (\log \left (-\frac {x^{3} - 2}{x}\right )\right )^{2} + 4 \, x^{3} + x^{2} - 20}{4 \, x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x^5-8*x^2)*log((-x^3+2)/x)*log(log((-x^3+2)/x))^2+(16*x^5+16*x^2)*log(log((-x^3+2)/x))+(8*x^6+x^
5+4*x^3-2*x^2-40)*log((-x^3+2)/x))/(4*x^5-8*x^2)/log((-x^3+2)/x),x, algorithm="fricas")

[Out]

1/4*(4*x^2*log(log(-(x^3 - 2)/x))^2 + 4*x^3 + x^2 - 20)/x

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {4 \, {\left (x^{5} - 2 \, x^{2}\right )} \log \left (-\frac {x^{3} - 2}{x}\right ) \log \left (\log \left (-\frac {x^{3} - 2}{x}\right )\right )^{2} + {\left (8 \, x^{6} + x^{5} + 4 \, x^{3} - 2 \, x^{2} - 40\right )} \log \left (-\frac {x^{3} - 2}{x}\right ) + 16 \, {\left (x^{5} + x^{2}\right )} \log \left (\log \left (-\frac {x^{3} - 2}{x}\right )\right )}{4 \, {\left (x^{5} - 2 \, x^{2}\right )} \log \left (-\frac {x^{3} - 2}{x}\right )}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x^5-8*x^2)*log((-x^3+2)/x)*log(log((-x^3+2)/x))^2+(16*x^5+16*x^2)*log(log((-x^3+2)/x))+(8*x^6+x^
5+4*x^3-2*x^2-40)*log((-x^3+2)/x))/(4*x^5-8*x^2)/log((-x^3+2)/x),x, algorithm="giac")

[Out]

integrate(1/4*(4*(x^5 - 2*x^2)*log(-(x^3 - 2)/x)*log(log(-(x^3 - 2)/x))^2 + (8*x^6 + x^5 + 4*x^3 - 2*x^2 - 40)
*log(-(x^3 - 2)/x) + 16*(x^5 + x^2)*log(log(-(x^3 - 2)/x)))/((x^5 - 2*x^2)*log(-(x^3 - 2)/x)), x)

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maple [F]  time = 0.02, size = 0, normalized size = 0.00 \[\int \frac {\left (4 x^{5}-8 x^{2}\right ) \ln \left (\frac {-x^{3}+2}{x}\right ) \ln \left (\ln \left (\frac {-x^{3}+2}{x}\right )\right )^{2}+\left (16 x^{5}+16 x^{2}\right ) \ln \left (\ln \left (\frac {-x^{3}+2}{x}\right )\right )+\left (8 x^{6}+x^{5}+4 x^{3}-2 x^{2}-40\right ) \ln \left (\frac {-x^{3}+2}{x}\right )}{\left (4 x^{5}-8 x^{2}\right ) \ln \left (\frac {-x^{3}+2}{x}\right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((4*x^5-8*x^2)*ln((-x^3+2)/x)*ln(ln((-x^3+2)/x))^2+(16*x^5+16*x^2)*ln(ln((-x^3+2)/x))+(8*x^6+x^5+4*x^3-2*x
^2-40)*ln((-x^3+2)/x))/(4*x^5-8*x^2)/ln((-x^3+2)/x),x)

[Out]

int(((4*x^5-8*x^2)*ln((-x^3+2)/x)*ln(ln((-x^3+2)/x))^2+(16*x^5+16*x^2)*ln(ln((-x^3+2)/x))+(8*x^6+x^5+4*x^3-2*x
^2-40)*ln((-x^3+2)/x))/(4*x^5-8*x^2)/ln((-x^3+2)/x),x)

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maxima [A]  time = 0.57, size = 30, normalized size = 0.83 \begin {gather*} x \log \left (\log \left (-x^{3} + 2\right ) - \log \relax (x)\right )^{2} + x^{2} + \frac {1}{4} \, x - \frac {5}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x^5-8*x^2)*log((-x^3+2)/x)*log(log((-x^3+2)/x))^2+(16*x^5+16*x^2)*log(log((-x^3+2)/x))+(8*x^6+x^
5+4*x^3-2*x^2-40)*log((-x^3+2)/x))/(4*x^5-8*x^2)/log((-x^3+2)/x),x, algorithm="maxima")

[Out]

x*log(log(-x^3 + 2) - log(x))^2 + x^2 + 1/4*x - 5/x

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mupad [B]  time = 4.56, size = 28, normalized size = 0.78 \begin {gather*} \frac {x}{4}+x\,{\ln \left (\ln \left (-\frac {x^3-2}{x}\right )\right )}^2-\frac {5}{x}+x^2 \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(log(-(x^3 - 2)/x)*(4*x^3 - 2*x^2 + x^5 + 8*x^6 - 40) + log(log(-(x^3 - 2)/x))*(16*x^2 + 16*x^5) - log(lo
g(-(x^3 - 2)/x))^2*log(-(x^3 - 2)/x)*(8*x^2 - 4*x^5))/(log(-(x^3 - 2)/x)*(8*x^2 - 4*x^5)),x)

[Out]

x/4 + x*log(log(-(x^3 - 2)/x))^2 - 5/x + x^2

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sympy [A]  time = 0.64, size = 22, normalized size = 0.61 \begin {gather*} x^{2} + x \log {\left (\log {\left (\frac {2 - x^{3}}{x} \right )} \right )}^{2} + \frac {x}{4} - \frac {5}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x**5-8*x**2)*ln((-x**3+2)/x)*ln(ln((-x**3+2)/x))**2+(16*x**5+16*x**2)*ln(ln((-x**3+2)/x))+(8*x**
6+x**5+4*x**3-2*x**2-40)*ln((-x**3+2)/x))/(4*x**5-8*x**2)/ln((-x**3+2)/x),x)

[Out]

x**2 + x*log(log((2 - x**3)/x))**2 + x/4 - 5/x

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