Optimal. Leaf size=95 \[ \frac {(b d-2 a e) \tanh ^{-1}\left (\frac {b+2 c e^{h+i x}}{\sqrt {b^2-4 a c}}\right )}{a i \sqrt {b^2-4 a c}}-\frac {d \log \left (a+b e^{h+i x}+c e^{2 h+2 i x}\right )}{2 a i}+\frac {d x}{a} \]
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Rubi [A] time = 0.15, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 37, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.162, Rules used = {2282, 800, 634, 618, 206, 628} \[ \frac {(b d-2 a e) \tanh ^{-1}\left (\frac {b+2 c e^{h+i x}}{\sqrt {b^2-4 a c}}\right )}{a i \sqrt {b^2-4 a c}}-\frac {d \log \left (a+b e^{h+i x}+c e^{2 h+2 i x}\right )}{2 a i}+\frac {d x}{a} \]
Antiderivative was successfully verified.
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Rule 206
Rule 618
Rule 628
Rule 634
Rule 800
Rule 2282
Rubi steps
\begin {align*} \int \frac {d+e e^{h+575 x}}{a+b e^{h+575 x}+c e^{2 h+1150 x}} \, dx &=\frac {1}{575} \operatorname {Subst}\left (\int \frac {d+e x}{x \left (a+b x+c x^2\right )} \, dx,x,e^{h+575 x}\right )\\ &=\frac {1}{575} \operatorname {Subst}\left (\int \left (\frac {d}{a x}+\frac {-b d+a e-c d x}{a \left (a+b x+c x^2\right )}\right ) \, dx,x,e^{h+575 x}\right )\\ &=\frac {d x}{a}+\frac {\operatorname {Subst}\left (\int \frac {-b d+a e-c d x}{a+b x+c x^2} \, dx,x,e^{h+575 x}\right )}{575 a}\\ &=\frac {d x}{a}-\frac {d \operatorname {Subst}\left (\int \frac {b+2 c x}{a+b x+c x^2} \, dx,x,e^{h+575 x}\right )}{1150 a}-\frac {(b d-2 a e) \operatorname {Subst}\left (\int \frac {1}{a+b x+c x^2} \, dx,x,e^{h+575 x}\right )}{1150 a}\\ &=\frac {d x}{a}-\frac {d \log \left (a+b e^{h+575 x}+c e^{2 h+1150 x}\right )}{1150 a}+\frac {(b d-2 a e) \operatorname {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c e^{h+575 x}\right )}{575 a}\\ &=\frac {d x}{a}+\frac {(b d-2 a e) \tanh ^{-1}\left (\frac {b+2 c e^{h+575 x}}{\sqrt {b^2-4 a c}}\right )}{575 a \sqrt {b^2-4 a c}}-\frac {d \log \left (a+b e^{h+575 x}+c e^{2 h+1150 x}\right )}{1150 a}\\ \end {align*}
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Mathematica [A] time = 0.17, size = 94, normalized size = 0.99 \[ -\frac {\frac {2 (b d-2 a e) \tan ^{-1}\left (\frac {b+2 c e^{h+i x}}{\sqrt {4 a c-b^2}}\right )}{i \sqrt {4 a c-b^2}}+\frac {d \log \left (a+e^{h+i x} \left (b+c e^{h+i x}\right )\right )}{i}-2 d x}{2 a} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.45, size = 291, normalized size = 3.06 \[ \left [\frac {2 \, {\left (b^{2} - 4 \, a c\right )} d i x - {\left (b^{2} - 4 \, a c\right )} d \log \left (c e^{\left (2 \, i x + 2 \, h\right )} + b e^{\left (i x + h\right )} + a\right ) - \sqrt {b^{2} - 4 \, a c} {\left (b d - 2 \, a e\right )} \log \left (\frac {2 \, c^{2} e^{\left (2 \, i x + 2 \, h\right )} + 2 \, b c e^{\left (i x + h\right )} + b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} {\left (2 \, c e^{\left (i x + h\right )} + b\right )}}{c e^{\left (2 \, i x + 2 \, h\right )} + b e^{\left (i x + h\right )} + a}\right )}{2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} i}, \frac {2 \, {\left (b^{2} - 4 \, a c\right )} d i x - {\left (b^{2} - 4 \, a c\right )} d \log \left (c e^{\left (2 \, i x + 2 \, h\right )} + b e^{\left (i x + h\right )} + a\right ) + 2 \, \sqrt {-b^{2} + 4 \, a c} {\left (b d - 2 \, a e\right )} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, c e^{\left (i x + h\right )} + b\right )}}{b^{2} - 4 \, a c}\right )}{2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} i}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.26, size = 127, normalized size = 1.34 \[ \frac {1}{2} \, {\left (\frac {2 \, {\left (b d e^{\left (3 \, h\right )} - 2 \, a e^{\left (3 \, h + 1\right )}\right )} \arctan \left (\frac {{\left (2 \, c e^{\left (i x + 4 \, h\right )} + b e^{\left (3 \, h\right )}\right )} e^{\left (-3 \, h\right )}}{\sqrt {-b^{2} + 4 \, a c}}\right ) e^{\left (-3 \, h\right )}}{\sqrt {-b^{2} + 4 \, a c} a} + \frac {d \log \left (c e^{\left (2 \, i x + 8 \, h\right )} + b e^{\left (i x + 7 \, h\right )} + a e^{\left (6 \, h\right )}\right )}{a} - \frac {2 \, d \log \left (e^{\left (i x + 4 \, h\right )}\right )}{a}\right )} i \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 183, normalized size = 1.93 \[ -\frac {b d \arctan \left (\frac {2 c \,{\mathrm e}^{i x} {\mathrm e}^{2 h}+b \,{\mathrm e}^{h}}{\sqrt {4 a c \,{\mathrm e}^{2 h}-b^{2} {\mathrm e}^{2 h}}}\right ) {\mathrm e}^{h}}{\sqrt {4 a c \,{\mathrm e}^{2 h}-b^{2} {\mathrm e}^{2 h}}\, a i}+\frac {2 e \arctan \left (\frac {2 c \,{\mathrm e}^{i x} {\mathrm e}^{2 h}+b \,{\mathrm e}^{h}}{\sqrt {4 a c \,{\mathrm e}^{2 h}-b^{2} {\mathrm e}^{2 h}}}\right ) {\mathrm e}^{h}}{\sqrt {4 a c \,{\mathrm e}^{2 h}-b^{2} {\mathrm e}^{2 h}}\, i}-\frac {d \ln \left (b \,{\mathrm e}^{h} {\mathrm e}^{i x}+c \,{\mathrm e}^{2 h} {\mathrm e}^{2 i x}+a \right )}{2 a i}+\frac {d \ln \left ({\mathrm e}^{i x}\right )}{a i} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.78, size = 91, normalized size = 0.96 \[ \frac {d\,x}{a}-\frac {d\,\ln \left (a+b\,{\mathrm {e}}^{i\,x}\,{\mathrm {e}}^h+c\,{\mathrm {e}}^{2\,h}\,{\mathrm {e}}^{2\,i\,x}\right )}{2\,a\,i}+\frac {\mathrm {atan}\left (\frac {b+2\,c\,{\mathrm {e}}^{i\,x}\,{\mathrm {e}}^h}{\sqrt {4\,a\,c-b^2}}\right )\,\left (2\,a\,e-b\,d\right )}{a\,i\,\sqrt {4\,a\,c-b^2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.03, size = 116, normalized size = 1.22 \[ \operatorname {RootSum} {\left (z^{2} \left (4 a^{2} c i^{2} - a b^{2} i^{2}\right ) + z \left (4 a c d i - b^{2} d i\right ) + a e^{2} - b d e + c d^{2}, \left (i \mapsto i \log {\left (e^{h + i x} + \frac {4 i a^{2} c i - i a b^{2} i + a b e + 2 a c d - b^{2} d}{2 a c e - b c d} \right )} \right )\right )} + \frac {d x}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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