3.93 \(\int (\frac {x}{\csc ^{\frac {5}{2}}(e+f x)}-\frac {3 x}{5 \sqrt {\csc (e+f x)}}) \, dx\)

Optimal. Leaf size=42 \[ \frac {4}{25 f^2 \csc ^{\frac {5}{2}}(e+f x)}-\frac {2 x \cos (e+f x)}{5 f \csc ^{\frac {3}{2}}(e+f x)} \]

[Out]

4/25/f^2/csc(f*x+e)^(5/2)-2/5*x*cos(f*x+e)/f/csc(f*x+e)^(3/2)

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Rubi [A]  time = 0.11, antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {4187, 4189} \[ \frac {4}{25 f^2 \csc ^{\frac {5}{2}}(e+f x)}-\frac {2 x \cos (e+f x)}{5 f \csc ^{\frac {3}{2}}(e+f x)} \]

Antiderivative was successfully verified.

[In]

Int[x/Csc[e + f*x]^(5/2) - (3*x)/(5*Sqrt[Csc[e + f*x]]),x]

[Out]

4/(25*f^2*Csc[e + f*x]^(5/2)) - (2*x*Cos[e + f*x])/(5*f*Csc[e + f*x]^(3/2))

Rule 4187

Int[(csc[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(d*(b*Csc[e + f*x])^n)/(f^2*n
^2), x] + (Dist[(n + 1)/(b^2*n), Int[(c + d*x)*(b*Csc[e + f*x])^(n + 2), x], x] + Simp[((c + d*x)*Cos[e + f*x]
*(b*Csc[e + f*x])^(n + 1))/(b*f*n), x]) /; FreeQ[{b, c, d, e, f}, x] && LtQ[n, -1]

Rule 4189

Int[(csc[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Dist[(b*Sin[e + f*x])^n*(b*C
sc[e + f*x])^n, Int[(c + d*x)^m/(b*Sin[e + f*x])^n, x], x] /; FreeQ[{b, c, d, e, f, m, n}, x] &&  !IntegerQ[n]

Rubi steps

\begin {align*} \int \left (\frac {x}{\csc ^{\frac {5}{2}}(e+f x)}-\frac {3 x}{5 \sqrt {\csc (e+f x)}}\right ) \, dx &=-\left (\frac {3}{5} \int \frac {x}{\sqrt {\csc (e+f x)}} \, dx\right )+\int \frac {x}{\csc ^{\frac {5}{2}}(e+f x)} \, dx\\ &=\frac {4}{25 f^2 \csc ^{\frac {5}{2}}(e+f x)}-\frac {2 x \cos (e+f x)}{5 f \csc ^{\frac {3}{2}}(e+f x)}+\frac {3}{5} \int \frac {x}{\sqrt {\csc (e+f x)}} \, dx-\frac {1}{5} \left (3 \sqrt {\csc (e+f x)} \sqrt {\sin (e+f x)}\right ) \int x \sqrt {\sin (e+f x)} \, dx\\ &=\frac {4}{25 f^2 \csc ^{\frac {5}{2}}(e+f x)}-\frac {2 x \cos (e+f x)}{5 f \csc ^{\frac {3}{2}}(e+f x)}\\ \end {align*}

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Mathematica [A]  time = 0.50, size = 29, normalized size = 0.69 \[ -\frac {2 (5 f x \cot (e+f x)-2)}{25 f^2 \csc ^{\frac {5}{2}}(e+f x)} \]

Antiderivative was successfully verified.

[In]

Integrate[x/Csc[e + f*x]^(5/2) - (3*x)/(5*Sqrt[Csc[e + f*x]]),x]

[Out]

(-2*(-2 + 5*f*x*Cot[e + f*x]))/(25*f^2*Csc[e + f*x]^(5/2))

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/csc(f*x+e)^(5/2)-3/5*x/csc(f*x+e)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int -\frac {3 \, x}{5 \, \sqrt {\csc \left (f x + e\right )}} + \frac {x}{\csc \left (f x + e\right )^{\frac {5}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/csc(f*x+e)^(5/2)-3/5*x/csc(f*x+e)^(1/2),x, algorithm="giac")

[Out]

integrate(-3/5*x/sqrt(csc(f*x + e)) + x/csc(f*x + e)^(5/2), x)

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maple [F]  time = 0.20, size = 0, normalized size = 0.00 \[ \int \frac {x}{\csc \left (f x +e \right )^{\frac {5}{2}}}-\frac {3 x}{5 \sqrt {\csc \left (f x +e \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/csc(f*x+e)^(5/2)-3/5*x/csc(f*x+e)^(1/2),x)

[Out]

int(x/csc(f*x+e)^(5/2)-3/5*x/csc(f*x+e)^(1/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int -\frac {3 \, x}{5 \, \sqrt {\csc \left (f x + e\right )}} + \frac {x}{\csc \left (f x + e\right )^{\frac {5}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/csc(f*x+e)^(5/2)-3/5*x/csc(f*x+e)^(1/2),x, algorithm="maxima")

[Out]

integrate(-3/5*x/sqrt(csc(f*x + e)) + x/csc(f*x + e)^(5/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {x}{{\left (\frac {1}{\sin \left (e+f\,x\right )}\right )}^{5/2}}-\frac {3\,x}{5\,\sqrt {\frac {1}{\sin \left (e+f\,x\right )}}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(1/sin(e + f*x))^(5/2) - (3*x)/(5*(1/sin(e + f*x))^(1/2)),x)

[Out]

int(x/(1/sin(e + f*x))^(5/2) - (3*x)/(5*(1/sin(e + f*x))^(1/2)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ - \frac {\int \left (- \frac {5 x}{\csc ^{\frac {5}{2}}{\left (e + f x \right )}}\right )\, dx + \int \frac {3 x}{\sqrt {\csc {\left (e + f x \right )}}}\, dx}{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/csc(f*x+e)**(5/2)-3/5*x/csc(f*x+e)**(1/2),x)

[Out]

-(Integral(-5*x/csc(e + f*x)**(5/2), x) + Integral(3*x/sqrt(csc(e + f*x)), x))/5

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