Optimal. Leaf size=145 \[ \frac {16}{105} \sqrt {\pi } \text {erfi}\left (\sqrt {a+b x+c x^2}\right )-\frac {16 e^{a+b x+c x^2}}{105 \sqrt {a+b x+c x^2}}-\frac {8 e^{a+b x+c x^2}}{105 \left (a+b x+c x^2\right )^{3/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}} \]
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Rubi [A] time = 0.38, antiderivative size = 145, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.121, Rules used = {6707, 2177, 2180, 2204} \[ \frac {16}{105} \sqrt {\pi } \text {Erfi}\left (\sqrt {a+b x+c x^2}\right )-\frac {16 e^{a+b x+c x^2}}{105 \sqrt {a+b x+c x^2}}-\frac {8 e^{a+b x+c x^2}}{105 \left (a+b x+c x^2\right )^{3/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}} \]
Antiderivative was successfully verified.
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Rule 2177
Rule 2180
Rule 2204
Rule 6707
Rubi steps
\begin {align*} \int \frac {e^{a+b x+c x^2} (b+2 c x)}{\left (a+b x+c x^2\right )^{9/2}} \, dx &=\operatorname {Subst}\left (\int \frac {e^x}{x^{9/2}} \, dx,x,a+b x+c x^2\right )\\ &=-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}}+\frac {2}{7} \operatorname {Subst}\left (\int \frac {e^x}{x^{7/2}} \, dx,x,a+b x+c x^2\right )\\ &=-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}+\frac {4}{35} \operatorname {Subst}\left (\int \frac {e^x}{x^{5/2}} \, dx,x,a+b x+c x^2\right )\\ &=-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}-\frac {8 e^{a+b x+c x^2}}{105 \left (a+b x+c x^2\right )^{3/2}}+\frac {8}{105} \operatorname {Subst}\left (\int \frac {e^x}{x^{3/2}} \, dx,x,a+b x+c x^2\right )\\ &=-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}-\frac {8 e^{a+b x+c x^2}}{105 \left (a+b x+c x^2\right )^{3/2}}-\frac {16 e^{a+b x+c x^2}}{105 \sqrt {a+b x+c x^2}}+\frac {16}{105} \operatorname {Subst}\left (\int \frac {e^x}{\sqrt {x}} \, dx,x,a+b x+c x^2\right )\\ &=-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}-\frac {8 e^{a+b x+c x^2}}{105 \left (a+b x+c x^2\right )^{3/2}}-\frac {16 e^{a+b x+c x^2}}{105 \sqrt {a+b x+c x^2}}+\frac {32}{105} \operatorname {Subst}\left (\int e^{x^2} \, dx,x,\sqrt {a+b x+c x^2}\right )\\ &=-\frac {2 e^{a+b x+c x^2}}{7 \left (a+b x+c x^2\right )^{7/2}}-\frac {4 e^{a+b x+c x^2}}{35 \left (a+b x+c x^2\right )^{5/2}}-\frac {8 e^{a+b x+c x^2}}{105 \left (a+b x+c x^2\right )^{3/2}}-\frac {16 e^{a+b x+c x^2}}{105 \sqrt {a+b x+c x^2}}+\frac {16}{105} \sqrt {\pi } \text {erfi}\left (\sqrt {a+b x+c x^2}\right )\\ \end {align*}
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Mathematica [A] time = 0.24, size = 103, normalized size = 0.71 \[ -\frac {2 \left (e^{a+x (b+c x)} \left (8 (a+x (b+c x))^3+4 (a+x (b+c x))^2+6 (a+x (b+c x))+15\right )+8 (-a-x (b+c x))^{7/2} \Gamma \left (\frac {1}{2},-a-x (b+c x)\right )\right )}{105 (a+x (b+c x))^{7/2}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.43, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {c x^{2} + b x + a} {\left (2 \, c x + b\right )} e^{\left (c x^{2} + b x + a\right )}}{c^{5} x^{10} + 5 \, b c^{4} x^{9} + 5 \, {\left (2 \, b^{2} c^{3} + a c^{4}\right )} x^{8} + 10 \, {\left (b^{3} c^{2} + 2 \, a b c^{3}\right )} x^{7} + 5 \, {\left (b^{4} c + 6 \, a b^{2} c^{2} + 2 \, a^{2} c^{3}\right )} x^{6} + 5 \, a^{4} b x + {\left (b^{5} + 20 \, a b^{3} c + 30 \, a^{2} b c^{2}\right )} x^{5} + a^{5} + 5 \, {\left (a b^{4} + 6 \, a^{2} b^{2} c + 2 \, a^{3} c^{2}\right )} x^{4} + 10 \, {\left (a^{2} b^{3} + 2 \, a^{3} b c\right )} x^{3} + 5 \, {\left (2 \, a^{3} b^{2} + a^{4} c\right )} x^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (2 \, c x + b\right )} e^{\left (c x^{2} + b x + a\right )}}{{\left (c x^{2} + b x + a\right )}^{\frac {9}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.04, size = 120, normalized size = 0.83 \[ \frac {16 \sqrt {\pi }\, \erfi \left (\sqrt {c \,x^{2}+b x +a}\right )}{105}-\frac {2 \,{\mathrm e}^{c \,x^{2}+b x +a}}{7 \left (c \,x^{2}+b x +a \right )^{\frac {7}{2}}}-\frac {4 \,{\mathrm e}^{c \,x^{2}+b x +a}}{35 \left (c \,x^{2}+b x +a \right )^{\frac {5}{2}}}-\frac {8 \,{\mathrm e}^{c \,x^{2}+b x +a}}{105 \left (c \,x^{2}+b x +a \right )^{\frac {3}{2}}}-\frac {16 \,{\mathrm e}^{c \,x^{2}+b x +a}}{105 \sqrt {c \,x^{2}+b x +a}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (2 \, c x + b\right )} e^{\left (c x^{2} + b x + a\right )}}{{\left (c x^{2} + b x + a\right )}^{\frac {9}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.70, size = 154, normalized size = 1.06 \[ -\frac {{\mathrm {e}}^{c\,x^2+b\,x+a}\,\left (30\,c\,x^2+30\,b\,x+30\,a\right )+12\,{\mathrm {e}}^{c\,x^2+b\,x+a}\,{\left (c\,x^2+b\,x+a\right )}^2+8\,{\mathrm {e}}^{c\,x^2+b\,x+a}\,{\left (c\,x^2+b\,x+a\right )}^3+16\,{\mathrm {e}}^{c\,x^2+b\,x+a}\,{\left (c\,x^2+b\,x+a\right )}^4-16\,\sqrt {\pi }\,\mathrm {erfc}\left (\sqrt {-c\,x^2-b\,x-a}\right )\,{\left (-c\,x^2-b\,x-a\right )}^{9/2}}{105\,{\left (c\,x^2+b\,x+a\right )}^{9/2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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