Optimal. Leaf size=193 \[ -\frac {8 \sqrt {2 \pi } b^{5/2} \cos \left (a-\frac {b c}{d}\right ) C\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }} \sqrt {c+d x}}{\sqrt {d}}\right )}{15 d^{7/2}}+\frac {8 \sqrt {2 \pi } b^{5/2} \sin \left (a-\frac {b c}{d}\right ) S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }} \sqrt {c+d x}}{\sqrt {d}}\right )}{15 d^{7/2}}+\frac {8 b^2 \sin (a+b x)}{15 d^3 \sqrt {c+d x}}-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}} \]
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Rubi [A] time = 0.30, antiderivative size = 193, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {3297, 3306, 3305, 3351, 3304, 3352} \[ -\frac {8 \sqrt {2 \pi } b^{5/2} \cos \left (a-\frac {b c}{d}\right ) \text {FresnelC}\left (\frac {\sqrt {\frac {2}{\pi }} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{15 d^{7/2}}+\frac {8 \sqrt {2 \pi } b^{5/2} \sin \left (a-\frac {b c}{d}\right ) S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }} \sqrt {c+d x}}{\sqrt {d}}\right )}{15 d^{7/2}}+\frac {8 b^2 \sin (a+b x)}{15 d^3 \sqrt {c+d x}}-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 3297
Rule 3304
Rule 3305
Rule 3306
Rule 3351
Rule 3352
Rubi steps
\begin {align*} \int \frac {\sin (a+b x)}{(c+d x)^{7/2}} \, dx &=-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}}+\frac {(2 b) \int \frac {\cos (a+b x)}{(c+d x)^{5/2}} \, dx}{5 d}\\ &=-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}}-\frac {\left (4 b^2\right ) \int \frac {\sin (a+b x)}{(c+d x)^{3/2}} \, dx}{15 d^2}\\ &=-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}}+\frac {8 b^2 \sin (a+b x)}{15 d^3 \sqrt {c+d x}}-\frac {\left (8 b^3\right ) \int \frac {\cos (a+b x)}{\sqrt {c+d x}} \, dx}{15 d^3}\\ &=-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}}+\frac {8 b^2 \sin (a+b x)}{15 d^3 \sqrt {c+d x}}-\frac {\left (8 b^3 \cos \left (a-\frac {b c}{d}\right )\right ) \int \frac {\cos \left (\frac {b c}{d}+b x\right )}{\sqrt {c+d x}} \, dx}{15 d^3}+\frac {\left (8 b^3 \sin \left (a-\frac {b c}{d}\right )\right ) \int \frac {\sin \left (\frac {b c}{d}+b x\right )}{\sqrt {c+d x}} \, dx}{15 d^3}\\ &=-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}}+\frac {8 b^2 \sin (a+b x)}{15 d^3 \sqrt {c+d x}}-\frac {\left (16 b^3 \cos \left (a-\frac {b c}{d}\right )\right ) \operatorname {Subst}\left (\int \cos \left (\frac {b x^2}{d}\right ) \, dx,x,\sqrt {c+d x}\right )}{15 d^4}+\frac {\left (16 b^3 \sin \left (a-\frac {b c}{d}\right )\right ) \operatorname {Subst}\left (\int \sin \left (\frac {b x^2}{d}\right ) \, dx,x,\sqrt {c+d x}\right )}{15 d^4}\\ &=-\frac {4 b \cos (a+b x)}{15 d^2 (c+d x)^{3/2}}-\frac {8 b^{5/2} \sqrt {2 \pi } \cos \left (a-\frac {b c}{d}\right ) C\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }} \sqrt {c+d x}}{\sqrt {d}}\right )}{15 d^{7/2}}+\frac {8 b^{5/2} \sqrt {2 \pi } S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }} \sqrt {c+d x}}{\sqrt {d}}\right ) \sin \left (a-\frac {b c}{d}\right )}{15 d^{7/2}}-\frac {2 \sin (a+b x)}{5 d (c+d x)^{5/2}}+\frac {8 b^2 \sin (a+b x)}{15 d^3 \sqrt {c+d x}}\\ \end {align*}
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Mathematica [C] time = 0.50, size = 208, normalized size = 1.08 \[ -\frac {i \left (b (c+d x) \left (2 e^{i \left (a-\frac {b c}{d}\right )} \left (e^{\frac {i b (c+d x)}{d}} (2 b (c+d x)-i d)-2 i d \left (-\frac {i b (c+d x)}{d}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {i b (c+d x)}{d}\right )\right )-i e^{-i (a+b x)} \left (-4 i b (c+d x)+4 d e^{\frac {i b (c+d x)}{d}} \left (\frac {i b (c+d x)}{d}\right )^{3/2} \Gamma \left (\frac {1}{2},\frac {i b (c+d x)}{d}\right )+2 d\right )\right )-6 i d^2 \sin (a+b x)\right )}{15 d^3 (c+d x)^{5/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.83, size = 297, normalized size = 1.54 \[ -\frac {2 \, {\left (4 \, \sqrt {2} {\left (\pi b^{2} d^{3} x^{3} + 3 \, \pi b^{2} c d^{2} x^{2} + 3 \, \pi b^{2} c^{2} d x + \pi b^{2} c^{3}\right )} \sqrt {\frac {b}{\pi d}} \cos \left (-\frac {b c - a d}{d}\right ) \operatorname {C}\left (\sqrt {2} \sqrt {d x + c} \sqrt {\frac {b}{\pi d}}\right ) - 4 \, \sqrt {2} {\left (\pi b^{2} d^{3} x^{3} + 3 \, \pi b^{2} c d^{2} x^{2} + 3 \, \pi b^{2} c^{2} d x + \pi b^{2} c^{3}\right )} \sqrt {\frac {b}{\pi d}} \operatorname {S}\left (\sqrt {2} \sqrt {d x + c} \sqrt {\frac {b}{\pi d}}\right ) \sin \left (-\frac {b c - a d}{d}\right ) + \sqrt {d x + c} {\left (2 \, {\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) - {\left (4 \, b^{2} d^{2} x^{2} + 8 \, b^{2} c d x + 4 \, b^{2} c^{2} - 3 \, d^{2}\right )} \sin \left (b x + a\right )\right )}\right )}}{15 \, {\left (d^{6} x^{3} + 3 \, c d^{5} x^{2} + 3 \, c^{2} d^{4} x + c^{3} d^{3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin \left (b x + a\right )}{{\left (d x + c\right )}^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 220, normalized size = 1.14 \[ \frac {-\frac {2 \sin \left (\frac {\left (d x +c \right ) b}{d}+\frac {d a -c b}{d}\right )}{5 \left (d x +c \right )^{\frac {5}{2}}}+\frac {4 b \left (-\frac {\cos \left (\frac {\left (d x +c \right ) b}{d}+\frac {d a -c b}{d}\right )}{3 \left (d x +c \right )^{\frac {3}{2}}}-\frac {2 b \left (-\frac {\sin \left (\frac {\left (d x +c \right ) b}{d}+\frac {d a -c b}{d}\right )}{\sqrt {d x +c}}+\frac {b \sqrt {2}\, \sqrt {\pi }\, \left (\cos \left (\frac {d a -c b}{d}\right ) \FresnelC \left (\frac {\sqrt {2}\, \sqrt {d x +c}\, b}{\sqrt {\pi }\, \sqrt {\frac {b}{d}}\, d}\right )-\sin \left (\frac {d a -c b}{d}\right ) \mathrm {S}\left (\frac {\sqrt {2}\, \sqrt {d x +c}\, b}{\sqrt {\pi }\, \sqrt {\frac {b}{d}}\, d}\right )\right )}{d \sqrt {\frac {b}{d}}}\right )}{3 d}\right )}{5 d}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [C] time = 1.06, size = 129, normalized size = 0.67 \[ \frac {{\left ({\left (\left (i - 1\right ) \, \sqrt {2} \Gamma \left (-\frac {5}{2}, \frac {i \, {\left (d x + c\right )} b}{d}\right ) - \left (i + 1\right ) \, \sqrt {2} \Gamma \left (-\frac {5}{2}, -\frac {i \, {\left (d x + c\right )} b}{d}\right )\right )} \cos \left (-\frac {b c - a d}{d}\right ) + {\left (\left (i + 1\right ) \, \sqrt {2} \Gamma \left (-\frac {5}{2}, \frac {i \, {\left (d x + c\right )} b}{d}\right ) - \left (i - 1\right ) \, \sqrt {2} \Gamma \left (-\frac {5}{2}, -\frac {i \, {\left (d x + c\right )} b}{d}\right )\right )} \sin \left (-\frac {b c - a d}{d}\right )\right )} \left (\frac {{\left (d x + c\right )} b}{d}\right )^{\frac {5}{2}}}{4 \, {\left (d x + c\right )}^{\frac {5}{2}} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\sin \left (a+b\,x\right )}{{\left (c+d\,x\right )}^{7/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin {\left (a + b x \right )}}{\left (c + d x\right )^{\frac {7}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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