Optimal. Leaf size=126 \[ \frac {\sqrt {\pi } (d+e x) \left (c (d+e x)^n\right )^{-1/n} e^{-\frac {4 a b f n \log (F)+1}{4 b^2 f n^2 \log (F)}} \text {erfi}\left (\frac {2 a b f \log (F)+2 b^2 f \log (F) \log \left (c (d+e x)^n\right )+\frac {1}{n}}{2 b \sqrt {f} \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}} \]
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Rubi [A] time = 0.14, antiderivative size = 126, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {2277, 2274, 15, 2276, 2234, 2204} \[ \frac {\sqrt {\pi } (d+e x) \left (c (d+e x)^n\right )^{-1/n} e^{-\frac {4 a b f n \log (F)+1}{4 b^2 f n^2 \log (F)}} \text {Erfi}\left (\frac {2 a b f \log (F)+2 b^2 f \log (F) \log \left (c (d+e x)^n\right )+\frac {1}{n}}{2 b \sqrt {f} \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}} \]
Antiderivative was successfully verified.
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Rule 15
Rule 2204
Rule 2234
Rule 2274
Rule 2276
Rule 2277
Rubi steps
\begin {align*} \int F^{f \left (a+b \log \left (c (d+e x)^n\right )\right )^2} \, dx &=\frac {\operatorname {Subst}\left (\int F^{f \left (a+b \log \left (c x^n\right )\right )^2} \, dx,x,d+e x\right )}{e}\\ &=\frac {\operatorname {Subst}\left (\int F^{a^2 f+2 a b f \log \left (c x^n\right )+b^2 f \log ^2\left (c x^n\right )} \, dx,x,d+e x\right )}{e}\\ &=\frac {\operatorname {Subst}\left (\int F^{a^2 f+b^2 f \log ^2\left (c x^n\right )} \left (c x^n\right )^{2 a b f \log (F)} \, dx,x,d+e x\right )}{e}\\ &=\frac {\left ((d+e x)^{-2 a b f n \log (F)} \left (c (d+e x)^n\right )^{2 a b f \log (F)}\right ) \operatorname {Subst}\left (\int F^{a^2 f+b^2 f \log ^2\left (c x^n\right )} x^{2 a b f n \log (F)} \, dx,x,d+e x\right )}{e}\\ &=\frac {\left ((d+e x) \left (c (d+e x)^n\right )^{2 a b f \log (F)-\frac {1+2 a b f n \log (F)}{n}}\right ) \operatorname {Subst}\left (\int \exp \left (a^2 f \log (F)+b^2 f x^2 \log (F)+\frac {x (1+2 a b f n \log (F))}{n}\right ) \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e n}\\ &=\frac {\left (\exp \left (a^2 f \log (F)-\frac {(1+2 a b f n \log (F))^2}{4 b^2 f n^2 \log (F)}\right ) (d+e x) \left (c (d+e x)^n\right )^{2 a b f \log (F)-\frac {1+2 a b f n \log (F)}{n}}\right ) \operatorname {Subst}\left (\int \exp \left (\frac {\left (2 b^2 f x \log (F)+\frac {1+2 a b f n \log (F)}{n}\right )^2}{4 b^2 f \log (F)}\right ) \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e n}\\ &=\frac {e^{-\frac {1+4 a b f n \log (F)}{4 b^2 f n^2 \log (F)}} \sqrt {\pi } (d+e x) \left (c (d+e x)^n\right )^{-1/n} \text {erfi}\left (\frac {\frac {1}{n}+2 a b f \log (F)+2 b^2 f \log (F) \log \left (c (d+e x)^n\right )}{2 b \sqrt {f} \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}}\\ \end {align*}
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Mathematica [A] time = 0.07, size = 123, normalized size = 0.98 \[ \frac {\sqrt {\pi } (d+e x) \left (c (d+e x)^n\right )^{-1/n} e^{-\frac {4 a b f n \log (F)+1}{4 b^2 f n^2 \log (F)}} \text {erfi}\left (\frac {2 b f n \log (F) \left (a+b \log \left (c (d+e x)^n\right )\right )+1}{2 b \sqrt {f} n \sqrt {\log (F)}}\right )}{2 b e \sqrt {f} n \sqrt {\log (F)}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.40, size = 131, normalized size = 1.04 \[ -\frac {\sqrt {\pi } \sqrt {-b^{2} f n^{2} \log \relax (F)} \operatorname {erf}\left (\frac {{\left (2 \, b^{2} f n^{2} \log \left (e x + d\right ) \log \relax (F) + 2 \, b^{2} f n \log \relax (F) \log \relax (c) + 2 \, a b f n \log \relax (F) + 1\right )} \sqrt {-b^{2} f n^{2} \log \relax (F)}}{2 \, b^{2} f n^{2} \log \relax (F)}\right ) e^{\left (-\frac {4 \, b^{2} f n \log \relax (F) \log \relax (c) + 4 \, a b f n \log \relax (F) + 1}{4 \, b^{2} f n^{2} \log \relax (F)}\right )}}{2 \, b e n} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.55, size = 116, normalized size = 0.92 \[ -\frac {\sqrt {\pi } \operatorname {erf}\left (-\sqrt {-f \log \relax (F)} b n \log \left (x e + d\right ) - \sqrt {-f \log \relax (F)} b \log \relax (c) - \sqrt {-f \log \relax (F)} a - \frac {\sqrt {-f \log \relax (F)}}{2 \, b f n \log \relax (F)}\right ) e^{\left (-\frac {a}{b n} - \frac {1}{4 \, b^{2} f n^{2} \log \relax (F)} - 1\right )}}{2 \, \sqrt {-f \log \relax (F)} b c^{\left (\frac {1}{n}\right )} n} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.02, size = 0, normalized size = 0.00 \[ \int F^{\left (b \ln \left (c \left (e x +d \right )^{n}\right )+a \right )^{2} f}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{2} f}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\mathrm {e}}^{f\,\ln \relax (F)\,{\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int F^{f \left (a + b \log {\left (c \left (d + e x\right )^{n} \right )}\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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