3.76.42 \(\int \frac {1}{625} (1633602+1623602 x+1623602 \log (4)) \, dx\)

Optimal. Leaf size=15 \[ 16 \left (x+\frac {811801 (1+x+\log (4))^2}{10000}\right ) \]

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Rubi [A]  time = 0.00, antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {9} \begin {gather*} \frac {(811801 x+816801+811801 \log (4))^2}{507375625} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1633602 + 1623602*x + 1623602*Log[4])/625,x]

[Out]

(816801 + 811801*x + 811801*Log[4])^2/507375625

Rule 9

Int[(a_)*((b_) + (c_.)*(x_)), x_Symbol] :> Simp[(a*(b + c*x)^2)/(2*c), x] /; FreeQ[{a, b, c}, x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\frac {(816801+811801 x+811801 \log (4))^2}{507375625}\\ \end {aligned} \end {gather*}

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Mathematica [A]  time = 0.00, size = 20, normalized size = 1.33 \begin {gather*} \frac {2}{625} \left (816801 x+\frac {811801 x^2}{2}+811801 x \log (4)\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1633602 + 1623602*x + 1623602*Log[4])/625,x]

[Out]

(2*(816801*x + (811801*x^2)/2 + 811801*x*Log[4]))/625

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fricas [A]  time = 1.89, size = 14, normalized size = 0.93 \begin {gather*} \frac {811801}{625} \, x^{2} + \frac {3247204}{625} \, x \log \relax (2) + \frac {1633602}{625} \, x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(3247204/625*log(2)+1623602/625*x+1633602/625,x, algorithm="fricas")

[Out]

811801/625*x^2 + 3247204/625*x*log(2) + 1633602/625*x

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giac [A]  time = 0.18, size = 14, normalized size = 0.93 \begin {gather*} \frac {811801}{625} \, x^{2} + \frac {3247204}{625} \, x \log \relax (2) + \frac {1633602}{625} \, x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(3247204/625*log(2)+1623602/625*x+1633602/625,x, algorithm="giac")

[Out]

811801/625*x^2 + 3247204/625*x*log(2) + 1633602/625*x

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maple [A]  time = 0.02, size = 13, normalized size = 0.87

method	result	size
gosper	\(\frac {x \left (811801 x +3247204 \ln \relax (2)+1633602\right )}{625}\)	\(13\)
default	\(\frac {3247204 x \ln \relax (2)}{625}+\frac {811801 x^{2}}{625}+\frac {1633602 x}{625}\)	\(15\)
norman	\(\left (\frac {3247204 \ln \relax (2)}{625}+\frac {1633602}{625}\right ) x +\frac {811801 x^{2}}{625}\)	\(15\)
risch	\(\frac {3247204 x \ln \relax (2)}{625}+\frac {811801 x^{2}}{625}+\frac {1633602 x}{625}\)	\(15\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(3247204/625*ln(2)+1623602/625*x+1633602/625,x,method=_RETURNVERBOSE)

[Out]

1/625*x*(811801*x+3247204*ln(2)+1633602)

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maxima [A]  time = 0.36, size = 14, normalized size = 0.93 \begin {gather*} \frac {811801}{625} \, x^{2} + \frac {3247204}{625} \, x \log \relax (2) + \frac {1633602}{625} \, x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(3247204/625*log(2)+1623602/625*x+1633602/625,x, algorithm="maxima")

[Out]

811801/625*x^2 + 3247204/625*x*log(2) + 1633602/625*x

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mupad [B]  time = 0.07, size = 14, normalized size = 0.93 \begin {gather*} \frac {811801\,x^2}{625}+\left (\frac {3247204\,\ln \relax (2)}{625}+\frac {1633602}{625}\right )\,x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1623602*x)/625 + (3247204*log(2))/625 + 1633602/625,x)

[Out]

x*((3247204*log(2))/625 + 1633602/625) + (811801*x^2)/625

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sympy [A]  time = 0.05, size = 17, normalized size = 1.13 \begin {gather*} \frac {811801 x^{2}}{625} + x \left (\frac {1633602}{625} + \frac {3247204 \log {\relax (2 )}}{625}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(3247204/625*ln(2)+1623602/625*x+1633602/625,x)

[Out]

811801*x**2/625 + x*(1633602/625 + 3247204*log(2)/625)

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