Optimal. Leaf size=295 \[ -\frac {(e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} (a d (A d (1-m)+B c (m+1))-b c (A d (-m-2 p+1)+B c (m+2 p+1))) F_1\left (\frac {m+1}{2};-p,1;\frac {m+3}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )}{2 c^2 d e (m+1) (b c-a d)}-\frac {b (m+2 p+1) (e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} (B c-A d) \, _2F_1\left (\frac {m+1}{2},-p;\frac {m+3}{2};-\frac {b x^2}{a}\right )}{2 c d e (m+1) (b c-a d)}+\frac {(e x)^{m+1} \left (a+b x^2\right )^{p+1} (B c-A d)}{2 c e \left (c+d x^2\right ) (b c-a d)} \]
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Rubi [A] time = 0.41, antiderivative size = 295, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.194, Rules used = {579, 584, 365, 364, 511, 510} \[ -\frac {(e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} (a d (A d (1-m)+B c (m+1))-b c (A d (-m-2 p+1)+B c (m+2 p+1))) F_1\left (\frac {m+1}{2};-p,1;\frac {m+3}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )}{2 c^2 d e (m+1) (b c-a d)}-\frac {b (m+2 p+1) (e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} (B c-A d) \, _2F_1\left (\frac {m+1}{2},-p;\frac {m+3}{2};-\frac {b x^2}{a}\right )}{2 c d e (m+1) (b c-a d)}+\frac {(e x)^{m+1} \left (a+b x^2\right )^{p+1} (B c-A d)}{2 c e \left (c+d x^2\right ) (b c-a d)} \]
Antiderivative was successfully verified.
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Rule 364
Rule 365
Rule 510
Rule 511
Rule 579
Rule 584
Rubi steps
\begin {align*} \int \frac {(e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right )}{\left (c+d x^2\right )^2} \, dx &=\frac {(B c-A d) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{2 c (b c-a d) e \left (c+d x^2\right )}+\frac {\int \frac {(e x)^m \left (a+b x^2\right )^p \left (2 A b c-a A d (1-m)-a B c (1+m)-b (B c-A d) (1+m+2 p) x^2\right )}{c+d x^2} \, dx}{2 c (b c-a d)}\\ &=\frac {(B c-A d) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{2 c (b c-a d) e \left (c+d x^2\right )}+\frac {\int \left (-\frac {b (B c-A d) (1+m+2 p) (e x)^m \left (a+b x^2\right )^p}{d}+\frac {(d (2 A b c-a A d (1-m)-a B c (1+m))+b c (B c-A d) (1+m+2 p)) (e x)^m \left (a+b x^2\right )^p}{d \left (c+d x^2\right )}\right ) \, dx}{2 c (b c-a d)}\\ &=\frac {(B c-A d) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{2 c (b c-a d) e \left (c+d x^2\right )}-\frac {(b (B c-A d) (1+m+2 p)) \int (e x)^m \left (a+b x^2\right )^p \, dx}{2 c d (b c-a d)}-\frac {(a d (A d (1-m)+B c (1+m))-b c (A d (1-m-2 p)+B c (1+m+2 p))) \int \frac {(e x)^m \left (a+b x^2\right )^p}{c+d x^2} \, dx}{2 c d (b c-a d)}\\ &=\frac {(B c-A d) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{2 c (b c-a d) e \left (c+d x^2\right )}-\frac {\left (b (B c-A d) (1+m+2 p) \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p}\right ) \int (e x)^m \left (1+\frac {b x^2}{a}\right )^p \, dx}{2 c d (b c-a d)}-\frac {\left ((a d (A d (1-m)+B c (1+m))-b c (A d (1-m-2 p)+B c (1+m+2 p))) \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p}\right ) \int \frac {(e x)^m \left (1+\frac {b x^2}{a}\right )^p}{c+d x^2} \, dx}{2 c d (b c-a d)}\\ &=\frac {(B c-A d) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{2 c (b c-a d) e \left (c+d x^2\right )}-\frac {(a d (A d (1-m)+B c (1+m))-b c (A d (1-m-2 p)+B c (1+m+2 p))) (e x)^{1+m} \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} F_1\left (\frac {1+m}{2};-p,1;\frac {3+m}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )}{2 c^2 d (b c-a d) e (1+m)}-\frac {b (B c-A d) (1+m+2 p) (e x)^{1+m} \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} \, _2F_1\left (\frac {1+m}{2},-p;\frac {3+m}{2};-\frac {b x^2}{a}\right )}{2 c d (b c-a d) e (1+m)}\\ \end {align*}
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Mathematica [A] time = 0.25, size = 128, normalized size = 0.43 \[ \frac {x (e x)^m \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \left ((A d-B c) F_1\left (\frac {m+1}{2};-p,2;\frac {m+3}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )+B c F_1\left (\frac {m+1}{2};-p,1;\frac {m+3}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )\right )}{c^2 d (m+1)} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.98, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (B x^{2} + A\right )} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}}{d^{2} x^{4} + 2 \, c d x^{2} + c^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B x^{2} + A\right )} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}}{{\left (d x^{2} + c\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.07, size = 0, normalized size = 0.00 \[ \int \frac {\left (B \,x^{2}+A \right ) \left (e x \right )^{m} \left (b \,x^{2}+a \right )^{p}}{\left (d \,x^{2}+c \right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B x^{2} + A\right )} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}}{{\left (d x^{2} + c\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\left (B\,x^2+A\right )\,{\left (e\,x\right )}^m\,{\left (b\,x^2+a\right )}^p}{{\left (d\,x^2+c\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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