3.87 \(\int f^{a+b x^2} x^2 \, dx\)

Optimal. Leaf size=59 \[ \frac {x f^{a+b x^2}}{2 b \log (f)}-\frac {\sqrt {\pi } f^a \text {erfi}\left (\sqrt {b} x \sqrt {\log (f)}\right )}{4 b^{3/2} \log ^{\frac {3}{2}}(f)} \]

[Out]

1/2*f^(b*x^2+a)*x/b/ln(f)-1/4*f^a*erfi(x*b^(1/2)*ln(f)^(1/2))*Pi^(1/2)/b^(3/2)/ln(f)^(3/2)

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Rubi [A]  time = 0.03, antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2212, 2204} \[ \frac {x f^{a+b x^2}}{2 b \log (f)}-\frac {\sqrt {\pi } f^a \text {Erfi}\left (\sqrt {b} x \sqrt {\log (f)}\right )}{4 b^{3/2} \log ^{\frac {3}{2}}(f)} \]

Antiderivative was successfully verified.

[In]

Int[f^(a + b*x^2)*x^2,x]

[Out]

-(f^a*Sqrt[Pi]*Erfi[Sqrt[b]*x*Sqrt[Log[f]]])/(4*b^(3/2)*Log[f]^(3/2)) + (f^(a + b*x^2)*x)/(2*b*Log[f])

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2212

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m
- n + 1)*F^(a + b*(c + d*x)^n))/(b*d*n*Log[F]), x] - Dist[(m - n + 1)/(b*n*Log[F]), Int[(c + d*x)^(m - n)*F^(
a + b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[(2*(m + 1))/n] && LtQ[0, (m + 1)/n, 5] &&
IntegerQ[n] && (LtQ[0, n, m + 1] || LtQ[m, n, 0])

Rubi steps

\begin {align*} \int f^{a+b x^2} x^2 \, dx &=\frac {f^{a+b x^2} x}{2 b \log (f)}-\frac {\int f^{a+b x^2} \, dx}{2 b \log (f)}\\ &=-\frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {b} x \sqrt {\log (f)}\right )}{4 b^{3/2} \log ^{\frac {3}{2}}(f)}+\frac {f^{a+b x^2} x}{2 b \log (f)}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 59, normalized size = 1.00 \[ \frac {x f^{a+b x^2}}{2 b \log (f)}-\frac {\sqrt {\pi } f^a \text {erfi}\left (\sqrt {b} x \sqrt {\log (f)}\right )}{4 b^{3/2} \log ^{\frac {3}{2}}(f)} \]

Antiderivative was successfully verified.

[In]

Integrate[f^(a + b*x^2)*x^2,x]

[Out]

-1/4*(f^a*Sqrt[Pi]*Erfi[Sqrt[b]*x*Sqrt[Log[f]]])/(b^(3/2)*Log[f]^(3/2)) + (f^(a + b*x^2)*x)/(2*b*Log[f])

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fricas [A]  time = 0.41, size = 49, normalized size = 0.83 \[ \frac {2 \, b f^{b x^{2} + a} x \log \relax (f) + \sqrt {\pi } \sqrt {-b \log \relax (f)} f^{a} \operatorname {erf}\left (\sqrt {-b \log \relax (f)} x\right )}{4 \, b^{2} \log \relax (f)^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(b*x^2+a)*x^2,x, algorithm="fricas")

[Out]

1/4*(2*b*f^(b*x^2 + a)*x*log(f) + sqrt(pi)*sqrt(-b*log(f))*f^a*erf(sqrt(-b*log(f))*x))/(b^2*log(f)^2)

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giac [A]  time = 0.27, size = 57, normalized size = 0.97 \[ \frac {\sqrt {\pi } f^{a} \operatorname {erf}\left (-\sqrt {-b \log \relax (f)} x\right )}{4 \, \sqrt {-b \log \relax (f)} b \log \relax (f)} + \frac {x e^{\left (b x^{2} \log \relax (f) + a \log \relax (f)\right )}}{2 \, b \log \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(b*x^2+a)*x^2,x, algorithm="giac")

[Out]

1/4*sqrt(pi)*f^a*erf(-sqrt(-b*log(f))*x)/(sqrt(-b*log(f))*b*log(f)) + 1/2*x*e^(b*x^2*log(f) + a*log(f))/(b*log
(f))

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maple [A]  time = 0.04, size = 54, normalized size = 0.92 \[ \frac {x \,f^{a} f^{b \,x^{2}}}{2 b \ln \relax (f )}-\frac {\sqrt {\pi }\, f^{a} \erf \left (\sqrt {-b \ln \relax (f )}\, x \right )}{4 \sqrt {-b \ln \relax (f )}\, b \ln \relax (f )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(b*x^2+a)*x^2,x)

[Out]

1/2*f^a/ln(f)/b*x*f^(b*x^2)-1/4*f^a/ln(f)/b*Pi^(1/2)/(-b*ln(f))^(1/2)*erf((-b*ln(f))^(1/2)*x)

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maxima [A]  time = 0.78, size = 53, normalized size = 0.90 \[ \frac {f^{b x^{2}} f^{a} x}{2 \, b \log \relax (f)} - \frac {\sqrt {\pi } f^{a} \operatorname {erf}\left (\sqrt {-b \log \relax (f)} x\right )}{4 \, \sqrt {-b \log \relax (f)} b \log \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(b*x^2+a)*x^2,x, algorithm="maxima")

[Out]

1/2*f^(b*x^2)*f^a*x/(b*log(f)) - 1/4*sqrt(pi)*f^a*erf(sqrt(-b*log(f))*x)/(sqrt(-b*log(f))*b*log(f))

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mupad [B]  time = 3.61, size = 54, normalized size = 0.92 \[ \frac {f^a\,f^{b\,x^2}\,x}{2\,b\,\ln \relax (f)}-\frac {f^a\,\sqrt {\pi }\,\mathrm {erfi}\left (\frac {b\,x\,\ln \relax (f)}{\sqrt {b\,\ln \relax (f)}}\right )}{4\,b\,\ln \relax (f)\,\sqrt {b\,\ln \relax (f)}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(a + b*x^2)*x^2,x)

[Out]

(f^a*f^(b*x^2)*x)/(2*b*log(f)) - (f^a*pi^(1/2)*erfi((b*x*log(f))/(b*log(f))^(1/2)))/(4*b*log(f)*(b*log(f))^(1/
2))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int f^{a + b x^{2}} x^{2}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f**(b*x**2+a)*x**2,x)

[Out]

Integral(f**(a + b*x**2)*x**2, x)

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