Optimal. Leaf size=49 \[ \frac {F^a \Gamma \left (\frac {13}{2},-\frac {b \log (F)}{(c+d x)^2}\right )}{2 d (c+d x)^{13} \left (-\frac {b \log (F)}{(c+d x)^2}\right )^{13/2}} \]
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Rubi [A] time = 0.05, antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2218} \[ \frac {F^a \text {Gamma}\left (\frac {13}{2},-\frac {b \log (F)}{(c+d x)^2}\right )}{2 d (c+d x)^{13} \left (-\frac {b \log (F)}{(c+d x)^2}\right )^{13/2}} \]
Antiderivative was successfully verified.
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Rule 2218
Rubi steps
\begin {align*} \int \frac {F^{a+\frac {b}{(c+d x)^2}}}{(c+d x)^{14}} \, dx &=\frac {F^a \Gamma \left (\frac {13}{2},-\frac {b \log (F)}{(c+d x)^2}\right )}{2 d (c+d x)^{13} \left (-\frac {b \log (F)}{(c+d x)^2}\right )^{13/2}}\\ \end {align*}
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Mathematica [A] time = 0.03, size = 49, normalized size = 1.00 \[ \frac {F^a \Gamma \left (\frac {13}{2},-\frac {b \log (F)}{(c+d x)^2}\right )}{2 d (c+d x)^{13} \left (-\frac {b \log (F)}{(c+d x)^2}\right )^{13/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.50, size = 791, normalized size = 16.14 \[ \frac {10395 \, \sqrt {\pi } {\left (d^{12} x^{11} + 11 \, c d^{11} x^{10} + 55 \, c^{2} d^{10} x^{9} + 165 \, c^{3} d^{9} x^{8} + 330 \, c^{4} d^{8} x^{7} + 462 \, c^{5} d^{7} x^{6} + 462 \, c^{6} d^{6} x^{5} + 330 \, c^{7} d^{5} x^{4} + 165 \, c^{8} d^{4} x^{3} + 55 \, c^{9} d^{3} x^{2} + 11 \, c^{10} d^{2} x + c^{11} d\right )} F^{a} \sqrt {-\frac {b \log \relax (F)}{d^{2}}} \operatorname {erf}\left (\frac {d \sqrt {-\frac {b \log \relax (F)}{d^{2}}}}{d x + c}\right ) - 2 \, {\left (32 \, b^{6} \log \relax (F)^{6} - 176 \, {\left (b^{5} d^{2} x^{2} + 2 \, b^{5} c d x + b^{5} c^{2}\right )} \log \relax (F)^{5} + 792 \, {\left (b^{4} d^{4} x^{4} + 4 \, b^{4} c d^{3} x^{3} + 6 \, b^{4} c^{2} d^{2} x^{2} + 4 \, b^{4} c^{3} d x + b^{4} c^{4}\right )} \log \relax (F)^{4} - 2772 \, {\left (b^{3} d^{6} x^{6} + 6 \, b^{3} c d^{5} x^{5} + 15 \, b^{3} c^{2} d^{4} x^{4} + 20 \, b^{3} c^{3} d^{3} x^{3} + 15 \, b^{3} c^{4} d^{2} x^{2} + 6 \, b^{3} c^{5} d x + b^{3} c^{6}\right )} \log \relax (F)^{3} + 6930 \, {\left (b^{2} d^{8} x^{8} + 8 \, b^{2} c d^{7} x^{7} + 28 \, b^{2} c^{2} d^{6} x^{6} + 56 \, b^{2} c^{3} d^{5} x^{5} + 70 \, b^{2} c^{4} d^{4} x^{4} + 56 \, b^{2} c^{5} d^{3} x^{3} + 28 \, b^{2} c^{6} d^{2} x^{2} + 8 \, b^{2} c^{7} d x + b^{2} c^{8}\right )} \log \relax (F)^{2} - 10395 \, {\left (b d^{10} x^{10} + 10 \, b c d^{9} x^{9} + 45 \, b c^{2} d^{8} x^{8} + 120 \, b c^{3} d^{7} x^{7} + 210 \, b c^{4} d^{6} x^{6} + 252 \, b c^{5} d^{5} x^{5} + 210 \, b c^{6} d^{4} x^{4} + 120 \, b c^{7} d^{3} x^{3} + 45 \, b c^{8} d^{2} x^{2} + 10 \, b c^{9} d x + b c^{10}\right )} \log \relax (F)\right )} F^{\frac {a d^{2} x^{2} + 2 \, a c d x + a c^{2} + b}{d^{2} x^{2} + 2 \, c d x + c^{2}}}}{128 \, {\left (b^{7} d^{12} x^{11} + 11 \, b^{7} c d^{11} x^{10} + 55 \, b^{7} c^{2} d^{10} x^{9} + 165 \, b^{7} c^{3} d^{9} x^{8} + 330 \, b^{7} c^{4} d^{8} x^{7} + 462 \, b^{7} c^{5} d^{7} x^{6} + 462 \, b^{7} c^{6} d^{6} x^{5} + 330 \, b^{7} c^{7} d^{5} x^{4} + 165 \, b^{7} c^{8} d^{4} x^{3} + 55 \, b^{7} c^{9} d^{3} x^{2} + 11 \, b^{7} c^{10} d^{2} x + b^{7} c^{11} d\right )} \log \relax (F)^{7}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {F^{a + \frac {b}{{\left (d x + c\right )}^{2}}}}{{\left (d x + c\right )}^{14}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.36, size = 241, normalized size = 4.92 \[ -\frac {F^{a} F^{\frac {b}{\left (d x +c \right )^{2}}}}{2 \left (d x +c \right )^{11} b d \ln \relax (F )}+\frac {11 F^{a} F^{\frac {b}{\left (d x +c \right )^{2}}}}{4 \left (d x +c \right )^{9} b^{2} d \ln \relax (F )^{2}}-\frac {99 F^{a} F^{\frac {b}{\left (d x +c \right )^{2}}}}{8 \left (d x +c \right )^{7} b^{3} d \ln \relax (F )^{3}}+\frac {693 F^{a} F^{\frac {b}{\left (d x +c \right )^{2}}}}{16 \left (d x +c \right )^{5} b^{4} d \ln \relax (F )^{4}}-\frac {3465 F^{a} F^{\frac {b}{\left (d x +c \right )^{2}}}}{32 \left (d x +c \right )^{3} b^{5} d \ln \relax (F )^{5}}+\frac {10395 F^{a} F^{\frac {b}{\left (d x +c \right )^{2}}}}{64 \left (d x +c \right ) b^{6} d \ln \relax (F )^{6}}-\frac {10395 \sqrt {\pi }\, F^{a} \erf \left (\frac {\sqrt {-b \ln \relax (F )}}{d x +c}\right )}{128 \sqrt {-b \ln \relax (F )}\, b^{6} d \ln \relax (F )^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {F^{a + \frac {b}{{\left (d x + c\right )}^{2}}}}{{\left (d x + c\right )}^{14}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.08, size = 217, normalized size = 4.43 \[ -\frac {\frac {F^a\,\left (\frac {10395\,\sqrt {\pi }\,\mathrm {erfi}\left (\frac {b\,\ln \relax (F)}{\sqrt {b\,\ln \relax (F)}\,\left (c+d\,x\right )}\right )}{128}-\frac {10395\,F^{\frac {b}{{\left (c+d\,x\right )}^2}}\,\sqrt {b\,\ln \relax (F)}}{64\,\left (c+d\,x\right )}\right )}{\sqrt {b\,\ln \relax (F)}}-\frac {693\,F^{a+\frac {b}{{\left (c+d\,x\right )}^2}}\,b^2\,{\ln \relax (F)}^2}{16\,{\left (c+d\,x\right )}^5}+\frac {99\,F^{a+\frac {b}{{\left (c+d\,x\right )}^2}}\,b^3\,{\ln \relax (F)}^3}{8\,{\left (c+d\,x\right )}^7}-\frac {11\,F^{a+\frac {b}{{\left (c+d\,x\right )}^2}}\,b^4\,{\ln \relax (F)}^4}{4\,{\left (c+d\,x\right )}^9}+\frac {F^{a+\frac {b}{{\left (c+d\,x\right )}^2}}\,b^5\,{\ln \relax (F)}^5}{2\,{\left (c+d\,x\right )}^{11}}+\frac {3465\,F^{a+\frac {b}{{\left (c+d\,x\right )}^2}}\,b\,\ln \relax (F)}{32\,{\left (c+d\,x\right )}^3}}{b^6\,d\,{\ln \relax (F)}^6} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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