3.329 \(\int \cos ^2(c+d x) \sin ^3(c+d x) (a+a \sin (c+d x))^{3/2} \, dx\)

Optimal. Leaf size=233 \[ -\frac {38 a^2 \sin ^4(c+d x) \cos (c+d x)}{1287 d \sqrt {a \sin (c+d x)+a}}-\frac {862 a^2 \sin ^3(c+d x) \cos (c+d x)}{9009 d \sqrt {a \sin (c+d x)+a}}-\frac {1724 a^2 \cos (c+d x)}{6435 d \sqrt {a \sin (c+d x)+a}}+\frac {2 \sin ^4(c+d x) \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{13 d}+\frac {6 a \sin ^4(c+d x) \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{143 d}-\frac {1724 \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{15015 d}+\frac {3448 a \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{45045 d} \]

[Out]

-1724/15015*cos(d*x+c)*(a+a*sin(d*x+c))^(3/2)/d+2/13*cos(d*x+c)*sin(d*x+c)^4*(a+a*sin(d*x+c))^(3/2)/d-1724/643
5*a^2*cos(d*x+c)/d/(a+a*sin(d*x+c))^(1/2)-862/9009*a^2*cos(d*x+c)*sin(d*x+c)^3/d/(a+a*sin(d*x+c))^(1/2)-38/128
7*a^2*cos(d*x+c)*sin(d*x+c)^4/d/(a+a*sin(d*x+c))^(1/2)+3448/45045*a*cos(d*x+c)*(a+a*sin(d*x+c))^(1/2)/d+6/143*
a*cos(d*x+c)*sin(d*x+c)^4*(a+a*sin(d*x+c))^(1/2)/d

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Rubi [A]  time = 0.72, antiderivative size = 233, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {2879, 2976, 2981, 2770, 2759, 2751, 2646} \[ -\frac {38 a^2 \sin ^4(c+d x) \cos (c+d x)}{1287 d \sqrt {a \sin (c+d x)+a}}-\frac {862 a^2 \sin ^3(c+d x) \cos (c+d x)}{9009 d \sqrt {a \sin (c+d x)+a}}-\frac {1724 a^2 \cos (c+d x)}{6435 d \sqrt {a \sin (c+d x)+a}}+\frac {2 \sin ^4(c+d x) \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{13 d}+\frac {6 a \sin ^4(c+d x) \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{143 d}-\frac {1724 \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{15015 d}+\frac {3448 a \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{45045 d} \]

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^2*Sin[c + d*x]^3*(a + a*Sin[c + d*x])^(3/2),x]

[Out]

(-1724*a^2*Cos[c + d*x])/(6435*d*Sqrt[a + a*Sin[c + d*x]]) - (862*a^2*Cos[c + d*x]*Sin[c + d*x]^3)/(9009*d*Sqr
t[a + a*Sin[c + d*x]]) - (38*a^2*Cos[c + d*x]*Sin[c + d*x]^4)/(1287*d*Sqrt[a + a*Sin[c + d*x]]) + (3448*a*Cos[
c + d*x]*Sqrt[a + a*Sin[c + d*x]])/(45045*d) + (6*a*Cos[c + d*x]*Sin[c + d*x]^4*Sqrt[a + a*Sin[c + d*x]])/(143
*d) - (1724*Cos[c + d*x]*(a + a*Sin[c + d*x])^(3/2))/(15015*d) + (2*Cos[c + d*x]*Sin[c + d*x]^4*(a + a*Sin[c +
d*x])^(3/2))/(13*d)

Rule 2646

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(-2*b*Cos[c + d*x])/(d*Sqrt[a + b*Sin[c + d*
x]]), x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]

Rule 2751

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> -Simp[(d
*Cos[e + f*x]*(a + b*Sin[e + f*x])^m)/(f*(m + 1)), x] + Dist[(a*d*m + b*c*(m + 1))/(b*(m + 1)), Int[(a + b*Sin
[e + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] &&  !LtQ[m,
-2^(-1)]

Rule 2759

Int[sin[(e_.) + (f_.)*(x_)]^2*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> -Simp[(Cos[e + f*x]*(a
+ b*Sin[e + f*x])^(m + 1))/(b*f*(m + 2)), x] + Dist[1/(b*(m + 2)), Int[(a + b*Sin[e + f*x])^m*(b*(m + 1) - a*
Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f, m}, x] && EqQ[a^2 - b^2, 0] &&  !LtQ[m, -2^(-1)]

Rule 2770

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp
[(-2*b*Cos[e + f*x]*(c + d*Sin[e + f*x])^n)/(f*(2*n + 1)*Sqrt[a + b*Sin[e + f*x]]), x] + Dist[(2*n*(b*c + a*d)
)/(b*(2*n + 1)), Int[Sqrt[a + b*Sin[e + f*x]]*(c + d*Sin[e + f*x])^(n - 1), x], x] /; FreeQ[{a, b, c, d, e, f}
, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[n, 0] && IntegerQ[2*n]

Rule 2879

Int[cos[(e_.) + (f_.)*(x_)]^2*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)
, x_Symbol] :> Dist[1/b^2, Int[(d*Sin[e + f*x])^n*(a + b*Sin[e + f*x])^(m + 1)*(a - b*Sin[e + f*x]), x], x] /;
FreeQ[{a, b, d, e, f, m, n}, x] && EqQ[a^2 - b^2, 0] && IntegersQ[2*m, 2*n]

Rule 2976

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_
.) + (f_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b*B*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])
^(n + 1))/(d*f*(m + n + 1)), x] + Dist[1/(d*(m + n + 1)), Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x]
)^n*Simp[a*A*d*(m + n + 1) + B*(a*c*(m - 1) + b*d*(n + 1)) + (A*b*d*(m + n + 1) - B*(b*c*m - a*d*(2*m + n)))*S
in[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] &&
NeQ[c^2 - d^2, 0] && GtQ[m, 1/2] &&  !LtQ[n, -1] && IntegerQ[2*m] && (IntegerQ[2*n] || EqQ[c, 0])

Rule 2981

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.
) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(-2*b*B*Cos[e + f*x]*(c + d*Sin[e + f*x])^(n + 1))/(d*f*(2*n + 3)*Sqr
t[a + b*Sin[e + f*x]]), x] + Dist[(A*b*d*(2*n + 3) - B*(b*c - 2*a*d*(n + 1)))/(b*d*(2*n + 3)), Int[Sqrt[a + b*
Sin[e + f*x]]*(c + d*Sin[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c - a*d, 0] &&
EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !LtQ[n, -1]

Rubi steps

\begin {align*} \int \cos ^2(c+d x) \sin ^3(c+d x) (a+a \sin (c+d x))^{3/2} \, dx &=\frac {\int \sin ^3(c+d x) (a-a \sin (c+d x)) (a+a \sin (c+d x))^{5/2} \, dx}{a^2}\\ &=\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}+\frac {2 \int \sin ^3(c+d x) (a+a \sin (c+d x))^{3/2} \left (\frac {5 a^2}{2}-\frac {3}{2} a^2 \sin (c+d x)\right ) \, dx}{13 a^2}\\ &=\frac {6 a \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{143 d}+\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}+\frac {4 \int \sin ^3(c+d x) \sqrt {a+a \sin (c+d x)} \left (\frac {31 a^3}{4}+\frac {19}{4} a^3 \sin (c+d x)\right ) \, dx}{143 a^2}\\ &=-\frac {38 a^2 \cos (c+d x) \sin ^4(c+d x)}{1287 d \sqrt {a+a \sin (c+d x)}}+\frac {6 a \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{143 d}+\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}+\frac {(431 a) \int \sin ^3(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{1287}\\ &=-\frac {862 a^2 \cos (c+d x) \sin ^3(c+d x)}{9009 d \sqrt {a+a \sin (c+d x)}}-\frac {38 a^2 \cos (c+d x) \sin ^4(c+d x)}{1287 d \sqrt {a+a \sin (c+d x)}}+\frac {6 a \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{143 d}+\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}+\frac {(862 a) \int \sin ^2(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{3003}\\ &=-\frac {862 a^2 \cos (c+d x) \sin ^3(c+d x)}{9009 d \sqrt {a+a \sin (c+d x)}}-\frac {38 a^2 \cos (c+d x) \sin ^4(c+d x)}{1287 d \sqrt {a+a \sin (c+d x)}}+\frac {6 a \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{143 d}-\frac {1724 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{15015 d}+\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}+\frac {1724 \int \left (\frac {3 a}{2}-a \sin (c+d x)\right ) \sqrt {a+a \sin (c+d x)} \, dx}{15015}\\ &=-\frac {862 a^2 \cos (c+d x) \sin ^3(c+d x)}{9009 d \sqrt {a+a \sin (c+d x)}}-\frac {38 a^2 \cos (c+d x) \sin ^4(c+d x)}{1287 d \sqrt {a+a \sin (c+d x)}}+\frac {3448 a \cos (c+d x) \sqrt {a+a \sin (c+d x)}}{45045 d}+\frac {6 a \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{143 d}-\frac {1724 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{15015 d}+\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}+\frac {(862 a) \int \sqrt {a+a \sin (c+d x)} \, dx}{6435}\\ &=-\frac {1724 a^2 \cos (c+d x)}{6435 d \sqrt {a+a \sin (c+d x)}}-\frac {862 a^2 \cos (c+d x) \sin ^3(c+d x)}{9009 d \sqrt {a+a \sin (c+d x)}}-\frac {38 a^2 \cos (c+d x) \sin ^4(c+d x)}{1287 d \sqrt {a+a \sin (c+d x)}}+\frac {3448 a \cos (c+d x) \sqrt {a+a \sin (c+d x)}}{45045 d}+\frac {6 a \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{143 d}-\frac {1724 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{15015 d}+\frac {2 \cos (c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^{3/2}}{13 d}\\ \end {align*}

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Mathematica [A]  time = 3.87, size = 120, normalized size = 0.52 \[ -\frac {a \sqrt {a (\sin (c+d x)+1)} \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^3 (381174 \sin (c+d x)-77665 \sin (3 (c+d x))+3465 \sin (5 (c+d x))-194160 \cos (2 (c+d x))+22680 \cos (4 (c+d x))+281816)}{360360 d \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^2*Sin[c + d*x]^3*(a + a*Sin[c + d*x])^(3/2),x]

[Out]

-1/360360*(a*(Cos[(c + d*x)/2] - Sin[(c + d*x)/2])^3*Sqrt[a*(1 + Sin[c + d*x])]*(281816 - 194160*Cos[2*(c + d*
x)] + 22680*Cos[4*(c + d*x)] + 381174*Sin[c + d*x] - 77665*Sin[3*(c + d*x)] + 3465*Sin[5*(c + d*x)]))/(d*(Cos[
(c + d*x)/2] + Sin[(c + d*x)/2]))

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fricas [A]  time = 0.49, size = 189, normalized size = 0.81 \[ -\frac {2 \, {\left (3465 \, a \cos \left (d x + c\right )^{7} - 4410 \, a \cos \left (d x + c\right )^{6} - 14140 \, a \cos \left (d x + c\right )^{5} + 7330 \, a \cos \left (d x + c\right )^{4} + 15299 \, a \cos \left (d x + c\right )^{3} - 568 \, a \cos \left (d x + c\right )^{2} + 2272 \, a \cos \left (d x + c\right ) - {\left (3465 \, a \cos \left (d x + c\right )^{6} + 7875 \, a \cos \left (d x + c\right )^{5} - 6265 \, a \cos \left (d x + c\right )^{4} - 13595 \, a \cos \left (d x + c\right )^{3} + 1704 \, a \cos \left (d x + c\right )^{2} + 2272 \, a \cos \left (d x + c\right ) + 4544 \, a\right )} \sin \left (d x + c\right ) + 4544 \, a\right )} \sqrt {a \sin \left (d x + c\right ) + a}}{45045 \, {\left (d \cos \left (d x + c\right ) + d \sin \left (d x + c\right ) + d\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^2*sin(d*x+c)^3*(a+a*sin(d*x+c))^(3/2),x, algorithm="fricas")

[Out]

-2/45045*(3465*a*cos(d*x + c)^7 - 4410*a*cos(d*x + c)^6 - 14140*a*cos(d*x + c)^5 + 7330*a*cos(d*x + c)^4 + 152
99*a*cos(d*x + c)^3 - 568*a*cos(d*x + c)^2 + 2272*a*cos(d*x + c) - (3465*a*cos(d*x + c)^6 + 7875*a*cos(d*x + c
)^5 - 6265*a*cos(d*x + c)^4 - 13595*a*cos(d*x + c)^3 + 1704*a*cos(d*x + c)^2 + 2272*a*cos(d*x + c) + 4544*a)*s
in(d*x + c) + 4544*a)*sqrt(a*sin(d*x + c) + a)/(d*cos(d*x + c) + d*sin(d*x + c) + d)

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giac [B]  time = 0.64, size = 412, normalized size = 1.77 \[ \frac {1}{1441440} \, \sqrt {2} {\left (\frac {10010 \, a \cos \left (\frac {1}{4} \, \pi + \frac {9}{2} \, d x + \frac {9}{2} \, c\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} - \frac {18018 \, a \cos \left (\frac {1}{4} \, \pi + \frac {5}{2} \, d x + \frac {5}{2} \, c\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} - \frac {180180 \, a \cos \left (\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} + \frac {8190 \, a \cos \left (-\frac {1}{4} \, \pi + \frac {11}{2} \, d x + \frac {11}{2} \, c\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} - \frac {12870 \, a \cos \left (-\frac {1}{4} \, \pi + \frac {7}{2} \, d x + \frac {7}{2} \, c\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} - \frac {60060 \, a \cos \left (-\frac {1}{4} \, \pi + \frac {3}{2} \, d x + \frac {3}{2} \, c\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} + \frac {4095 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {1}{4} \, \pi + \frac {11}{2} \, d x + \frac {11}{2} \, c\right )}{d} - \frac {12870 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {1}{4} \, \pi + \frac {7}{2} \, d x + \frac {7}{2} \, c\right )}{d} - \frac {15015 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {1}{4} \, \pi + \frac {3}{2} \, d x + \frac {3}{2} \, c\right )}{d} + \frac {3465 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (-\frac {1}{4} \, \pi + \frac {13}{2} \, d x + \frac {13}{2} \, c\right )}{d} - \frac {10010 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (-\frac {1}{4} \, \pi + \frac {9}{2} \, d x + \frac {9}{2} \, c\right )}{d} - \frac {9009 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (-\frac {1}{4} \, \pi + \frac {5}{2} \, d x + \frac {5}{2} \, c\right )}{d} + \frac {180180 \, a \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{d}\right )} \sqrt {a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^2*sin(d*x+c)^3*(a+a*sin(d*x+c))^(3/2),x, algorithm="giac")

[Out]

1/1441440*sqrt(2)*(10010*a*cos(1/4*pi + 9/2*d*x + 9/2*c)*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))/d - 18018*a*cos(1
/4*pi + 5/2*d*x + 5/2*c)*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))/d - 180180*a*cos(1/4*pi + 1/2*d*x + 1/2*c)*sgn(co
s(-1/4*pi + 1/2*d*x + 1/2*c))/d + 8190*a*cos(-1/4*pi + 11/2*d*x + 11/2*c)*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))/
d - 12870*a*cos(-1/4*pi + 7/2*d*x + 7/2*c)*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))/d - 60060*a*cos(-1/4*pi + 3/2*d
*x + 3/2*c)*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))/d + 4095*a*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))*sin(1/4*pi + 11
/2*d*x + 11/2*c)/d - 12870*a*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))*sin(1/4*pi + 7/2*d*x + 7/2*c)/d - 15015*a*sgn
(cos(-1/4*pi + 1/2*d*x + 1/2*c))*sin(1/4*pi + 3/2*d*x + 3/2*c)/d + 3465*a*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))*
sin(-1/4*pi + 13/2*d*x + 13/2*c)/d - 10010*a*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))*sin(-1/4*pi + 9/2*d*x + 9/2*c
)/d - 9009*a*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))*sin(-1/4*pi + 5/2*d*x + 5/2*c)/d + 180180*a*sgn(cos(-1/4*pi +
1/2*d*x + 1/2*c))*sin(-1/4*pi + 1/2*d*x + 1/2*c)/d)*sqrt(a)

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maple [A]  time = 0.94, size = 97, normalized size = 0.42 \[ -\frac {2 \left (1+\sin \left (d x +c \right )\right ) a^{2} \left (\sin \left (d x +c \right )-1\right )^{2} \left (3465 \left (\sin ^{5}\left (d x +c \right )\right )+11340 \left (\sin ^{4}\left (d x +c \right )\right )+15085 \left (\sin ^{3}\left (d x +c \right )\right )+12930 \left (\sin ^{2}\left (d x +c \right )\right )+10344 \sin \left (d x +c \right )+6896\right )}{45045 \cos \left (d x +c \right ) \sqrt {a +a \sin \left (d x +c \right )}\, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^2*sin(d*x+c)^3*(a+a*sin(d*x+c))^(3/2),x)

[Out]

-2/45045*(1+sin(d*x+c))*a^2*(sin(d*x+c)-1)^2*(3465*sin(d*x+c)^5+11340*sin(d*x+c)^4+15085*sin(d*x+c)^3+12930*si
n(d*x+c)^2+10344*sin(d*x+c)+6896)/cos(d*x+c)/(a+a*sin(d*x+c))^(1/2)/d

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \cos \left (d x + c\right )^{2} \sin \left (d x + c\right )^{3}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^2*sin(d*x+c)^3*(a+a*sin(d*x+c))^(3/2),x, algorithm="maxima")

[Out]

integrate((a*sin(d*x + c) + a)^(3/2)*cos(d*x + c)^2*sin(d*x + c)^3, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int {\cos \left (c+d\,x\right )}^2\,{\sin \left (c+d\,x\right )}^3\,{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{3/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(c + d*x)^2*sin(c + d*x)^3*(a + a*sin(c + d*x))^(3/2),x)

[Out]

int(cos(c + d*x)^2*sin(c + d*x)^3*(a + a*sin(c + d*x))^(3/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**2*sin(d*x+c)**3*(a+a*sin(d*x+c))**(3/2),x)

[Out]

Timed out

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