Optimal. Leaf size=90 \[ \frac {6 a d^2 (c+d x) \cos (e+f x)}{f^3}+\frac {3 a d (c+d x)^2 \sin (e+f x)}{f^2}-\frac {a (c+d x)^3 \cos (e+f x)}{f}+\frac {a (c+d x)^4}{4 d}-\frac {6 a d^3 \sin (e+f x)}{f^4} \]
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Rubi [A] time = 0.12, antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3317, 3296, 2637} \[ \frac {6 a d^2 (c+d x) \cos (e+f x)}{f^3}+\frac {3 a d (c+d x)^2 \sin (e+f x)}{f^2}-\frac {a (c+d x)^3 \cos (e+f x)}{f}+\frac {a (c+d x)^4}{4 d}-\frac {6 a d^3 \sin (e+f x)}{f^4} \]
Antiderivative was successfully verified.
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Rule 2637
Rule 3296
Rule 3317
Rubi steps
\begin {align*} \int (c+d x)^3 (a+a \sin (e+f x)) \, dx &=\int \left (a (c+d x)^3+a (c+d x)^3 \sin (e+f x)\right ) \, dx\\ &=\frac {a (c+d x)^4}{4 d}+a \int (c+d x)^3 \sin (e+f x) \, dx\\ &=\frac {a (c+d x)^4}{4 d}-\frac {a (c+d x)^3 \cos (e+f x)}{f}+\frac {(3 a d) \int (c+d x)^2 \cos (e+f x) \, dx}{f}\\ &=\frac {a (c+d x)^4}{4 d}-\frac {a (c+d x)^3 \cos (e+f x)}{f}+\frac {3 a d (c+d x)^2 \sin (e+f x)}{f^2}-\frac {\left (6 a d^2\right ) \int (c+d x) \sin (e+f x) \, dx}{f^2}\\ &=\frac {a (c+d x)^4}{4 d}+\frac {6 a d^2 (c+d x) \cos (e+f x)}{f^3}-\frac {a (c+d x)^3 \cos (e+f x)}{f}+\frac {3 a d (c+d x)^2 \sin (e+f x)}{f^2}-\frac {\left (6 a d^3\right ) \int \cos (e+f x) \, dx}{f^3}\\ &=\frac {a (c+d x)^4}{4 d}+\frac {6 a d^2 (c+d x) \cos (e+f x)}{f^3}-\frac {a (c+d x)^3 \cos (e+f x)}{f}-\frac {6 a d^3 \sin (e+f x)}{f^4}+\frac {3 a d (c+d x)^2 \sin (e+f x)}{f^2}\\ \end {align*}
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Mathematica [A] time = 0.93, size = 123, normalized size = 1.37 \[ a \left (\frac {3 d \left (c^2 f^2+2 c d f^2 x+d^2 \left (f^2 x^2-2\right )\right ) \sin (e+f x)}{f^4}-\frac {(c+d x) \left (c^2 f^2+2 c d f^2 x+d^2 \left (f^2 x^2-6\right )\right ) \cos (e+f x)}{f^3}+\frac {1}{4} x \left (4 c^3+6 c^2 d x+4 c d^2 x^2+d^3 x^3\right )\right ) \]
Antiderivative was successfully verified.
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fricas [A] time = 0.67, size = 168, normalized size = 1.87 \[ \frac {a d^{3} f^{4} x^{4} + 4 \, a c d^{2} f^{4} x^{3} + 6 \, a c^{2} d f^{4} x^{2} + 4 \, a c^{3} f^{4} x - 4 \, {\left (a d^{3} f^{3} x^{3} + 3 \, a c d^{2} f^{3} x^{2} + a c^{3} f^{3} - 6 \, a c d^{2} f + 3 \, {\left (a c^{2} d f^{3} - 2 \, a d^{3} f\right )} x\right )} \cos \left (f x + e\right ) + 12 \, {\left (a d^{3} f^{2} x^{2} + 2 \, a c d^{2} f^{2} x + a c^{2} d f^{2} - 2 \, a d^{3}\right )} \sin \left (f x + e\right )}{4 \, f^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.35, size = 157, normalized size = 1.74 \[ \frac {1}{4} \, a d^{3} x^{4} + a c d^{2} x^{3} + \frac {3}{2} \, a c^{2} d x^{2} + a c^{3} x - \frac {{\left (a d^{3} f^{3} x^{3} + 3 \, a c d^{2} f^{3} x^{2} + 3 \, a c^{2} d f^{3} x + a c^{3} f^{3} - 6 \, a d^{3} f x - 6 \, a c d^{2} f\right )} \cos \left (f x + e\right )}{f^{4}} + \frac {3 \, {\left (a d^{3} f^{2} x^{2} + 2 \, a c d^{2} f^{2} x + a c^{2} d f^{2} - 2 \, a d^{3}\right )} \sin \left (f x + e\right )}{f^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.04, size = 482, normalized size = 5.36 \[ \frac {\frac {a \,d^{3} \left (-\left (f x +e \right )^{3} \cos \left (f x +e \right )+3 \left (f x +e \right )^{2} \sin \left (f x +e \right )-6 \sin \left (f x +e \right )+6 \left (f x +e \right ) \cos \left (f x +e \right )\right )}{f^{3}}+\frac {3 a c \,d^{2} \left (-\left (f x +e \right )^{2} \cos \left (f x +e \right )+2 \cos \left (f x +e \right )+2 \left (f x +e \right ) \sin \left (f x +e \right )\right )}{f^{2}}-\frac {3 a \,d^{3} e \left (-\left (f x +e \right )^{2} \cos \left (f x +e \right )+2 \cos \left (f x +e \right )+2 \left (f x +e \right ) \sin \left (f x +e \right )\right )}{f^{3}}+\frac {3 a \,c^{2} d \left (\sin \left (f x +e \right )-\left (f x +e \right ) \cos \left (f x +e \right )\right )}{f}-\frac {6 a c \,d^{2} e \left (\sin \left (f x +e \right )-\left (f x +e \right ) \cos \left (f x +e \right )\right )}{f^{2}}+\frac {3 a \,d^{3} e^{2} \left (\sin \left (f x +e \right )-\left (f x +e \right ) \cos \left (f x +e \right )\right )}{f^{3}}-a \,c^{3} \cos \left (f x +e \right )+\frac {3 a \,c^{2} d e \cos \left (f x +e \right )}{f}-\frac {3 a c \,d^{2} e^{2} \cos \left (f x +e \right )}{f^{2}}+\frac {a \,d^{3} e^{3} \cos \left (f x +e \right )}{f^{3}}+\frac {a \,d^{3} \left (f x +e \right )^{4}}{4 f^{3}}+\frac {a c \,d^{2} \left (f x +e \right )^{3}}{f^{2}}-\frac {a \,d^{3} e \left (f x +e \right )^{3}}{f^{3}}+\frac {3 a \,c^{2} d \left (f x +e \right )^{2}}{2 f}-\frac {3 a c \,d^{2} e \left (f x +e \right )^{2}}{f^{2}}+\frac {3 a \,d^{3} e^{2} \left (f x +e \right )^{2}}{2 f^{3}}+a \,c^{3} \left (f x +e \right )-\frac {3 a \,c^{2} d e \left (f x +e \right )}{f}+\frac {3 a c \,d^{2} e^{2} \left (f x +e \right )}{f^{2}}-\frac {a \,d^{3} e^{3} \left (f x +e \right )}{f^{3}}}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.34, size = 462, normalized size = 5.13 \[ \frac {4 \, {\left (f x + e\right )} a c^{3} + \frac {{\left (f x + e\right )}^{4} a d^{3}}{f^{3}} - \frac {4 \, {\left (f x + e\right )}^{3} a d^{3} e}{f^{3}} + \frac {6 \, {\left (f x + e\right )}^{2} a d^{3} e^{2}}{f^{3}} - \frac {4 \, {\left (f x + e\right )} a d^{3} e^{3}}{f^{3}} + \frac {4 \, {\left (f x + e\right )}^{3} a c d^{2}}{f^{2}} - \frac {12 \, {\left (f x + e\right )}^{2} a c d^{2} e}{f^{2}} + \frac {12 \, {\left (f x + e\right )} a c d^{2} e^{2}}{f^{2}} + \frac {6 \, {\left (f x + e\right )}^{2} a c^{2} d}{f} - \frac {12 \, {\left (f x + e\right )} a c^{2} d e}{f} - 4 \, a c^{3} \cos \left (f x + e\right ) + \frac {4 \, a d^{3} e^{3} \cos \left (f x + e\right )}{f^{3}} - \frac {12 \, a c d^{2} e^{2} \cos \left (f x + e\right )}{f^{2}} + \frac {12 \, a c^{2} d e \cos \left (f x + e\right )}{f} - \frac {12 \, {\left ({\left (f x + e\right )} \cos \left (f x + e\right ) - \sin \left (f x + e\right )\right )} a d^{3} e^{2}}{f^{3}} + \frac {24 \, {\left ({\left (f x + e\right )} \cos \left (f x + e\right ) - \sin \left (f x + e\right )\right )} a c d^{2} e}{f^{2}} - \frac {12 \, {\left ({\left (f x + e\right )} \cos \left (f x + e\right ) - \sin \left (f x + e\right )\right )} a c^{2} d}{f} + \frac {12 \, {\left ({\left ({\left (f x + e\right )}^{2} - 2\right )} \cos \left (f x + e\right ) - 2 \, {\left (f x + e\right )} \sin \left (f x + e\right )\right )} a d^{3} e}{f^{3}} - \frac {12 \, {\left ({\left ({\left (f x + e\right )}^{2} - 2\right )} \cos \left (f x + e\right ) - 2 \, {\left (f x + e\right )} \sin \left (f x + e\right )\right )} a c d^{2}}{f^{2}} - \frac {4 \, {\left ({\left ({\left (f x + e\right )}^{3} - 6 \, f x - 6 \, e\right )} \cos \left (f x + e\right ) - 3 \, {\left ({\left (f x + e\right )}^{2} - 2\right )} \sin \left (f x + e\right )\right )} a d^{3}}{f^{3}}}{4 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.26, size = 191, normalized size = 2.12 \[ \frac {a\,d^3\,x^4}{4}-\frac {3\,\sin \left (e+f\,x\right )\,\left (2\,a\,d^3-a\,c^2\,d\,f^2\right )}{f^4}-\frac {\cos \left (e+f\,x\right )\,\left (a\,c^3\,f^2-6\,a\,c\,d^2\right )}{f^3}+a\,c^3\,x+\frac {3\,x\,\cos \left (e+f\,x\right )\,\left (2\,a\,d^3-a\,c^2\,d\,f^2\right )}{f^3}+\frac {3\,a\,c^2\,d\,x^2}{2}+a\,c\,d^2\,x^3-\frac {a\,d^3\,x^3\,\cos \left (e+f\,x\right )}{f}+\frac {3\,a\,d^3\,x^2\,\sin \left (e+f\,x\right )}{f^2}+\frac {6\,a\,c\,d^2\,x\,\sin \left (e+f\,x\right )}{f^2}-\frac {3\,a\,c\,d^2\,x^2\,\cos \left (e+f\,x\right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.79, size = 264, normalized size = 2.93 \[ \begin {cases} a c^{3} x - \frac {a c^{3} \cos {\left (e + f x \right )}}{f} + \frac {3 a c^{2} d x^{2}}{2} - \frac {3 a c^{2} d x \cos {\left (e + f x \right )}}{f} + \frac {3 a c^{2} d \sin {\left (e + f x \right )}}{f^{2}} + a c d^{2} x^{3} - \frac {3 a c d^{2} x^{2} \cos {\left (e + f x \right )}}{f} + \frac {6 a c d^{2} x \sin {\left (e + f x \right )}}{f^{2}} + \frac {6 a c d^{2} \cos {\left (e + f x \right )}}{f^{3}} + \frac {a d^{3} x^{4}}{4} - \frac {a d^{3} x^{3} \cos {\left (e + f x \right )}}{f} + \frac {3 a d^{3} x^{2} \sin {\left (e + f x \right )}}{f^{2}} + \frac {6 a d^{3} x \cos {\left (e + f x \right )}}{f^{3}} - \frac {6 a d^{3} \sin {\left (e + f x \right )}}{f^{4}} & \text {for}\: f \neq 0 \\\left (a \sin {\relax (e )} + a\right ) \left (c^{3} x + \frac {3 c^{2} d x^{2}}{2} + c d^{2} x^{3} + \frac {d^{3} x^{4}}{4}\right ) & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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