Optimal. Leaf size=307 \[ -\frac {\left (8 a^2+b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} F\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{4 a b d \sqrt {a+b \sin (c+d x)}}+\frac {\left (8 a^2+3 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{4 a^2 b d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {3 \left (4 a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \Pi \left (2;\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{4 a^2 d \sqrt {a+b \sin (c+d x)}}+\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d} \]
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Rubi [A] time = 0.67, antiderivative size = 307, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.310, Rules used = {2893, 3059, 2655, 2653, 3002, 2663, 2661, 2807, 2805} \[ -\frac {\left (8 a^2+b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} F\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{4 a b d \sqrt {a+b \sin (c+d x)}}+\frac {\left (8 a^2+3 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{4 a^2 b d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {3 \left (4 a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \Pi \left (2;\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{4 a^2 d \sqrt {a+b \sin (c+d x)}}+\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d} \]
Antiderivative was successfully verified.
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Rule 2653
Rule 2655
Rule 2661
Rule 2663
Rule 2805
Rule 2807
Rule 2893
Rule 3002
Rule 3059
Rubi steps
\begin {align*} \int \frac {\cos (c+d x) \cot ^3(c+d x)}{\sqrt {a+b \sin (c+d x)}} \, dx &=\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d}-\frac {\int \frac {\csc (c+d x) \left (\frac {3}{4} \left (4 a^2-b^2\right )-\frac {1}{2} a b \sin (c+d x)-\frac {1}{4} \left (8 a^2+3 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx}{2 a^2}\\ &=\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d}+\frac {\int \frac {\csc (c+d x) \left (-\frac {3}{4} b \left (4 a^2-b^2\right )-\frac {1}{4} a \left (8 a^2+b^2\right ) \sin (c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx}{2 a^2 b}-\frac {\left (-8 a^2-3 b^2\right ) \int \sqrt {a+b \sin (c+d x)} \, dx}{8 a^2 b}\\ &=\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d}-\frac {1}{8} \left (\frac {8 a}{b}+\frac {b}{a}\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}} \, dx-\frac {1}{8} \left (3 \left (4-\frac {b^2}{a^2}\right )\right ) \int \frac {\csc (c+d x)}{\sqrt {a+b \sin (c+d x)}} \, dx-\frac {\left (\left (-8 a^2-3 b^2\right ) \sqrt {a+b \sin (c+d x)}\right ) \int \sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}} \, dx}{8 a^2 b \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}\\ &=\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d}+\frac {\left (8 a^2+3 b^2\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{4 a^2 b d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {\left (\left (\frac {8 a}{b}+\frac {b}{a}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}\right ) \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}} \, dx}{8 \sqrt {a+b \sin (c+d x)}}-\frac {\left (3 \left (4-\frac {b^2}{a^2}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}\right ) \int \frac {\csc (c+d x)}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}} \, dx}{8 \sqrt {a+b \sin (c+d x)}}\\ &=\frac {3 b \cot (c+d x) \sqrt {a+b \sin (c+d x)}}{4 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) \sqrt {a+b \sin (c+d x)}}{2 a d}+\frac {\left (8 a^2+3 b^2\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{4 a^2 b d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {\left (\frac {8 a}{b}+\frac {b}{a}\right ) F\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{4 d \sqrt {a+b \sin (c+d x)}}-\frac {3 \left (4-\frac {b^2}{a^2}\right ) \Pi \left (2;\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{4 d \sqrt {a+b \sin (c+d x)}}\\ \end {align*}
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Mathematica [C] time = 3.35, size = 443, normalized size = 1.44 \[ \frac {\frac {2 \left (16 a^2-9 b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \Pi \left (2;\frac {1}{4} (-2 c-2 d x+\pi )|\frac {2 b}{a+b}\right )}{a^2 \sqrt {a+b \sin (c+d x)}}-\frac {4 \cot (c+d x) \sqrt {a+b \sin (c+d x)} (2 a \csc (c+d x)-3 b)}{a^2}+\frac {2 i \left (8 a^2+3 b^2\right ) \cos (2 (c+d x)) \csc ^2(c+d x) \sec (c+d x) \sqrt {-\frac {b (\sin (c+d x)-1)}{a+b}} \sqrt {-\frac {b (\sin (c+d x)+1)}{a-b}} \left (2 a (a-b) E\left (i \sinh ^{-1}\left (\sqrt {-\frac {1}{a+b}} \sqrt {a+b \sin (c+d x)}\right )|\frac {a+b}{a-b}\right )+b \left (2 a F\left (i \sinh ^{-1}\left (\sqrt {-\frac {1}{a+b}} \sqrt {a+b \sin (c+d x)}\right )|\frac {a+b}{a-b}\right )-b \Pi \left (\frac {a+b}{a};i \sinh ^{-1}\left (\sqrt {-\frac {1}{a+b}} \sqrt {a+b \sin (c+d x)}\right )|\frac {a+b}{a-b}\right )\right )\right )}{a^3 b^2 \sqrt {-\frac {1}{a+b}} \left (\csc ^2(c+d x)-2\right )}-\frac {8 b \sqrt {\frac {a+b \sin (c+d x)}{a+b}} F\left (\frac {1}{4} (-2 c-2 d x+\pi )|\frac {2 b}{a+b}\right )}{a \sqrt {a+b \sin (c+d x)}}}{16 d} \]
Antiderivative was successfully verified.
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fricas [F] time = 3.81, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\cos \left (d x + c\right ) \cot \left (d x + c\right )^{3}}{\sqrt {b \sin \left (d x + c\right ) + a}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (d x + c\right ) \cot \left (d x + c\right )^{3}}{\sqrt {b \sin \left (d x + c\right ) + a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 3.31, size = 913, normalized size = 2.97 \[ \frac {\sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}\, \left (\frac {2 \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, \left (\left (-\frac {a}{b}-1\right ) \EllipticE \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )+\EllipticF \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )\right )}{\sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}}+\frac {4 \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, b \EllipticPi \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, -\frac {\left (-\frac {a}{b}+1\right ) b}{a}, \sqrt {\frac {a -b}{a +b}}\right )}{\sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}\, a}-\frac {\sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}}{2 a \sin \left (d x +c \right )^{2}}+\frac {3 b \sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}}{4 a^{2} \sin \left (d x +c \right )}+\frac {b \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, \EllipticF \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )}{2 a \sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}}+\frac {3 b^{2} \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, \left (\left (-\frac {a}{b}-1\right ) \EllipticE \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )+\EllipticF \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )\right )}{4 a^{2} \sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}}-\frac {\left (4 a^{2}+3 b^{2}\right ) \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, b \EllipticPi \left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, -\frac {\left (-\frac {a}{b}+1\right ) b}{a}, \sqrt {\frac {a -b}{a +b}}\right )}{4 a^{3} \sqrt {-\left (-a -b \sin \left (d x +c \right )\right ) \left (\cos ^{2}\left (d x +c \right )\right )}}\right )}{\cos \left (d x +c \right ) \sqrt {a +b \sin \left (d x +c \right )}\, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (d x + c\right ) \cot \left (d x + c\right )^{3}}{\sqrt {b \sin \left (d x + c\right ) + a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\cos \left (c+d\,x\right )\,{\mathrm {cot}\left (c+d\,x\right )}^3}{\sqrt {a+b\,\sin \left (c+d\,x\right )}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos {\left (c + d x \right )} \cot ^{3}{\left (c + d x \right )}}{\sqrt {a + b \sin {\left (c + d x \right )}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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