3.188 \(\int f^{a+b x^n} x^{-1-2 n} \, dx\)

Optimal. Leaf size=71 \[ \frac {b^2 f^a \log ^2(f) \text {Ei}\left (b x^n \log (f)\right )}{2 n}-\frac {x^{-2 n} f^{a+b x^n}}{2 n}-\frac {b \log (f) x^{-n} f^{a+b x^n}}{2 n} \]

[Out]

-1/2*f^(a+b*x^n)/n/(x^(2*n))-1/2*b*f^(a+b*x^n)*ln(f)/n/(x^n)+1/2*b^2*f^a*Ei(b*x^n*ln(f))*ln(f)^2/n

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Rubi [A]  time = 0.08, antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {2215, 2210} \[ \frac {b^2 f^a \log ^2(f) \text {Ei}\left (b x^n \log (f)\right )}{2 n}-\frac {x^{-2 n} f^{a+b x^n}}{2 n}-\frac {b \log (f) x^{-n} f^{a+b x^n}}{2 n} \]

Antiderivative was successfully verified.

[In]

Int[f^(a + b*x^n)*x^(-1 - 2*n),x]

[Out]

-f^(a + b*x^n)/(2*n*x^(2*n)) - (b*f^(a + b*x^n)*Log[f])/(2*n*x^n) + (b^2*f^a*ExpIntegralEi[b*x^n*Log[f]]*Log[f
]^2)/(2*n)

Rule 2210

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> Simp[(F^a*ExpIntegralEi[
b*(c + d*x)^n*Log[F]])/(f*n), x] /; FreeQ[{F, a, b, c, d, e, f, n}, x] && EqQ[d*e - c*f, 0]

Rule 2215

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m
+ 1)*F^(a + b*(c + d*x)^n))/(d*(m + 1)), x] - Dist[(b*n*Log[F])/(m + 1), Int[(c + d*x)^Simplify[m + n]*F^(a +
b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d, m, n}, x] && IntegerQ[2*Simplify[(m + 1)/n]] && LtQ[-4, Simpl
ify[(m + 1)/n], 5] &&  !RationalQ[m] && SumSimplerQ[m, n]

Rubi steps

\begin {align*} \int f^{a+b x^n} x^{-1-2 n} \, dx &=-\frac {f^{a+b x^n} x^{-2 n}}{2 n}+\frac {1}{2} (b \log (f)) \int f^{a+b x^n} x^{-1-n} \, dx\\ &=-\frac {f^{a+b x^n} x^{-2 n}}{2 n}-\frac {b f^{a+b x^n} x^{-n} \log (f)}{2 n}+\frac {1}{2} \left (b^2 \log ^2(f)\right ) \int \frac {f^{a+b x^n}}{x} \, dx\\ &=-\frac {f^{a+b x^n} x^{-2 n}}{2 n}-\frac {b f^{a+b x^n} x^{-n} \log (f)}{2 n}+\frac {b^2 f^a \text {Ei}\left (b x^n \log (f)\right ) \log ^2(f)}{2 n}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 25, normalized size = 0.35 \[ -\frac {b^2 f^a \log ^2(f) \Gamma \left (-2,-b x^n \log (f)\right )}{n} \]

Antiderivative was successfully verified.

[In]

Integrate[f^(a + b*x^n)*x^(-1 - 2*n),x]

[Out]

-((b^2*f^a*Gamma[-2, -(b*x^n*Log[f])]*Log[f]^2)/n)

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fricas [A]  time = 0.41, size = 61, normalized size = 0.86 \[ \frac {b^{2} f^{a} x^{2 \, n} {\rm Ei}\left (b x^{n} \log \relax (f)\right ) \log \relax (f)^{2} - {\left (b x^{n} \log \relax (f) + 1\right )} e^{\left (b x^{n} \log \relax (f) + a \log \relax (f)\right )}}{2 \, n x^{2 \, n}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(a+b*x^n)*x^(-1-2*n),x, algorithm="fricas")

[Out]

1/2*(b^2*f^a*x^(2*n)*Ei(b*x^n*log(f))*log(f)^2 - (b*x^n*log(f) + 1)*e^(b*x^n*log(f) + a*log(f)))/(n*x^(2*n))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int f^{b x^{n} + a} x^{-2 \, n - 1}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(a+b*x^n)*x^(-1-2*n),x, algorithm="giac")

[Out]

integrate(f^(b*x^n + a)*x^(-2*n - 1), x)

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maple [A]  time = 0.13, size = 70, normalized size = 0.99 \[ -\frac {b^{2} f^{a} \Ei \left (1, -b \,x^{n} \ln \relax (f )\right ) \ln \relax (f )^{2}}{2 n}-\frac {b \,f^{a} f^{b \,x^{n}} x^{-n} \ln \relax (f )}{2 n}-\frac {f^{a} f^{b \,x^{n}} x^{-2 n}}{2 n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(b*x^n+a)*x^(-1-2*n),x)

[Out]

-1/2/n*f^(b*x^n)*f^a/(x^n)^2-1/2/n*ln(f)*b*f^(b*x^n)*f^a/(x^n)-1/2/n*ln(f)^2*b^2*f^a*Ei(1,-b*x^n*ln(f))

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maxima [A]  time = 1.01, size = 25, normalized size = 0.35 \[ -\frac {b^{2} f^{a} \Gamma \left (-2, -b x^{n} \log \relax (f)\right ) \log \relax (f)^{2}}{n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(a+b*x^n)*x^(-1-2*n),x, algorithm="maxima")

[Out]

-b^2*f^a*gamma(-2, -b*x^n*log(f))*log(f)^2/n

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {f^{a+b\,x^n}}{x^{2\,n+1}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(a + b*x^n)/x^(2*n + 1),x)

[Out]

int(f^(a + b*x^n)/x^(2*n + 1), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f**(a+b*x**n)*x**(-1-2*n),x)

[Out]

Timed out

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