Optimal. Leaf size=30 \[ \frac {e^2}{x \left (-1+x-\frac {1}{2} (-25+x)^2 x^2+\log \left (\frac {3}{x}\right )\right )} \]
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Rubi [A] time = 0.49, antiderivative size = 36, normalized size of antiderivative = 1.20, number of steps used = 3, number of rules used = 3, integrand size = 129, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.023, Rules used = {6688, 12, 6687} \begin {gather*} -\frac {2 e^2}{x \left (x^4-50 x^3+625 x^2-2 x-2 \log \left (\frac {3}{x}\right )+2\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 6687
Rule 6688
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {2 e^2 \left (4-4 x+1875 x^2-200 x^3+5 x^4-2 \log \left (\frac {3}{x}\right )\right )}{x^2 \left (2-2 x+625 x^2-50 x^3+x^4-2 \log \left (\frac {3}{x}\right )\right )^2} \, dx\\ &=\left (2 e^2\right ) \int \frac {4-4 x+1875 x^2-200 x^3+5 x^4-2 \log \left (\frac {3}{x}\right )}{x^2 \left (2-2 x+625 x^2-50 x^3+x^4-2 \log \left (\frac {3}{x}\right )\right )^2} \, dx\\ &=-\frac {2 e^2}{x \left (2-2 x+625 x^2-50 x^3+x^4-2 \log \left (\frac {3}{x}\right )\right )}\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 1.33, size = 38, normalized size = 1.27 \begin {gather*} \frac {2 e^2}{x \left (-2+2 x-625 x^2+50 x^3-x^4+2 \log \left (\frac {3}{x}\right )\right )} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.03, size = 37, normalized size = 1.23 \begin {gather*} -\frac {2 \, e^{2}}{x^{5} - 50 \, x^{4} + 625 \, x^{3} - 2 \, x^{2} - 2 \, x \log \left (\frac {3}{x}\right ) + 2 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.22, size = 42, normalized size = 1.40 \begin {gather*} \frac {2 \, e^{2}}{x^{5} {\left (\frac {50}{x} - \frac {625}{x^{2}} + \frac {2}{x^{3}} + \frac {2 \, \log \left (\frac {3}{x}\right )}{x^{4}} - \frac {2}{x^{4}} - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.07, size = 36, normalized size = 1.20
method | result | size |
risch | \(-\frac {2 \,{\mathrm e}^{2}}{x \left (x^{4}-50 x^{3}+625 x^{2}-2 x -2 \ln \left (\frac {3}{x}\right )+2\right )}\) | \(36\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.49, size = 37, normalized size = 1.23 \begin {gather*} -\frac {2 \, e^{2}}{x^{5} - 50 \, x^{4} + 625 \, x^{3} - 2 \, x^{2} - 2 \, x {\left (\log \relax (3) - 1\right )} + 2 \, x \log \relax (x)} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.66, size = 37, normalized size = 1.23 \begin {gather*} \frac {2\,{\mathrm {e}}^2}{x\,\left (2\,x+2\,\ln \left (\frac {3}{x}\right )-625\,x^2+50\,x^3-x^4-2\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.20, size = 34, normalized size = 1.13 \begin {gather*} \frac {2 e^{2}}{- x^{5} + 50 x^{4} - 625 x^{3} + 2 x^{2} + 2 x \log {\left (\frac {3}{x} \right )} - 2 x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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