Optimal. Leaf size=31 \[ e^{2 x} \left (x+\frac {5 \left (1-x \left (-1+x^2\right )+\log (3+2 x)\right )}{x}\right )^2 \]
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Rubi [F] time = 180.00, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \text {\$Aborted} \end {gather*}
Verification is not applicable to the result.
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Aborted
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Mathematica [A] time = 0.07, size = 32, normalized size = 1.03 \begin {gather*} \frac {e^{2 x} \left (5+5 x+x^2-5 x^3+5 \log (3+2 x)\right )^2}{x^2} \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 0.65, size = 83, normalized size = 2.68 \begin {gather*} -\frac {10 \, {\left (5 \, x^{3} - x^{2} - 5 \, x - 5\right )} e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right ) - 25 \, e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right )^{2} - {\left (25 \, x^{6} - 10 \, x^{5} - 49 \, x^{4} - 40 \, x^{3} + 35 \, x^{2} + 50 \, x + 25\right )} e^{\left (2 \, x\right )}}{x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.19, size = 132, normalized size = 4.26 \begin {gather*} \frac {25 \, x^{6} e^{\left (2 \, x\right )} - 10 \, x^{5} e^{\left (2 \, x\right )} - 49 \, x^{4} e^{\left (2 \, x\right )} - 50 \, x^{3} e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right ) - 40 \, x^{3} e^{\left (2 \, x\right )} + 10 \, x^{2} e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right ) + 35 \, x^{2} e^{\left (2 \, x\right )} + 50 \, x e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right ) + 25 \, e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right )^{2} + 50 \, x e^{\left (2 \, x\right )} + 50 \, e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right ) + 25 \, e^{\left (2 \, x\right )}}{x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.16, size = 87, normalized size = 2.81
method | result | size |
risch | \(\frac {25 \,{\mathrm e}^{2 x} \ln \left (2 x +3\right )^{2}}{x^{2}}-\frac {10 \left (5 x^{3}-x^{2}-5 x -5\right ) {\mathrm e}^{2 x} \ln \left (2 x +3\right )}{x^{2}}+\frac {\left (25 x^{6}-10 x^{5}-49 x^{4}-40 x^{3}+35 x^{2}+50 x +25\right ) {\mathrm e}^{2 x}}{x^{2}}\) | \(87\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.42, size = 83, normalized size = 2.68 \begin {gather*} -\frac {10 \, {\left (5 \, x^{3} - x^{2} - 5 \, x - 5\right )} e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right ) - 25 \, e^{\left (2 \, x\right )} \log \left (2 \, x + 3\right )^{2} - {\left (25 \, x^{6} - 10 \, x^{5} - 49 \, x^{4} - 40 \, x^{3} + 35 \, x^{2} + 50 \, x + 25\right )} e^{\left (2 \, x\right )}}{x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {{\mathrm {e}}^{2\,x}\,\left (100\,x^2+50\,x-150\right )\,{\ln \left (2\,x+3\right )}^2+{\mathrm {e}}^{2\,x}\,\left (-200\,x^5-360\,x^4+110\,x^3+400\,x^2+50\,x-300\right )\,\ln \left (2\,x+3\right )+{\mathrm {e}}^{2\,x}\,\left (100\,x^8+310\,x^7-16\,x^6-740\,x^5-574\,x^4+310\,x^3+400\,x^2-150\right )}{2\,x^4+3\,x^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 0.44, size = 90, normalized size = 2.90 \begin {gather*} \frac {\left (25 x^{6} - 10 x^{5} - 49 x^{4} - 50 x^{3} \log {\left (2 x + 3 \right )} - 40 x^{3} + 10 x^{2} \log {\left (2 x + 3 \right )} + 35 x^{2} + 50 x \log {\left (2 x + 3 \right )} + 50 x + 25 \log {\left (2 x + 3 \right )}^{2} + 50 \log {\left (2 x + 3 \right )} + 25\right ) e^{2 x}}{x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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