Optimal. Leaf size=95 \[ \frac {d^2 \sin (a+b x) \cos (a+b x)}{4 b^3}+\frac {d (c+d x) \sin ^2(a+b x)}{2 b^2}-\frac {(c+d x)^2 \sin (a+b x) \cos (a+b x)}{2 b}-\frac {d^2 x}{4 b^2}+\frac {(c+d x)^3}{6 d} \]
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Rubi [A] time = 0.05, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3311, 32, 2635, 8} \[ \frac {d (c+d x) \sin ^2(a+b x)}{2 b^2}+\frac {d^2 \sin (a+b x) \cos (a+b x)}{4 b^3}-\frac {(c+d x)^2 \sin (a+b x) \cos (a+b x)}{2 b}-\frac {d^2 x}{4 b^2}+\frac {(c+d x)^3}{6 d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 32
Rule 2635
Rule 3311
Rubi steps
\begin {align*} \int (c+d x)^2 \sin ^2(a+b x) \, dx &=-\frac {(c+d x)^2 \cos (a+b x) \sin (a+b x)}{2 b}+\frac {d (c+d x) \sin ^2(a+b x)}{2 b^2}+\frac {1}{2} \int (c+d x)^2 \, dx-\frac {d^2 \int \sin ^2(a+b x) \, dx}{2 b^2}\\ &=\frac {(c+d x)^3}{6 d}+\frac {d^2 \cos (a+b x) \sin (a+b x)}{4 b^3}-\frac {(c+d x)^2 \cos (a+b x) \sin (a+b x)}{2 b}+\frac {d (c+d x) \sin ^2(a+b x)}{2 b^2}-\frac {d^2 \int 1 \, dx}{4 b^2}\\ &=-\frac {d^2 x}{4 b^2}+\frac {(c+d x)^3}{6 d}+\frac {d^2 \cos (a+b x) \sin (a+b x)}{4 b^3}-\frac {(c+d x)^2 \cos (a+b x) \sin (a+b x)}{2 b}+\frac {d (c+d x) \sin ^2(a+b x)}{2 b^2}\\ \end {align*}
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Mathematica [A] time = 0.32, size = 77, normalized size = 0.81 \[ \frac {-3 \sin (2 (a+b x)) \left (2 b^2 (c+d x)^2-d^2\right )-6 b d (c+d x) \cos (2 (a+b x))+4 b^3 x \left (3 c^2+3 c d x+d^2 x^2\right )}{24 b^3} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.67, size = 112, normalized size = 1.18 \[ \frac {2 \, b^{3} d^{2} x^{3} + 6 \, b^{3} c d x^{2} - 6 \, {\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{2} - 3 \, {\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right ) + 3 \, {\left (2 \, b^{3} c^{2} + b d^{2}\right )} x}{12 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.82, size = 94, normalized size = 0.99 \[ \frac {1}{6} \, d^{2} x^{3} + \frac {1}{2} \, c d x^{2} + \frac {1}{2} \, c^{2} x - \frac {{\left (b d^{2} x + b c d\right )} \cos \left (2 \, b x + 2 \, a\right )}{4 \, b^{3}} - \frac {{\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \sin \left (2 \, b x + 2 \, a\right )}{8 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 289, normalized size = 3.04 \[ \frac {\frac {d^{2} \left (\left (b x +a \right )^{2} \left (-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )-\frac {\left (b x +a \right ) \left (\cos ^{2}\left (b x +a \right )\right )}{2}+\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{4}+\frac {b x}{4}+\frac {a}{4}-\frac {\left (b x +a \right )^{3}}{3}\right )}{b^{2}}-\frac {2 a \,d^{2} \left (\left (b x +a \right ) \left (-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )-\frac {\left (b x +a \right )^{2}}{4}+\frac {\left (\sin ^{2}\left (b x +a \right )\right )}{4}\right )}{b^{2}}+\frac {2 c d \left (\left (b x +a \right ) \left (-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )-\frac {\left (b x +a \right )^{2}}{4}+\frac {\left (\sin ^{2}\left (b x +a \right )\right )}{4}\right )}{b}+\frac {a^{2} d^{2} \left (-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )}{b^{2}}-\frac {2 a c d \left (-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )}{b}+c^{2} \left (-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )}{b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.40, size = 232, normalized size = 2.44 \[ \frac {6 \, {\left (2 \, b x + 2 \, a - \sin \left (2 \, b x + 2 \, a\right )\right )} c^{2} - \frac {12 \, {\left (2 \, b x + 2 \, a - \sin \left (2 \, b x + 2 \, a\right )\right )} a c d}{b} + \frac {6 \, {\left (2 \, b x + 2 \, a - \sin \left (2 \, b x + 2 \, a\right )\right )} a^{2} d^{2}}{b^{2}} + \frac {6 \, {\left (2 \, {\left (b x + a\right )}^{2} - 2 \, {\left (b x + a\right )} \sin \left (2 \, b x + 2 \, a\right ) - \cos \left (2 \, b x + 2 \, a\right )\right )} c d}{b} - \frac {6 \, {\left (2 \, {\left (b x + a\right )}^{2} - 2 \, {\left (b x + a\right )} \sin \left (2 \, b x + 2 \, a\right ) - \cos \left (2 \, b x + 2 \, a\right )\right )} a d^{2}}{b^{2}} + \frac {{\left (4 \, {\left (b x + a\right )}^{3} - 6 \, {\left (b x + a\right )} \cos \left (2 \, b x + 2 \, a\right ) - 3 \, {\left (2 \, {\left (b x + a\right )}^{2} - 1\right )} \sin \left (2 \, b x + 2 \, a\right )\right )} d^{2}}{b^{2}}}{24 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.20, size = 179, normalized size = 1.88 \[ x\,\left (\frac {c^2}{4}-\frac {d^2}{8\,b^2}\right )+x\,\left (\frac {c^2}{4}+\frac {d^2}{8\,b^2}\right )+\frac {d^2\,x^3}{6}+\frac {\sin \left (2\,a+2\,b\,x\right )\,\left (d^2-2\,b^2\,c^2\right )}{8\,b^3}+\frac {x\,\cos \left (2\,a+2\,b\,x\right )\,\left (\frac {c^2}{2}-\frac {d^2}{4\,b^2}\right )}{2}-\frac {x\,\cos \left (2\,a+2\,b\,x\right )\,\left (\frac {c^2}{2}+\frac {d^2}{4\,b^2}\right )}{2}+\frac {c\,d\,x^2}{2}-\frac {d^2\,x^2\,\sin \left (2\,a+2\,b\,x\right )}{4\,b}-\frac {c\,d\,\cos \left (2\,a+2\,b\,x\right )}{4\,b^2}-\frac {c\,d\,x\,\sin \left (2\,a+2\,b\,x\right )}{2\,b} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.57, size = 264, normalized size = 2.78 \[ \begin {cases} \frac {c^{2} x \sin ^{2}{\left (a + b x \right )}}{2} + \frac {c^{2} x \cos ^{2}{\left (a + b x \right )}}{2} + \frac {c d x^{2} \sin ^{2}{\left (a + b x \right )}}{2} + \frac {c d x^{2} \cos ^{2}{\left (a + b x \right )}}{2} + \frac {d^{2} x^{3} \sin ^{2}{\left (a + b x \right )}}{6} + \frac {d^{2} x^{3} \cos ^{2}{\left (a + b x \right )}}{6} - \frac {c^{2} \sin {\left (a + b x \right )} \cos {\left (a + b x \right )}}{2 b} - \frac {c d x \sin {\left (a + b x \right )} \cos {\left (a + b x \right )}}{b} - \frac {d^{2} x^{2} \sin {\left (a + b x \right )} \cos {\left (a + b x \right )}}{2 b} - \frac {c d \cos ^{2}{\left (a + b x \right )}}{2 b^{2}} + \frac {d^{2} x \sin ^{2}{\left (a + b x \right )}}{4 b^{2}} - \frac {d^{2} x \cos ^{2}{\left (a + b x \right )}}{4 b^{2}} + \frac {d^{2} \sin {\left (a + b x \right )} \cos {\left (a + b x \right )}}{4 b^{3}} & \text {for}\: b \neq 0 \\\left (c^{2} x + c d x^{2} + \frac {d^{2} x^{3}}{3}\right ) \sin ^{2}{\relax (a )} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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