Optimal. Leaf size=29 \[ 25-e^5-x-\frac {1}{20} \log ^{\frac {2}{\log (5)}}\left (e^{-x} x\right ) \]
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Rubi [A] time = 0.29, antiderivative size = 23, normalized size of antiderivative = 0.79, number of steps used = 4, number of rules used = 3, integrand size = 54, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {12, 6688, 6686} \begin {gather*} -x-\frac {1}{20} \log ^{\frac {2}{\log (5)}}\left (e^{-x} x\right ) \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 6686
Rule 6688
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\frac {\int \frac {-10 x \log (5) \log \left (e^{-x} x\right )+(-1+x) \log ^{\frac {2}{\log (5)}}\left (e^{-x} x\right )}{x \log \left (e^{-x} x\right )} \, dx}{10 \log (5)}\\ &=\frac {\int \left (-10 \log (5)+\frac {(-1+x) \log ^{-1+\frac {2}{\log (5)}}\left (e^{-x} x\right )}{x}\right ) \, dx}{10 \log (5)}\\ &=-x+\frac {\int \frac {(-1+x) \log ^{-1+\frac {2}{\log (5)}}\left (e^{-x} x\right )}{x} \, dx}{10 \log (5)}\\ &=-x-\frac {1}{20} \log ^{\frac {2}{\log (5)}}\left (e^{-x} x\right )\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.03, size = 23, normalized size = 0.79 \begin {gather*} -x-\frac {1}{20} \log ^{\frac {2}{\log (5)}}\left (e^{-x} x\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.77, size = 20, normalized size = 0.69 \begin {gather*} -x - \frac {1}{20} \, \log \left (x e^{\left (-x\right )}\right )^{\frac {2}{\log \relax (5)}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int -\frac {10 \, x \log \relax (5) \log \left (x e^{\left (-x\right )}\right ) - {\left (x - 1\right )} \log \left (x e^{\left (-x\right )}\right )^{\frac {2}{\log \relax (5)}}}{10 \, x \log \relax (5) \log \left (x e^{\left (-x\right )}\right )}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.26, size = 72, normalized size = 2.48
method | result | size |
risch | \(-x -\frac {\left (\ln \relax (x )-\ln \left ({\mathrm e}^{x}\right )-\frac {i \pi \,\mathrm {csgn}\left (i x \,{\mathrm e}^{-x}\right ) \left (-\mathrm {csgn}\left (i x \,{\mathrm e}^{-x}\right )+\mathrm {csgn}\left (i x \right )\right ) \left (-\mathrm {csgn}\left (i x \,{\mathrm e}^{-x}\right )+\mathrm {csgn}\left (i {\mathrm e}^{-x}\right )\right )}{2}\right )^{\frac {2}{\ln \relax (5)}}}{20}\) | \(72\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.48, size = 28, normalized size = 0.97 \begin {gather*} -\frac {20 \, x \log \relax (5) + {\left (-x + \log \relax (x)\right )}^{\frac {2}{\log \relax (5)}} \log \relax (5)}{20 \, \log \relax (5)} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.67, size = 19, normalized size = 0.66 \begin {gather*} -x-\frac {{\left (\ln \relax (x)-x\right )}^{\frac {2}{\ln \relax (5)}}}{20} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 2.32, size = 24, normalized size = 0.83 \begin {gather*} \frac {- x \log {\relax (5 )} - \frac {\left (- x + \log {\relax (x )}\right )^{\frac {2}{\log {\relax (5 )}}} \log {\relax (5 )}}{20}}{\log {\relax (5 )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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