Optimal. Leaf size=133 \[ \frac {\sqrt {\pi } g^2 (d+e x)^3 \left (c (d+e x)^n\right )^{-3/n} \exp \left (-\frac {3 (4 a b f n \log (F)+3)}{4 b^2 f n^2 \log (F)}\right ) \text {erfi}\left (\frac {2 a b f \log (F)+2 b^2 f \log (F) \log \left (c (d+e x)^n\right )+\frac {3}{n}}{2 b \sqrt {f} \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}} \]
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Rubi [A] time = 0.41, antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {12, 2278, 2274, 15, 2276, 2234, 2204} \[ \frac {\sqrt {\pi } g^2 (d+e x)^3 \left (c (d+e x)^n\right )^{-3/n} \exp \left (-\frac {3 (4 a b f n \log (F)+3)}{4 b^2 f n^2 \log (F)}\right ) \text {Erfi}\left (\frac {2 a b f \log (F)+2 b^2 f \log (F) \log \left (c (d+e x)^n\right )+\frac {3}{n}}{2 b \sqrt {f} \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}} \]
Antiderivative was successfully verified.
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Rule 12
Rule 15
Rule 2204
Rule 2234
Rule 2274
Rule 2276
Rule 2278
Rubi steps
\begin {align*} \int F^{f \left (a+b \log \left (c (d+e x)^n\right )\right )^2} (d g+e g x)^2 \, dx &=\frac {\operatorname {Subst}\left (\int F^{f \left (a+b \log \left (c x^n\right )\right )^2} g^2 x^2 \, dx,x,d+e x\right )}{e}\\ &=\frac {g^2 \operatorname {Subst}\left (\int F^{f \left (a+b \log \left (c x^n\right )\right )^2} x^2 \, dx,x,d+e x\right )}{e}\\ &=\frac {g^2 \operatorname {Subst}\left (\int F^{a^2 f+2 a b f \log \left (c x^n\right )+b^2 f \log ^2\left (c x^n\right )} x^2 \, dx,x,d+e x\right )}{e}\\ &=\frac {g^2 \operatorname {Subst}\left (\int F^{a^2 f+b^2 f \log ^2\left (c x^n\right )} x^2 \left (c x^n\right )^{2 a b f \log (F)} \, dx,x,d+e x\right )}{e}\\ &=\frac {\left (g^2 (d+e x)^{-2 a b f n \log (F)} \left (c (d+e x)^n\right )^{2 a b f \log (F)}\right ) \operatorname {Subst}\left (\int F^{a^2 f+b^2 f \log ^2\left (c x^n\right )} x^{2+2 a b f n \log (F)} \, dx,x,d+e x\right )}{e}\\ &=\frac {\left (g^2 (d+e x)^3 \left (c (d+e x)^n\right )^{2 a b f \log (F)-\frac {3+2 a b f n \log (F)}{n}}\right ) \operatorname {Subst}\left (\int \exp \left (a^2 f \log (F)+b^2 f x^2 \log (F)+\frac {x (3+2 a b f n \log (F))}{n}\right ) \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e n}\\ &=\frac {\left (\exp \left (a^2 f \log (F)-\frac {(3+2 a b f n \log (F))^2}{4 b^2 f n^2 \log (F)}\right ) g^2 (d+e x)^3 \left (c (d+e x)^n\right )^{2 a b f \log (F)-\frac {3+2 a b f n \log (F)}{n}}\right ) \operatorname {Subst}\left (\int \exp \left (\frac {\left (2 b^2 f x \log (F)+\frac {3+2 a b f n \log (F)}{n}\right )^2}{4 b^2 f \log (F)}\right ) \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e n}\\ &=\frac {\exp \left (-\frac {3 (3+4 a b f n \log (F))}{4 b^2 f n^2 \log (F)}\right ) g^2 \sqrt {\pi } (d+e x)^3 \left (c (d+e x)^n\right )^{-3/n} \text {erfi}\left (\frac {\frac {3}{n}+2 a b f \log (F)+2 b^2 f \log (F) \log \left (c (d+e x)^n\right )}{2 b \sqrt {f} \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}}\\ \end {align*}
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Mathematica [A] time = 0.36, size = 129, normalized size = 0.97 \[ \frac {\sqrt {\pi } g^2 \text {erfi}\left (\frac {2 b f n \log (F) \left (a+b \log \left (c (d+e x)^n\right )\right )+3}{2 b \sqrt {f} n \sqrt {\log (F)}}\right ) \exp \left (-\frac {3 \left (4 b f n \log (F) \left (a+b \left (\log \left (c (d+e x)^n\right )-n \log (d+e x)\right )\right )+3\right )}{4 b^2 f n^2 \log (F)}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.42, size = 134, normalized size = 1.01 \[ -\frac {\sqrt {\pi } \sqrt {-b^{2} f n^{2} \log \relax (F)} g^{2} \operatorname {erf}\left (\frac {{\left (2 \, b^{2} f n^{2} \log \left (e x + d\right ) \log \relax (F) + 2 \, b^{2} f n \log \relax (F) \log \relax (c) + 2 \, a b f n \log \relax (F) + 3\right )} \sqrt {-b^{2} f n^{2} \log \relax (F)}}{2 \, b^{2} f n^{2} \log \relax (F)}\right ) e^{\left (-\frac {3 \, {\left (4 \, b^{2} f n \log \relax (F) \log \relax (c) + 4 \, a b f n \log \relax (F) + 3\right )}}{4 \, b^{2} f n^{2} \log \relax (F)}\right )}}{2 \, b e n} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (e g x + d g\right )}^{2} F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{2} f}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.59, size = 0, normalized size = 0.00 \[ \int \left (e g x +d g \right )^{2} F^{\left (b \ln \left (c \left (e x +d \right )^{n}\right )+a \right )^{2} f}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (e g x + d g\right )}^{2} F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{2} f}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\mathrm {e}}^{f\,\ln \relax (F)\,{\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}^2}\,{\left (d\,g+e\,g\,x\right )}^2 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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