Optimal. Leaf size=263 \[ -\frac {\left (3 a^2 A+a b (9 A+B)+b^2 (8 A+3 B)\right ) \log (1-\sin (c+d x))}{16 d (a+b)^3}+\frac {\left (3 a^2 A-a b (9 A-B)+b^2 (8 A-3 B)\right ) \log (\sin (c+d x)+1)}{16 d (a-b)^3}-\frac {\sec ^4(c+d x) (-(a A-b B) \sin (c+d x)-a B+A b)}{4 d \left (a^2-b^2\right )}-\frac {b^4 (A b-a B) \log (a+b \sin (c+d x))}{d \left (a^2-b^2\right )^3}+\frac {\sec ^2(c+d x) \left (\left (3 a^3 A+a^2 b B-7 a A b^2+3 b^3 B\right ) \sin (c+d x)+4 b^2 (A b-a B)\right )}{8 d \left (a^2-b^2\right )^2} \]
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Rubi [A] time = 0.45, antiderivative size = 263, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {2837, 823, 801} \[ -\frac {b^4 (A b-a B) \log (a+b \sin (c+d x))}{d \left (a^2-b^2\right )^3}-\frac {\left (3 a^2 A+a b (9 A+B)+b^2 (8 A+3 B)\right ) \log (1-\sin (c+d x))}{16 d (a+b)^3}+\frac {\left (3 a^2 A-a b (9 A-B)+b^2 (8 A-3 B)\right ) \log (\sin (c+d x)+1)}{16 d (a-b)^3}-\frac {\sec ^4(c+d x) (-(a A-b B) \sin (c+d x)-a B+A b)}{4 d \left (a^2-b^2\right )}+\frac {\sec ^2(c+d x) \left (\left (3 a^3 A+a^2 b B-7 a A b^2+3 b^3 B\right ) \sin (c+d x)+4 b^2 (A b-a B)\right )}{8 d \left (a^2-b^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 801
Rule 823
Rule 2837
Rubi steps
\begin {align*} \int \frac {\sec ^5(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx &=\frac {b^5 \operatorname {Subst}\left (\int \frac {A+\frac {B x}{b}}{(a+x) \left (b^2-x^2\right )^3} \, dx,x,b \sin (c+d x)\right )}{d}\\ &=-\frac {\sec ^4(c+d x) (A b-a B-(a A-b B) \sin (c+d x))}{4 \left (a^2-b^2\right ) d}-\frac {b^3 \operatorname {Subst}\left (\int \frac {-3 a^2 A+4 A b^2-a b B-3 (a A-b B) x}{(a+x) \left (b^2-x^2\right )^2} \, dx,x,b \sin (c+d x)\right )}{4 \left (a^2-b^2\right ) d}\\ &=-\frac {\sec ^4(c+d x) (A b-a B-(a A-b B) \sin (c+d x))}{4 \left (a^2-b^2\right ) d}+\frac {\sec ^2(c+d x) \left (4 b^2 (A b-a B)+\left (3 a^3 A-7 a A b^2+a^2 b B+3 b^3 B\right ) \sin (c+d x)\right )}{8 \left (a^2-b^2\right )^2 d}+\frac {b \operatorname {Subst}\left (\int \frac {3 a^4 A-7 a^2 A b^2+8 A b^4+a^3 b B-5 a b^3 B+\left (3 a^3 A-7 a A b^2+a^2 b B+3 b^3 B\right ) x}{(a+x) \left (b^2-x^2\right )} \, dx,x,b \sin (c+d x)\right )}{8 \left (a^2-b^2\right )^2 d}\\ &=-\frac {\sec ^4(c+d x) (A b-a B-(a A-b B) \sin (c+d x))}{4 \left (a^2-b^2\right ) d}+\frac {\sec ^2(c+d x) \left (4 b^2 (A b-a B)+\left (3 a^3 A-7 a A b^2+a^2 b B+3 b^3 B\right ) \sin (c+d x)\right )}{8 \left (a^2-b^2\right )^2 d}+\frac {b \operatorname {Subst}\left (\int \left (\frac {(a-b)^2 \left (3 a^2 A+a b (9 A+B)+b^2 (8 A+3 B)\right )}{2 b (a+b) (b-x)}+\frac {8 b^3 (-A b+a B)}{(a-b) (a+b) (a+x)}+\frac {(a+b)^2 \left (3 a^2 A+b^2 (8 A-3 B)-a b (9 A-B)\right )}{2 (a-b) b (b+x)}\right ) \, dx,x,b \sin (c+d x)\right )}{8 \left (a^2-b^2\right )^2 d}\\ &=-\frac {\left (3 a^2 A+a b (9 A+B)+b^2 (8 A+3 B)\right ) \log (1-\sin (c+d x))}{16 (a+b)^3 d}+\frac {\left (3 a^2 A+b^2 (8 A-3 B)-a b (9 A-B)\right ) \log (1+\sin (c+d x))}{16 (a-b)^3 d}-\frac {b^4 (A b-a B) \log (a+b \sin (c+d x))}{\left (a^2-b^2\right )^3 d}-\frac {\sec ^4(c+d x) (A b-a B-(a A-b B) \sin (c+d x))}{4 \left (a^2-b^2\right ) d}+\frac {\sec ^2(c+d x) \left (4 b^2 (A b-a B)+\left (3 a^3 A-7 a A b^2+a^2 b B+3 b^3 B\right ) \sin (c+d x)\right )}{8 \left (a^2-b^2\right )^2 d}\\ \end {align*}
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Mathematica [A] time = 1.31, size = 321, normalized size = 1.22 \[ \frac {-\frac {2 \left (3 a^2 A+a b (9 A+B)+b^2 (8 A+3 B)\right ) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )}{(a+b)^3}+\frac {2 \left (3 a^2 A+a b (B-9 A)+b^2 (8 A-3 B)\right ) \log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )}{(a-b)^3}+\frac {16 b^4 (A b-a B) \log (a+b \sin (c+d x))}{\left (b^2-a^2\right )^3}+\frac {3 a A+a B+5 A b+3 b B}{(a+b)^2 \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^2}+\frac {-3 a A+a B+5 A b-3 b B}{(a-b)^2 \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^2}+\frac {A+B}{(a+b) \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^4}+\frac {B-A}{(a-b) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^4}}{16 d} \]
Warning: Unable to verify antiderivative.
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fricas [A] time = 1.77, size = 413, normalized size = 1.57 \[ \frac {4 \, B a^{5} - 4 \, A a^{4} b - 8 \, B a^{3} b^{2} + 8 \, A a^{2} b^{3} + 4 \, B a b^{4} - 4 \, A b^{5} + 16 \, {\left (B a b^{4} - A b^{5}\right )} \cos \left (d x + c\right )^{4} \log \left (b \sin \left (d x + c\right ) + a\right ) + {\left (3 \, A a^{5} + B a^{4} b - 10 \, A a^{3} b^{2} - 6 \, B a^{2} b^{3} + {\left (15 \, A - 8 \, B\right )} a b^{4} + {\left (8 \, A - 3 \, B\right )} b^{5}\right )} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - {\left (3 \, A a^{5} + B a^{4} b - 10 \, A a^{3} b^{2} - 6 \, B a^{2} b^{3} + {\left (15 \, A + 8 \, B\right )} a b^{4} - {\left (8 \, A + 3 \, B\right )} b^{5}\right )} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 8 \, {\left (B a^{3} b^{2} - A a^{2} b^{3} - B a b^{4} + A b^{5}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left (2 \, A a^{5} - 2 \, B a^{4} b - 4 \, A a^{3} b^{2} + 4 \, B a^{2} b^{3} + 2 \, A a b^{4} - 2 \, B b^{5} + {\left (3 \, A a^{5} + B a^{4} b - 10 \, A a^{3} b^{2} + 2 \, B a^{2} b^{3} + 7 \, A a b^{4} - 3 \, B b^{5}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{16 \, {\left (a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}\right )} d \cos \left (d x + c\right )^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.40, size = 539, normalized size = 2.05 \[ \frac {\frac {16 \, {\left (B a b^{5} - A b^{6}\right )} \log \left ({\left | b \sin \left (d x + c\right ) + a \right |}\right )}{a^{6} b - 3 \, a^{4} b^{3} + 3 \, a^{2} b^{5} - b^{7}} - \frac {{\left (3 \, A a^{2} + 9 \, A a b + B a b + 8 \, A b^{2} + 3 \, B b^{2}\right )} \log \left ({\left | -\sin \left (d x + c\right ) + 1 \right |}\right )}{a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}} + \frac {{\left (3 \, A a^{2} - 9 \, A a b + B a b + 8 \, A b^{2} - 3 \, B b^{2}\right )} \log \left ({\left | -\sin \left (d x + c\right ) - 1 \right |}\right )}{a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}} + \frac {2 \, {\left (6 \, B a b^{4} \sin \left (d x + c\right )^{4} - 6 \, A b^{5} \sin \left (d x + c\right )^{4} - 3 \, A a^{5} \sin \left (d x + c\right )^{3} - B a^{4} b \sin \left (d x + c\right )^{3} + 10 \, A a^{3} b^{2} \sin \left (d x + c\right )^{3} - 2 \, B a^{2} b^{3} \sin \left (d x + c\right )^{3} - 7 \, A a b^{4} \sin \left (d x + c\right )^{3} + 3 \, B b^{5} \sin \left (d x + c\right )^{3} + 4 \, B a^{3} b^{2} \sin \left (d x + c\right )^{2} - 4 \, A a^{2} b^{3} \sin \left (d x + c\right )^{2} - 16 \, B a b^{4} \sin \left (d x + c\right )^{2} + 16 \, A b^{5} \sin \left (d x + c\right )^{2} + 5 \, A a^{5} \sin \left (d x + c\right ) - B a^{4} b \sin \left (d x + c\right ) - 14 \, A a^{3} b^{2} \sin \left (d x + c\right ) + 6 \, B a^{2} b^{3} \sin \left (d x + c\right ) + 9 \, A a b^{4} \sin \left (d x + c\right ) - 5 \, B b^{5} \sin \left (d x + c\right ) + 2 \, B a^{5} - 2 \, A a^{4} b - 8 \, B a^{3} b^{2} + 8 \, A a^{2} b^{3} + 12 \, B a b^{4} - 12 \, A b^{5}\right )}}{{\left (a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}\right )} {\left (\sin \left (d x + c\right )^{2} - 1\right )}^{2}}}{16 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.51, size = 586, normalized size = 2.23 \[ \frac {A}{2 d \left (8 a +8 b \right ) \left (\sin \left (d x +c \right )-1\right )^{2}}+\frac {B}{2 d \left (8 a +8 b \right ) \left (\sin \left (d x +c \right )-1\right )^{2}}-\frac {3 a A}{16 d \left (a +b \right )^{2} \left (\sin \left (d x +c \right )-1\right )}-\frac {5 A b}{16 d \left (a +b \right )^{2} \left (\sin \left (d x +c \right )-1\right )}-\frac {a B}{16 d \left (a +b \right )^{2} \left (\sin \left (d x +c \right )-1\right )}-\frac {3 B b}{16 d \left (a +b \right )^{2} \left (\sin \left (d x +c \right )-1\right )}-\frac {3 \ln \left (\sin \left (d x +c \right )-1\right ) a^{2} A}{16 d \left (a +b \right )^{3}}-\frac {9 \ln \left (\sin \left (d x +c \right )-1\right ) A a b}{16 d \left (a +b \right )^{3}}-\frac {\ln \left (\sin \left (d x +c \right )-1\right ) A \,b^{2}}{2 d \left (a +b \right )^{3}}-\frac {\ln \left (\sin \left (d x +c \right )-1\right ) B a b}{16 d \left (a +b \right )^{3}}-\frac {3 \ln \left (\sin \left (d x +c \right )-1\right ) B \,b^{2}}{16 d \left (a +b \right )^{3}}-\frac {b^{5} \ln \left (a +b \sin \left (d x +c \right )\right ) A}{d \left (a +b \right )^{3} \left (a -b \right )^{3}}+\frac {b^{4} \ln \left (a +b \sin \left (d x +c \right )\right ) a B}{d \left (a +b \right )^{3} \left (a -b \right )^{3}}-\frac {A}{2 d \left (8 a -8 b \right ) \left (1+\sin \left (d x +c \right )\right )^{2}}+\frac {B}{2 d \left (8 a -8 b \right ) \left (1+\sin \left (d x +c \right )\right )^{2}}-\frac {3 a A}{16 d \left (a -b \right )^{2} \left (1+\sin \left (d x +c \right )\right )}+\frac {5 A b}{16 d \left (a -b \right )^{2} \left (1+\sin \left (d x +c \right )\right )}+\frac {a B}{16 d \left (a -b \right )^{2} \left (1+\sin \left (d x +c \right )\right )}-\frac {3 B b}{16 d \left (a -b \right )^{2} \left (1+\sin \left (d x +c \right )\right )}+\frac {3 \ln \left (1+\sin \left (d x +c \right )\right ) a^{2} A}{16 d \left (a -b \right )^{3}}-\frac {9 \ln \left (1+\sin \left (d x +c \right )\right ) A a b}{16 d \left (a -b \right )^{3}}+\frac {\ln \left (1+\sin \left (d x +c \right )\right ) A \,b^{2}}{2 d \left (a -b \right )^{3}}+\frac {\ln \left (1+\sin \left (d x +c \right )\right ) B a b}{16 d \left (a -b \right )^{3}}-\frac {3 \ln \left (1+\sin \left (d x +c \right )\right ) B \,b^{2}}{16 d \left (a -b \right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.38, size = 367, normalized size = 1.40 \[ \frac {\frac {16 \, {\left (B a b^{4} - A b^{5}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}} + \frac {{\left (3 \, A a^{2} - {\left (9 \, A - B\right )} a b + {\left (8 \, A - 3 \, B\right )} b^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right )}{a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}} - \frac {{\left (3 \, A a^{2} + {\left (9 \, A + B\right )} a b + {\left (8 \, A + 3 \, B\right )} b^{2}\right )} \log \left (\sin \left (d x + c\right ) - 1\right )}{a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}} + \frac {2 \, {\left (2 \, B a^{3} - 2 \, A a^{2} b - 6 \, B a b^{2} + 6 \, A b^{3} - {\left (3 \, A a^{3} + B a^{2} b - 7 \, A a b^{2} + 3 \, B b^{3}\right )} \sin \left (d x + c\right )^{3} + 4 \, {\left (B a b^{2} - A b^{3}\right )} \sin \left (d x + c\right )^{2} + {\left (5 \, A a^{3} - B a^{2} b - 9 \, A a b^{2} + 5 \, B b^{3}\right )} \sin \left (d x + c\right )\right )}}{{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \sin \left (d x + c\right )^{4} + a^{4} - 2 \, a^{2} b^{2} + b^{4} - 2 \, {\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \sin \left (d x + c\right )^{2}}}{16 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 12.95, size = 427, normalized size = 1.62 \[ \frac {\frac {B\,a^3-A\,a^2\,b-3\,B\,a\,b^2+3\,A\,b^3}{4\,\left (a^4-2\,a^2\,b^2+b^4\right )}+\frac {\sin \left (c+d\,x\right )\,\left (5\,A\,a^3-B\,a^2\,b-9\,A\,a\,b^2+5\,B\,b^3\right )}{8\,\left (a^4-2\,a^2\,b^2+b^4\right )}-\frac {{\sin \left (c+d\,x\right )}^2\,\left (A\,b^3-B\,a\,b^2\right )}{2\,\left (a^4-2\,a^2\,b^2+b^4\right )}-\frac {{\sin \left (c+d\,x\right )}^3\,\left (3\,A\,a^3+B\,a^2\,b-7\,A\,a\,b^2+3\,B\,b^3\right )}{8\,\left (a^4-2\,a^2\,b^2+b^4\right )}}{d\,\left ({\cos \left (c+d\,x\right )}^2+{\sin \left (c+d\,x\right )}^4-{\sin \left (c+d\,x\right )}^2\right )}-\frac {\ln \left (\sin \left (c+d\,x\right )-1\right )\,\left (3\,A\,a^2+\left (9\,A+B\right )\,a\,b+\left (8\,A+3\,B\right )\,b^2\right )}{d\,\left (16\,a^3+48\,a^2\,b+48\,a\,b^2+16\,b^3\right )}-\frac {\ln \left (a+b\,\sin \left (c+d\,x\right )\right )\,\left (A\,b^5-B\,a\,b^4\right )}{d\,\left (a^6-3\,a^4\,b^2+3\,a^2\,b^4-b^6\right )}+\frac {\ln \left (\sin \left (c+d\,x\right )+1\right )\,\left (3\,A\,a^2+\left (B-9\,A\right )\,a\,b+\left (8\,A-3\,B\right )\,b^2\right )}{d\,\left (16\,a^3-48\,a^2\,b+48\,a\,b^2-16\,b^3\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (A + B \sin {\left (c + d x \right )}\right ) \sec ^{5}{\left (c + d x \right )}}{a + b \sin {\left (c + d x \right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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