3.122 \(\int \frac {f^{a+\frac {b}{x}}}{x^2} \, dx\)

Optimal. Leaf size=18 \[ -\frac {f^{a+\frac {b}{x}}}{b \log (f)} \]

[Out]

-f^(a+b/x)/b/ln(f)

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Rubi [A]  time = 0.02, antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {2209} \[ -\frac {f^{a+\frac {b}{x}}}{b \log (f)} \]

Antiderivative was successfully verified.

[In]

Int[f^(a + b/x)/x^2,x]

[Out]

-(f^(a + b/x)/(b*Log[f]))

Rule 2209

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Simp[((e + f*x)^n*
F^(a + b*(c + d*x)^n))/(b*f*n*(c + d*x)^n*Log[F]), x] /; FreeQ[{F, a, b, c, d, e, f, n}, x] && EqQ[m, n - 1] &
& EqQ[d*e - c*f, 0]

Rubi steps

\begin {align*} \int \frac {f^{a+\frac {b}{x}}}{x^2} \, dx &=-\frac {f^{a+\frac {b}{x}}}{b \log (f)}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 18, normalized size = 1.00 \[ -\frac {f^{a+\frac {b}{x}}}{b \log (f)} \]

Antiderivative was successfully verified.

[In]

Integrate[f^(a + b/x)/x^2,x]

[Out]

-(f^(a + b/x)/(b*Log[f]))

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fricas [A]  time = 0.41, size = 20, normalized size = 1.11 \[ -\frac {f^{\frac {a x + b}{x}}}{b \log \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(a+b/x)/x^2,x, algorithm="fricas")

[Out]

-f^((a*x + b)/x)/(b*log(f))

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giac [A]  time = 0.18, size = 20, normalized size = 1.11 \[ -\frac {f^{\frac {a x + b}{x}}}{b \log \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(a+b/x)/x^2,x, algorithm="giac")

[Out]

-f^((a*x + b)/x)/(b*log(f))

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maple [A]  time = 0.00, size = 19, normalized size = 1.06 \[ -\frac {f^{a +\frac {b}{x}}}{b \ln \relax (f )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(a+b/x)/x^2,x)

[Out]

-f^(a+b/x)/b/ln(f)

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maxima [A]  time = 1.06, size = 18, normalized size = 1.00 \[ -\frac {f^{a + \frac {b}{x}}}{b \log \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(a+b/x)/x^2,x, algorithm="maxima")

[Out]

-f^(a + b/x)/(b*log(f))

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mupad [B]  time = 3.52, size = 18, normalized size = 1.00 \[ -\frac {f^{a+\frac {b}{x}}}{b\,\ln \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(a + b/x)/x^2,x)

[Out]

-f^(a + b/x)/(b*log(f))

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sympy [A]  time = 0.12, size = 20, normalized size = 1.11 \[ \begin {cases} - \frac {f^{a + \frac {b}{x}}}{b \log {\relax (f )}} & \text {for}\: b \log {\relax (f )} \neq 0 \\- \frac {1}{x} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f**(a+b/x)/x**2,x)

[Out]

Piecewise((-f**(a + b/x)/(b*log(f)), Ne(b*log(f), 0)), (-1/x, True))

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