Optimal. Leaf size=1221 \[ \frac {c \tanh ^{-1}\left (\frac {a e^2+c d^2 x^2}{\sqrt {c d^4+a e^4} \sqrt {c x^4+a}}\right ) d^3}{e^3 \sqrt {c d^4+a e^4}}-\frac {\sqrt {c} \tanh ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {c x^4+a}}\right ) d}{e^3}-\frac {\sqrt {c x^4+a} d}{e \left (d^2-e^2 x^2\right )}-\frac {2 \sqrt [4]{a} \sqrt [4]{c} \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{e^2 \sqrt {c x^4+a}}+\frac {3 \sqrt [4]{a} \sqrt [4]{c} \left (\frac {\sqrt {c} d^2}{\sqrt {a}}+e^2\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 e^4 \sqrt {c x^4+a}}-\frac {\sqrt [4]{c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} e^4 \sqrt {c x^4+a}}+\frac {\sqrt [4]{c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} e^4 \sqrt {c x^4+a}}-\frac {\sqrt [4]{c} \left (c d^4+a e^4\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} e^4 \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \sqrt {c x^4+a}}+\frac {2 \sqrt {c} x \sqrt {c x^4+a}}{e^2 \left (\sqrt {c} x^2+\sqrt {a}\right )}+\frac {x \sqrt {c x^4+a}}{d^2-e^2 x^2}-\frac {\left (c d^4-a e^4\right ) \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {c x^4+a}}\right )}{2 e^3 \sqrt {-c d^4-a e^4} d}+\frac {\sqrt {-c d^4-a e^4} \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {c x^4+a}}\right )}{2 e^3 d}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right )^2 \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{c} e^4 \sqrt {c x^4+a} d^2}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (c d^4+a e^4\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{c} e^4 \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \sqrt {c x^4+a} d^2} \]
[Out]
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Rubi [A] time = 1.80, antiderivative size = 1221, normalized size of antiderivative = 1.00, number of steps used = 32, number of rules used = 15, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.790, Rules used = {2153, 1227, 1198, 220, 1196, 1217, 1707, 1248, 733, 844, 217, 206, 725, 1336, 1209} \[ \frac {c \tanh ^{-1}\left (\frac {a e^2+c d^2 x^2}{\sqrt {c d^4+a e^4} \sqrt {c x^4+a}}\right ) d^3}{e^3 \sqrt {c d^4+a e^4}}-\frac {\sqrt {c} \tanh ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {c x^4+a}}\right ) d}{e^3}-\frac {\sqrt {c x^4+a} d}{e \left (d^2-e^2 x^2\right )}-\frac {2 \sqrt [4]{a} \sqrt [4]{c} \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{e^2 \sqrt {c x^4+a}}+\frac {3 \sqrt [4]{a} \sqrt [4]{c} \left (\frac {\sqrt {c} d^2}{\sqrt {a}}+e^2\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 e^4 \sqrt {c x^4+a}}-\frac {\sqrt [4]{c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} e^4 \sqrt {c x^4+a}}+\frac {\sqrt [4]{c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} e^4 \sqrt {c x^4+a}}-\frac {\sqrt [4]{c} \left (c d^4+a e^4\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} e^4 \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \sqrt {c x^4+a}}+\frac {2 \sqrt {c} x \sqrt {c x^4+a}}{e^2 \left (\sqrt {c} x^2+\sqrt {a}\right )}+\frac {x \sqrt {c x^4+a}}{d^2-e^2 x^2}-\frac {\left (c d^4-a e^4\right ) \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {c x^4+a}}\right )}{2 e^3 \sqrt {-c d^4-a e^4} d}+\frac {\sqrt {-c d^4-a e^4} \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {c x^4+a}}\right )}{2 e^3 d}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right )^2 \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{c} e^4 \sqrt {c x^4+a} d^2}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (c d^4+a e^4\right ) \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {\frac {c x^4+a}{\left (\sqrt {c} x^2+\sqrt {a}\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{c} e^4 \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \sqrt {c x^4+a} d^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 206
Rule 217
Rule 220
Rule 725
Rule 733
Rule 844
Rule 1196
Rule 1198
Rule 1209
Rule 1217
Rule 1227
Rule 1248
Rule 1336
Rule 1707
Rule 2153
Rubi steps
\begin {align*} \int \frac {\sqrt {a+c x^4}}{(d+e x)^2} \, dx &=\int \left (\frac {d^2 \sqrt {a+c x^4}}{\left (d^2-e^2 x^2\right )^2}-\frac {2 d e x \sqrt {a+c x^4}}{\left (d^2-e^2 x^2\right )^2}+\frac {e^2 x^2 \sqrt {a+c x^4}}{\left (-d^2+e^2 x^2\right )^2}\right ) \, dx\\ &=d^2 \int \frac {\sqrt {a+c x^4}}{\left (d^2-e^2 x^2\right )^2} \, dx-(2 d e) \int \frac {x \sqrt {a+c x^4}}{\left (d^2-e^2 x^2\right )^2} \, dx+e^2 \int \frac {x^2 \sqrt {a+c x^4}}{\left (-d^2+e^2 x^2\right )^2} \, dx\\ &=\frac {x \sqrt {a+c x^4}}{2 \left (d^2-e^2 x^2\right )}+\frac {1}{2} \left (a-\frac {c d^4}{e^4}\right ) \int \frac {1}{\left (d^2-e^2 x^2\right ) \sqrt {a+c x^4}} \, dx+\frac {c \int \frac {d^2+e^2 x^2}{\sqrt {a+c x^4}} \, dx}{2 e^4}-(d e) \operatorname {Subst}\left (\int \frac {\sqrt {a+c x^2}}{\left (d^2-e^2 x\right )^2} \, dx,x,x^2\right )+e^2 \int \left (\frac {d^2 \sqrt {a+c x^4}}{e^2 \left (-d^2+e^2 x^2\right )^2}+\frac {\sqrt {a+c x^4}}{e^2 \left (-d^2+e^2 x^2\right )}\right ) \, dx\\ &=-\frac {d \sqrt {a+c x^4}}{e \left (d^2-e^2 x^2\right )}+\frac {x \sqrt {a+c x^4}}{2 \left (d^2-e^2 x^2\right )}+d^2 \int \frac {\sqrt {a+c x^4}}{\left (-d^2+e^2 x^2\right )^2} \, dx+\frac {1}{2} \left (\sqrt {a} \left (\sqrt {a}-\frac {\sqrt {c} d^2}{e^2}\right )\right ) \int \frac {1+\frac {\sqrt {c} x^2}{\sqrt {a}}}{\left (d^2-e^2 x^2\right ) \sqrt {a+c x^4}} \, dx-\frac {\left (\sqrt {a} \sqrt {c}\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx}{2 e^2}+\frac {(c d) \operatorname {Subst}\left (\int \frac {x}{\left (d^2-e^2 x\right ) \sqrt {a+c x^2}} \, dx,x,x^2\right )}{e}-\frac {\left (\sqrt {c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right )\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{2 e^4}+\frac {\left (c \left (d^2+\frac {\sqrt {a} e^2}{\sqrt {c}}\right )\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{2 e^4}+\int \frac {\sqrt {a+c x^4}}{-d^2+e^2 x^2} \, dx\\ &=\frac {\sqrt {c} x \sqrt {a+c x^4}}{2 e^2 \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {d \sqrt {a+c x^4}}{e \left (d^2-e^2 x^2\right )}+\frac {x \sqrt {a+c x^4}}{d^2-e^2 x^2}-\frac {\left (c d^4-a e^4\right ) \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {a+c x^4}}\right )}{4 d e^3 \sqrt {-c d^4-a e^4}}-\frac {\sqrt [4]{a} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 e^2 \sqrt {a+c x^4}}-\frac {\sqrt [4]{c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} e^4 \sqrt {a+c x^4}}+\frac {\sqrt [4]{c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} e^4 \sqrt {a+c x^4}}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right )^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{8 \sqrt [4]{a} \sqrt [4]{c} d^2 e^4 \sqrt {a+c x^4}}+\frac {1}{2} \left (-a+\frac {c d^4}{e^4}\right ) \int \frac {1}{\left (-d^2+e^2 x^2\right ) \sqrt {a+c x^4}} \, dx+\left (a+\frac {c d^4}{e^4}\right ) \int \frac {1}{\left (-d^2+e^2 x^2\right ) \sqrt {a+c x^4}} \, dx-\frac {\int \frac {-c d^2-c e^2 x^2}{\sqrt {a+c x^4}} \, dx}{e^4}-\frac {c \int \frac {-d^2-e^2 x^2}{\sqrt {a+c x^4}} \, dx}{2 e^4}-\frac {(c d) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+c x^2}} \, dx,x,x^2\right )}{e^3}+\frac {\left (c d^3\right ) \operatorname {Subst}\left (\int \frac {1}{\left (d^2-e^2 x\right ) \sqrt {a+c x^2}} \, dx,x,x^2\right )}{e^3}\\ &=\frac {\sqrt {c} x \sqrt {a+c x^4}}{2 e^2 \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {d \sqrt {a+c x^4}}{e \left (d^2-e^2 x^2\right )}+\frac {x \sqrt {a+c x^4}}{d^2-e^2 x^2}-\frac {\left (c d^4-a e^4\right ) \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {a+c x^4}}\right )}{4 d e^3 \sqrt {-c d^4-a e^4}}-\frac {\sqrt [4]{a} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 e^2 \sqrt {a+c x^4}}-\frac {\sqrt [4]{c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} e^4 \sqrt {a+c x^4}}+\frac {\sqrt [4]{c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} e^4 \sqrt {a+c x^4}}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right )^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{8 \sqrt [4]{a} \sqrt [4]{c} d^2 e^4 \sqrt {a+c x^4}}-\frac {1}{2} \left (\sqrt {a} \left (\sqrt {a}-\frac {\sqrt {c} d^2}{e^2}\right )\right ) \int \frac {1+\frac {\sqrt {c} x^2}{\sqrt {a}}}{\left (-d^2+e^2 x^2\right ) \sqrt {a+c x^4}} \, dx-\frac {(c d) \operatorname {Subst}\left (\int \frac {1}{1-c x^2} \, dx,x,\frac {x^2}{\sqrt {a+c x^4}}\right )}{e^3}-\frac {\left (c d^3\right ) \operatorname {Subst}\left (\int \frac {1}{c d^4+a e^4-x^2} \, dx,x,\frac {-a e^2-c d^2 x^2}{\sqrt {a+c x^4}}\right )}{e^3}-\frac {\left (\sqrt {a} \sqrt {c}\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx}{2 e^2}-\frac {\left (\sqrt {a} \sqrt {c}\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx}{e^2}-\frac {\left (\sqrt {c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right )\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{2 e^4}-\frac {\left (\sqrt {c} \left (a+\frac {c d^4}{e^4}\right )\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{\sqrt {c} d^2+\sqrt {a} e^2}+\frac {\left (\sqrt {a} \left (a+\frac {c d^4}{e^4}\right ) e^2\right ) \int \frac {1+\frac {\sqrt {c} x^2}{\sqrt {a}}}{\left (-d^2+e^2 x^2\right ) \sqrt {a+c x^4}} \, dx}{\sqrt {c} d^2+\sqrt {a} e^2}+\frac {\left (\sqrt {c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right )\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{2 e^4}+\frac {\left (\sqrt {c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right )\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx}{e^4}\\ &=\frac {2 \sqrt {c} x \sqrt {a+c x^4}}{e^2 \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {d \sqrt {a+c x^4}}{e \left (d^2-e^2 x^2\right )}+\frac {x \sqrt {a+c x^4}}{d^2-e^2 x^2}+\frac {\sqrt {-c d^4-a e^4} \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {a+c x^4}}\right )}{2 d e^3}-\frac {\left (c d^4-a e^4\right ) \tan ^{-1}\left (\frac {\sqrt {-c d^4-a e^4} x}{d e \sqrt {a+c x^4}}\right )}{2 d e^3 \sqrt {-c d^4-a e^4}}-\frac {\sqrt {c} d \tanh ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {a+c x^4}}\right )}{e^3}+\frac {c d^3 \tanh ^{-1}\left (\frac {a e^2+c d^2 x^2}{\sqrt {c d^4+a e^4} \sqrt {a+c x^4}}\right )}{e^3 \sqrt {c d^4+a e^4}}-\frac {2 \sqrt [4]{a} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{e^2 \sqrt {a+c x^4}}-\frac {\sqrt [4]{c} \left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} e^4 \sqrt {a+c x^4}}-\frac {\sqrt [4]{c} \left (a+\frac {c d^4}{e^4}\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \sqrt {a+c x^4}}+\frac {\sqrt [4]{c} \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{\sqrt [4]{a} e^4 \sqrt {a+c x^4}}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right )^2 \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{c} d^2 e^4 \sqrt {a+c x^4}}+\frac {\left (\sqrt {c} d^2-\sqrt {a} e^2\right ) \left (c d^4+a e^4\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \Pi \left (\frac {\left (\sqrt {c} d^2+\sqrt {a} e^2\right )^2}{4 \sqrt {a} \sqrt {c} d^2 e^2};2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{c} d^2 e^4 \left (\sqrt {c} d^2+\sqrt {a} e^2\right ) \sqrt {a+c x^4}}\\ \end {align*}
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Mathematica [C] time = 1.93, size = 382, normalized size = 0.31 \[ \frac {2 \sqrt [4]{-1} \sqrt [4]{a} c^{3/4} d^2 \sqrt {\frac {c x^4}{a}+1} \Pi \left (\frac {i \sqrt {a} e^2}{\sqrt {c} d^2};\left .\sin ^{-1}\left (\frac {(-1)^{3/4} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )\right |-1\right )-\frac {2 \sqrt {c} \sqrt {\frac {c x^4}{a}+1} \left (\sqrt {a} e^2+i \sqrt {c} d^2\right ) F\left (\left .i \sinh ^{-1}\left (\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}} x\right )\right |-1\right )}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}}-\frac {c d^3 e \sqrt {a+c x^4} \tanh ^{-1}\left (\frac {-a e^2-c d^2 x^2}{\sqrt {a+c x^4} \sqrt {a e^4+c d^4}}\right )}{\sqrt {a e^4+c d^4}}-\frac {e^3 \left (a+c x^4\right )}{d+e x}-\sqrt {c} d e \sqrt {a+c x^4} \tanh ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {a+c x^4}}\right )-2 i a e^2 \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}} \sqrt {\frac {c x^4}{a}+1} E\left (\left .i \sinh ^{-1}\left (\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}} x\right )\right |-1\right )}{e^4 \sqrt {a+c x^4}} \]
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {c x^{4} + a}}{{\left (e x + d\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.03, size = 402, normalized size = 0.33 \[ \frac {c \,d^{3} \arctanh \left (\frac {\frac {2 c \,d^{2} x^{2}}{e^{2}}+2 a}{2 \sqrt {a +\frac {c \,d^{4}}{e^{4}}}\, \sqrt {c \,x^{4}+a}}\right )}{\sqrt {a +\frac {c \,d^{4}}{e^{4}}}\, e^{5}}+\frac {2 \sqrt {-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}+1}\, \sqrt {\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}+1}\, c \,d^{2} \EllipticF \left (\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, x , i\right )}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}\, e^{4}}-\frac {2 \sqrt {-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}+1}\, \sqrt {\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}+1}\, c \,d^{2} \EllipticPi \left (\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, x , -\frac {i \sqrt {a}\, e^{2}}{\sqrt {c}\, d^{2}}, \frac {\sqrt {-\frac {i \sqrt {c}}{\sqrt {a}}}}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}}\right )}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}\, e^{4}}-\frac {\sqrt {c}\, d \ln \left (2 \sqrt {c}\, x^{2}+2 \sqrt {c \,x^{4}+a}\right )}{e^{3}}+\frac {2 i \sqrt {-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}+1}\, \sqrt {\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}+1}\, \left (-\EllipticE \left (\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, x , i\right )+\EllipticF \left (\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, x , i\right )\right ) \sqrt {a}\, \sqrt {c}}{\sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {c \,x^{4}+a}\, e^{2}}-\frac {\sqrt {c \,x^{4}+a}}{\left (e x +d \right ) e} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {c x^{4} + a}}{{\left (e x + d\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\sqrt {c\,x^4+a}}{{\left (d+e\,x\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {a + c x^{4}}}{\left (d + e x\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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