Optimal. Leaf size=26 \[ \frac {25 x}{6 \left (1-e^{x+\frac {1}{5} \left (-7-2 x^3\right )}\right )} \]
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Rubi [F] time = 3.28, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {25+e^{\frac {1}{5} \left (-7+5 x-2 x^3\right )} \left (-25+25 x-30 x^3\right )}{6-12 e^{\frac {1}{5} \left (-7+5 x-2 x^3\right )}+6 e^{\frac {2}{5} \left (-7+5 x-2 x^3\right )}} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {e^{\frac {14}{5}+\frac {4 x^3}{5}} \left (25+e^{\frac {1}{5} \left (-7+5 x-2 x^3\right )} \left (-25+25 x-30 x^3\right )\right )}{6 \left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2} \, dx\\ &=\frac {1}{6} \int \frac {e^{\frac {14}{5}+\frac {4 x^3}{5}} \left (25+e^{\frac {1}{5} \left (-7+5 x-2 x^3\right )} \left (-25+25 x-30 x^3\right )\right )}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2} \, dx\\ &=\frac {1}{6} \int \left (-\frac {5 e^{\frac {14}{5}+\frac {4 x^3}{5}} x \left (-5+6 x^2\right )}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2}-5 e^{\frac {7}{5}-x+\frac {2 x^3}{5}} \left (5-5 x+6 x^3\right )-\frac {5 e^{\frac {14}{5}-x+\frac {4 x^3}{5}} \left (5-5 x+6 x^3\right )}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}}\right ) \, dx\\ &=-\left (\frac {5}{6} \int \frac {e^{\frac {14}{5}+\frac {4 x^3}{5}} x \left (-5+6 x^2\right )}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2} \, dx\right )-\frac {5}{6} \int e^{\frac {7}{5}-x+\frac {2 x^3}{5}} \left (5-5 x+6 x^3\right ) \, dx-\frac {5}{6} \int \frac {e^{\frac {14}{5}-x+\frac {4 x^3}{5}} \left (5-5 x+6 x^3\right )}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}} \, dx\\ &=-\frac {25 e^{\frac {7}{5}-x+\frac {2 x^3}{5}} \left (5 x-6 x^3\right )}{6 \left (5-6 x^2\right )}-\frac {5}{6} \int \left (-\frac {5 e^{\frac {14}{5}+\frac {4 x^3}{5}} x}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2}+\frac {6 e^{\frac {14}{5}+\frac {4 x^3}{5}} x^3}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2}\right ) \, dx-\frac {5}{6} \int \left (\frac {5 e^{\frac {14}{5}-x+\frac {4 x^3}{5}}}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}}-\frac {5 e^{\frac {14}{5}-x+\frac {4 x^3}{5}} x}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}}+\frac {6 e^{\frac {14}{5}-x+\frac {4 x^3}{5}} x^3}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}}\right ) \, dx\\ &=-\frac {25 e^{\frac {7}{5}-x+\frac {2 x^3}{5}} \left (5 x-6 x^3\right )}{6 \left (5-6 x^2\right )}-\frac {25}{6} \int \frac {e^{\frac {14}{5}-x+\frac {4 x^3}{5}}}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}} \, dx+\frac {25}{6} \int \frac {e^{\frac {14}{5}+\frac {4 x^3}{5}} x}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2} \, dx+\frac {25}{6} \int \frac {e^{\frac {14}{5}-x+\frac {4 x^3}{5}} x}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}} \, dx-5 \int \frac {e^{\frac {14}{5}+\frac {4 x^3}{5}} x^3}{\left (e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )^2} \, dx-5 \int \frac {e^{\frac {14}{5}-x+\frac {4 x^3}{5}} x^3}{e^x-e^{\frac {7}{5}+\frac {2 x^3}{5}}} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.69, size = 39, normalized size = 1.50 \begin {gather*} \frac {25 e^{\frac {7}{5}+\frac {2 x^3}{5}} x}{6 \left (-e^x+e^{\frac {7}{5}+\frac {2 x^3}{5}}\right )} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.60, size = 16, normalized size = 0.62 \begin {gather*} -\frac {25 \, x}{6 \, {\left (e^{\left (-\frac {2}{5} \, x^{3} + x - \frac {7}{5}\right )} - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.27, size = 16, normalized size = 0.62 \begin {gather*} -\frac {25 \, x}{6 \, {\left (e^{\left (-\frac {2}{5} \, x^{3} + x - \frac {7}{5}\right )} - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.09, size = 17, normalized size = 0.65
method | result | size |
norman | \(-\frac {25 x}{6 \left ({\mathrm e}^{-\frac {2}{5} x^{3}+x -\frac {7}{5}}-1\right )}\) | \(17\) |
risch | \(-\frac {25 x}{6 \left ({\mathrm e}^{-\frac {2}{5} x^{3}+x -\frac {7}{5}}-1\right )}\) | \(17\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.31, size = 18, normalized size = 0.69 \begin {gather*} -\frac {25\,x}{6\,\left ({\mathrm {e}}^{-\frac {2\,x^3}{5}+x-\frac {7}{5}}-1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.18, size = 20, normalized size = 0.77 \begin {gather*} - \frac {25 x}{6 e^{- \frac {2 x^{3}}{5} + x - \frac {7}{5}} - 6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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